Chapter 8: Problem 38
The arc length function for a curve \(y=f(x),\) where \(f\) is an increasing function, is \(s(x)=\int_{0}^{x} \sqrt{3 t+5} d t\) (a) If \(f\) has \(y\) -intercept 2 , find an equation for \(f\) (b) What point on the graph of \(f\) is 3 units along the curve from the \(y\) -intercept? State your answer rounded to 3 decimal places.
Short Answer
Step by step solution
Find the Derivative of s(x)
Integrate s'(x) to Find f(x)
Use the y-intercept to Find C
Write the Equation for f(x)
Find the Point 3 Units Along the Curve
Find f(x) at x ≈ 2.171
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fundamental Theorem of Calculus
Integral Calculus
- We calculate \( f(x) = \int \sqrt{3x+5} \, dx \) to 'reverse' the derivative back into the original function.
- This integration gives us a function that describes how the curve's length accumulates over a given range.
Substitution Method
In our task, we face the integral \( \int \sqrt{3x + 5} \, dx \). A substitution is made by letting \( u = 3x + 5 \). This gives
- \( du = 3 \, dx \) or \( dx = \frac{du}{3} \).
- Now, our integral becomes \( \frac{1}{3} \int \sqrt{u} \, du \).
Increasing Function
An increasing function means that as \( x \) gets larger, \( f(x) \) also gets larger. This impacts how we interpret and solve the problem.
- First, it confirms that the arc length \( s(x) \) will continually grow as \( x \) increases, ensuring no 'unexpected turns' or decreases in the function.
- It aids in setting logical bounds for solutions. When solving for \( x \) given \( s(x) = 3 \), we can confidently navigate only positive solutions for \( x \).