Chapter 14: Problem 53
Assume that all the given functions have continuous second-order partial derivatives. If \(z=f(x, y),\) where \(x=r \cos \theta\) and \(y=r \sin \theta,\) show that \(\frac{\partial^{2} z}{\partial x^{2}}+\frac{\partial^{2} z}{\partial y^{2}}=\frac{\partial^{2} z}{\partial r^{2}}+\frac{1}{r^{2}} \frac{\partial^{2} z}{\partial \theta^{2}}+\frac{1}{r} \frac{\partial z}{\partial r}\)
Short Answer
Step by step solution
Understand the Geometry
Find First Partial Derivatives
Express \(\frac{\partial z}{\partial x}\) and \(\frac{\partial z}{\partial y}\) in terms of \(r\) and \(\theta\)
Find \(\frac{\partial^2 z}{\partial x^2}\) and \(\frac{\partial^2 z}{\partial y^2}\)
Summing Second Derivatives in Cartesian Coordinates
Confirm the Identity in Polar Coordinates is Satisfied
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
- The reference point is called the pole, equivalent to the origin in Cartesian coordinates.
- The angle in the polar coordinate system is typically measured from the positive x-axis.
- \(x = r \cos \theta\)
- \(y = r \sin \theta\)
Cartesian Coordinates
- Cartesian coordinates are intuitive for many geometric and algebraic problems, offering straightforward computation for distances and relations.
- Conversions: When converting from Cartesian coordinates to polar coordinates, we use the relations \(r = \sqrt{x^2 + y^2}\) and \(\theta = \tan^{-1}(y/x)\).
Chain Rule
- \(\frac{\partial z}{\partial x} = \frac{\partial z}{\partial r} \frac{\partial r}{\partial x} + \frac{\partial z}{\partial \theta} \frac{\partial \theta}{\partial x}\)
- \(\frac{\partial z}{\partial y} = \frac{\partial z}{\partial r} \frac{\partial r}{\partial y} + \frac{\partial z}{\partial \theta} \frac{\partial \theta}{\partial y}\)
Second-order Derivatives
- \(\frac{\partial^2 z}{\partial r^2}\)
- \(\frac{\partial^2 z}{\partial \theta^2}\)
- \(\frac{1}{r}\frac{\partial z}{\partial r}\)