Chapter 17: Problem 16
Write a trial solution for the method of undetermined coefficients. Do not determine the coefficients. $$ y^{\prime \prime}+3 y^{\prime}-4 y=\left(x^{3}+x\right) e^{x} $$
Short Answer
Expert verified
Trial solution: \((Ax^4 + Bx^3 + Cx^2 + Dx)e^x\).
Step by step solution
01
Identify the Type of Non-Homogeneous Term
The non-homogeneous term on the right-hand side of the differential equation is \((x^3 + x)e^x\). This is a product of a polynomial \((x^3 + x)\) and an exponential function \(e^x\).
02
Determine the Form of the Trial Solution
Since the non-homogeneous term \((x^3 + x)e^x\) is a combination of a polynomial and an exponential function, the trial solution will need to account for both. The general form of the trial solution will take the form \((Ax^3 + Bx^2 + Cx + D)e^x\), where \(A\), \(B\), \(C\), and \(D\) are coefficients to be determined.
03
Check for Overlap with Homogeneous Solution
Check the characteristic equation of the homogeneous part \(y'' + 3y' - 4y = 0\) to ensure the trial solution does not overlap. The characteristic equation is \(r^2 + 3r - 4 = 0\), which gives roots \(r = 1\) and \(r = -4\). The root \(r = 1\) indicates the solution of the homogeneous equation includes terms with \(e^x\). Thus, the trial solution must be multiplied by \(x\) to ensure it's not a part of the homogeneous solution, resulting in \((Ax^4 + Bx^3 + Cx^2 + Dx)e^x\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Second Order Linear Differential Equations
Second order linear differential equations are a crucial part of calculus and mathematical modeling. These equations include the second derivative of a function, typically represented as \( y'' \). The standard form of a second order linear differential equation is:
This form of equations helps model systems with forces or accelerations, like spring-mass systems or circuits. Recognizing the order and terms in these equations sets the stage for applying methods like undetermined coefficients.
- \( a y'' + b y' + c y = g(x) \)
This form of equations helps model systems with forces or accelerations, like spring-mass systems or circuits. Recognizing the order and terms in these equations sets the stage for applying methods like undetermined coefficients.
Non-Homogeneous Differential Equations
A non-homogeneous differential equation includes a non-zero function on the right side, often denoted as \( g(x) \). This term makes the equation unique and more complex than its homogeneous counterpart. In our example, the non-homogeneous term is given by:
- \( (x^3 + x)e^x \)
Characteristic Equation
The characteristic equation is a key step in solving linear differential equations. For the homogeneous part, it is derived by assuming a solution of the form \( y = e^{rx} \) and substituting into the differential equation. This results in an algebraic equation. For example, the characteristic equation for:
- \( y'' + 3y' - 4y = 0 \)
- \( r^2 + 3r - 4 = 0 \)
Trial Solution
The trial solution is a formative step in the method of undetermined coefficients. It approximates the solution based on the form of the non-homogeneous term. In our example, the initial trial solution might look like:
- \( (Ax^3 + Bx^2 + Cx + D)e^x \)
- \( (Ax^4 + Bx^3 + Cx^2 + Dx)e^x \)
Homogeneous Solution
The homogeneous solution refers to the solution of the differential equation when the non-homogeneous term \( g(x) \) is zero. Using our equation's characteristic roots \( r = 1 \) and \( r = -4 \), the general form of the homogeneous solution is:
- \( y_h = C_1 e^x + C_2 e^{-4x} \)