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Find the limit or show that it does not exist. $$ \lim _{x \rightarrow-\infty} \frac{\sqrt{1+4 x^{6}}}{2-x^{3}} $$

Short Answer

Expert verified
The limit is -2.

Step by step solution

01

Identify the Indeterminate Form

First, analyze the behavior of the expression as \( x \to -\infty \). The numerator is \( \sqrt{1+4x^6} \) and the denominator is \( 2-x^3 \). As \( x \to -\infty \), both the numerator and denominator grow significantly. The result is an indeterminate form of type \( \frac{\infty}{\infty} \).
02

Divide by Dominant Term

To simplify the expression, divide both the numerator and the denominator by \( x^3 \), the highest power of \( x \) in the denominator. This gives:\[ \lim_{x \to -\infty} \frac{\sqrt{\frac{1}{x^6} + 4}}{\frac{2}{x^3} - 1} \]
03

Simplify the Expression

As \( x \to -\infty \), terms that decrease as \( x \) becomes large can be neglected:- \( \frac{1}{x^6} \to 0 \)- \( \frac{2}{x^3} \to 0 \)This simplifies the limit to:\[ \lim_{x \to -\infty} \frac{\sqrt{4}}{-1} \]
04

Calculate the Limit

Calculate \( \frac{\sqrt{4}}{-1} \). Since \( \sqrt{4} = 2 \), the expression simplifies to \( \frac{2}{-1} = -2 \).
05

Conclusion

The limit of the original expression as \( x \to -\infty \) is \( -2 \). Thus, the limit exists and is finite.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indeterminate Forms
In calculus, indeterminate forms are expressions that do not present an immediate, clear value. When we evaluate the limit of a quotient where both the numerator and the denominator approach infinity, as seen in the exercise expression \( \lim _{x \rightarrow-\infty} \frac{\sqrt{1+4 x^{6}}}{2-x^{3}} \), it might initially seem that the outcome is uncertain or undefined. In such cases, the form is termed \( \frac{\infty}{\infty} \), known as an indeterminate form. Indeterminate forms require us to apply specific techniques so we can uncover a meaningful limit. This can include factoring, multiplying by the conjugate, or the dominant term method. Recognizing these forms is crucial since the direct evaluation would not result in a useful or meaningful value. This step ensures we understand that more analysis is needed to determine the actual behavior of the function as \( x \to -\infty \).
Dominant Term Method
The dominant term method is a powerful tool to simplify limits involving polynomials or expressions with radicals, especially when dealing with indeterminate forms. In the given example, the numerator and denominator both reach high values, resulting in an indeterminate form. To apply the dominant term method, we divide every term by the highest power of \( x \) found in the expression. This isolates the dominant term, which greatly influences the behavior of the function as \( x \to -\infty \). For the exercise, we divide by \( x^3 \), which is the dominant term in the denominator, reconfiguring the limit to:
  • The numerator becomes \( \sqrt{\frac{1}{x^6} + 4} \), interspersing further simplification as non-dominant terms vanish when approached by large \( x \).
  • The denominator reduces to \( \frac{2}{x^3} - 1 \), leaving a clear path to simplify.
By focusing on the terms that influence the function as \( x \to -\infty \), students can simplify the expression clearly and arrive at the desired limit, which is \( -2 \), as demonstrated in the original solution.
Infinity in Calculus
The concept of infinity in calculus is pivotal in understanding how functions behave as variables grow very large positively or negatively. In our exercise, we evaluated the limit as \( x \to -\infty \). This symbolizes not just a negative, large value but also the exploration of how the function approaches a finite limit under these conditions. When analyzing limits at infinity, it's crucial to:
  • Determine if a function approaches a specific finite number.
  • Understand how large values in the numerator and denominator can lead to indeterminate forms.
Evaluating behaviors at infinity helps us grasp trends and asymptotic behaviors of functions. In our problem, the proper application of simplification methods transformed an initially complex expression into one that clearly approaches \( -2 \) as \( x \) becomes infinitely negative. Infinity, both in positive and negative directions, allows calculus to explore and define behaviors and characteristics of functions far beyond finite numbers, aiding in a deeper understanding of continued growth and decay within mathematical contexts.

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Most popular questions from this chapter

For the limit $$\lim _{x \rightarrow-\infty} \frac{1-3 x}{\sqrt{x^{2}+1}}=3$$ illustrate Definition 8 by finding values of \(N\) that correspond to \(\varepsilon=0.1\) and \(\varepsilon=0.05\)

The unemployment rate \(U(t)\) varies with time. The table gives the percentage of unemployed in the US labor force from 2003 to 2012 . (a) What is the meaning of \(U^{\prime}(t) ?\) What are its units? (b) Construct a table of estimated values for \(U^{\prime}(t)\). \(\begin{array}{|c|c|c|c|}\hline t & {U(t)} & {t} & {U(t)} \\ \hline 2003 & {6.0} & {2008} & {5.8} \\ {2004} & {5.5} & {2009} & {9.3} \\ {2005} & {5.1} & {2010} & {9.6} \\ {2006} & {4.6} & {2011} & {8.9} \\ {2007} & {4.6} & {2012} & {8.1} \\ \hline\end{array}\)

Let \(f(x)=x^{2}\) (a) Estimate the values of \(f^{\prime}(0), f^{\prime}\left(\frac{1}{2}\right), f^{\prime}(1),\) and \(f^{\prime}(2)\) by using a graphing device to zoom in on the graph of \(f .\) (b) Use symmetry to deduce the values of \(f^{\prime}\left(-\frac{1}{2}\right)\) (c) Use the results from parts (a) and (b) to guess a formula for \(f^{\prime}(x)\). (d) Use the definition of derivative to prove that your guess in part (c) is correct.

Use the definition of continuity and the properties of limits to show that the function is continuous at the given number \(a\). $$ f(x)=\left(x+2 x^{3}\right)^{4}, \quad a=-1 $$

Find the limits as \(x \rightarrow \infty\) and as \(x \rightarrow-\infty\). Use this information, together with intercepts, to give a rough sketch of the graph as in Example 12 . $$ y=(3-x)(1+x)^{2}(1-x)^{4} $$

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