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Solve the following equations. $$\cos 3 x=\sin 3 x, 0 \leq x<2 \pi$$

Short Answer

Expert verified
Answer: The specific solutions are \(x = \frac{\pi}{12}, \frac{3\pi}{12}, \frac{5\pi}{12}, ..., \frac{23\pi}{12}\).

Step by step solution

01

Use the identity \(\sin(y) = \cos(\frac{\pi}{2} - y)\)

Replace the sine function with its equivalent cosine function: $$\cos(3x) = \cos\left(\frac{\pi}{2} - 3x\right)$$
02

Apply the angle subtraction formula

When two cosine functions are equal, their angles either have to be equal directly or the sum of their angles equal to \(2n\pi\): $$3x = \frac{\pi}{2} - 3x \quad \text{or} \quad 3x + \frac{\pi}{2} - 3x = 2n\pi$$ For some integer \(n\).
03

Solve for x

Solve the equation for x and obtain the general solution: For the first case: $$3x = \frac{\pi}{2} - 3x$$ $$6x = \frac{\pi}{2}$$ $$x = \frac{\pi}{12}$$ For the second case: $$\frac{\pi}{2} = 2n\pi$$ $$n = \frac{1}{4}$$ However, n must be an integer, so the second case has no solution.
04

Find the specific solutions in the interval \([0, 2\pi)\)

Since the general solution is \(x = \frac{\pi}{12}\), the specific solutions will be multiples of this value within the interval: $$x = \frac{k\pi}{12},$$ where \(k = 0, 1, 2, ..., 24\). Observe that only the odd multiples of \(\frac{\pi}{12}\) will work, as only odd multiples will result in an angle subtraction of \(\frac{\pi}{2}\) which is necessary for the given equation. Therefore, the specific solutions are: $$x = \frac{\pi}{12}, \frac{3\pi}{12}, \frac{5\pi}{12}, ..., \frac{23\pi}{12}$$

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