Chapter 7: Problem 28
Find the approximations \(T_{n}, M_{n},\) and \(S_{n}\) for \(n=6\) and \(12 .\) Then compute the corresponding errors \(E_{r}, E_{M},\) and \(E_{S} .\) (Round your answers to six decimal places. You may wish to use the sum command on a computer algebra system.) What observations can you make? In particular, what happens to the errors when \(n\) is doubled? $$ \int_{1}^{4} \frac{1}{\sqrt{x}} d x $$
Short Answer
Step by step solution
Define the integral and method
Calculate the exact integral
Trapezoidal Approximation for n=6
Midpoint Approximation for n=6
Simpson's Approximation for n=6
Repeat for n=12
Calculate Errors for n=6
Calculate Errors for n=12
Observations on Error Halving
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trapezoidal Rule
The approximation is calculated using the formula:
- \( T_n = \frac{\Delta x}{2} \left( f(x_0) + 2 \sum_{i=1}^{n-1} f(x_i) + f(x_n) \right) \)
In this exercise, doubling \(n\) reduces the error, making the approximation with \(T_{12}\) more accurate than \(T_6\).
Midpoint Rule
The process involves dividing the given interval \([a, b]\) into \(n\) equal parts, similar to other methods, and is characterized by the formula:
- \( M_n = \Delta x \sum_{i=1}^{n} f(x_i^*) \)
With increased \(n\), the Midpoint Rule's precision improves significantly, as smaller intervals mean the midpoints give a better representation of the curve. In the exercise, moving from \(M_6\) to \(M_{12}\) shows a noticeable decrease in the error.
Simpson's Rule
The general formula is:
- \( S_n = \frac{\Delta x}{3} \left( f(x_0) + 4 \sum_{\text{odd}} f(x_i) + 2 \sum_{\text{even}} f(x_i) + f(x_n) \right) \)
Simpson's Rule minimizes the error in approximation greatly as \(n\) increases. When the number of subintervals doubles, for example from \(n=6\) to \(n=12\), the error generally reduces substantially, confirming its strength in achieving higher accuracy with fewer calculations than other rules like Trapezoidal or Midpoint.