Chapter 7: Problem 27
Find the approximations \(T_{n}, M_{n},\) and \(S_{n}\) for \(n=6\) and \(12 .\) Then compute the corresponding errors \(E_{r}, E_{M},\) and \(E_{S} .\) (Round your answers to six decimal places. You may wish to use the sum command on a computer algebra system.) What observations can you make? In particular, what happens to the errors when \(n\) is doubled? $$ \int_{0}^{2} x^{4} d x $$
Short Answer
Step by step solution
Calculate the Exact Integral
Trapezoidal Rule Approximation
Midpoint Rule Approximation
Simpson's Rule Approximation
Calculate Errors
Compare Errors by Doubling n
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trapezoidal Rule
The formula for this approximation is:\[T_n = \frac{b-a}{2n} \left( f(x_0) + 2 \sum_{i=1}^{n-1} f(x_i) + f(x_n) \right)\]where \( n \) is the number of intervals, \( b \) and \( a \) are the upper and lower limits, respectively, and \( x_i \) are the dividing points.
Key points to remember:
- Increases in \( n \) (number of intervals) make the approximation closer to the true value.
- The error is generally proportional to \( \frac{1}{n^2} \). So, doubling \( n \) often decreases the error significantly, but not as much as Simpson's rule.
Midpoint Rule
Here's the formula:\[M_n = \frac{b-a}{n} \sum_{i=0}^{n-1} f\left( \frac{x_i + x_{i+1}}{2} \right)\]Each term in the formula is the function value at the midpoint \( \frac{x_i + x_{i+1}}{2} \) multiplied by the width of the interval.
Observations to note:
- This approach can be a bit more accurate than the Trapezoidal Rule for certain functions, like polynomial functions.
- The error often decreases in proportion to \( \frac{1}{n^2} \), similar to the Trapezoidal Rule.
Simpson's Rule
The formula for Simpson's Rule is:\[S_n = \frac{b-a}{3n} \left( f(x_0) + 4 \sum_{i=1, \text{odd}}^{n-1} f(x_i) + 2 \sum_{i=2, \text{even}}^{n-2} f(x_i) + f(x_n) \right)\]What makes Simpson's Rule stand out is its error rate, which diminishes proportionally to \( \frac{1}{n^4} \). This makes it substantially more precise, especially when \( n \) is increased.
Keep in mind:
- Simpson's Rule typically provides a superior approximation, primarily due to its higher degree of precision for polynomial integrands.
- The method is efficient for even values of \( n \).