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Suppose that \(\mathbf{a} \neq \mathbf{0}\). (a) If \(\mathbf{a} \cdot \mathbf{b}=\mathbf{a} \cdot \mathbf{c},\) does it follow that \(\mathbf{b}=\mathbf{c} ?\) (b) If \(\mathbf{a} \times \mathbf{b}=\mathbf{a} \times \mathbf{c},\) does it follow that \(\mathbf{b}=\mathbf{c} ?\) (c) If \(\mathbf{a} \cdot \mathbf{b}=\mathbf{a} \cdot \mathbf{c}\) and \(\mathbf{a} \times \mathbf{b}=\mathbf{a} \times \mathbf{c},\) does it follow that \(\mathbf{b}=\mathbf{c} ?\)

Short Answer

Expert verified
(a) No, (b) No, (c) Yes.

Step by step solution

01

Analyzing Dot Product Equality

Consider the equation \( \mathbf{a} \cdot \mathbf{b} = \mathbf{a} \cdot \mathbf{c} \). The dot product formula gives us \( a_1b_1 + a_2b_2 + a_3b_3 = a_1c_1 + a_2c_2 + a_3c_3 \). This implies that the sums of the products of corresponding components of \( \mathbf{b} \) and \( \mathbf{c} \) with \( \mathbf{a} \) are equal. However, this does not necessarily mean \( \mathbf{b} = \mathbf{c} \), as varying the components of either \( \mathbf{b} \) or \( \mathbf{c} \) while maintaining the equality can yield different vectors.
02

Analyzing Cross Product Equality

Consider the equation \( \mathbf{a} \times \mathbf{b} = \mathbf{a} \times \mathbf{c} \). The cross product vector \( \mathbf{a} \times \mathbf{b} \) is perpendicular to both \( \mathbf{a} \) and \( \mathbf{b} \), and similarly for \( \mathbf{a} \times \mathbf{c} \). If \( \mathbf{a} eq \mathbf{0} \) and \( \mathbf{a} \times \mathbf{b} = \mathbf{a} \times \mathbf{c} \), it implies \( \mathbf{b} - \mathbf{c} \) is parallel to \( \mathbf{a} \). Still, \( \mathbf{b} eq \mathbf{c} \) necessarily follows, since parallelism doesn't ensure equality outside a scalar.
03

Considering Both Dot and Cross Product Equalities

When both \( \mathbf{a} \cdot \mathbf{b} = \mathbf{a} \cdot \mathbf{c} \) and \( \mathbf{a} \times \mathbf{b} = \mathbf{a} \times \mathbf{c} \), it covers more constraints. The conditions imply the projections and perpendicular components are equal; \( \mathbf{a} \cdot (\mathbf{b} - \mathbf{c}) = 0 \) indicates \( \mathbf{b} - \mathbf{c} \) is orthogonal to \( \mathbf{a} \), and the cross product \( \mathbf{a} \times (\mathbf{b} - \mathbf{c}) = \mathbf{0} \) implies \( \mathbf{b} - \mathbf{c} \) is parallel to \( \mathbf{a} \). The combined orthogonality and parallelism conditions demand \( \mathbf{b} - \mathbf{c} = \mathbf{0} \), so \( \mathbf{b} = \mathbf{c} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product, also known as the scalar product, is a fundamental operation in vector algebra. It calculates the sum of the products of corresponding components of two vectors. If we have two vectors \( \mathbf{a} \) and \( \mathbf{b} \), the dot product \( \mathbf{a} \cdot \mathbf{b} \) is expressed as: \[ a_1b_1 + a_2b_2 + a_3b_3 \] This expression involves multiplying each component of \( \mathbf{a} \) with its counterpart in \( \mathbf{b} \), then summing up all these products. Some key properties of the dot product include:
  • It is commutative: \( \mathbf{a} \cdot \mathbf{b} = \mathbf{b} \cdot \mathbf{a} \).
  • It is distributive over vector addition: \( \mathbf{a} \cdot (\mathbf{b} + \mathbf{c}) = \mathbf{a} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c} \).
  • The dot product of a vector with itself gives the square of its magnitude: \( \mathbf{a} \cdot \mathbf{a} = ||\mathbf{a}||^2 \).
When the dot products \( \mathbf{a} \cdot \mathbf{b} \) and \( \mathbf{a} \cdot \mathbf{c} \) are equal, this equality suggests a certain alignment of \( \mathbf{b} \) and \( \mathbf{c} \) with respect to \( \mathbf{a} \), but does not necessarily imply that \( \mathbf{b} = \mathbf{c} \). This is because multiple vector pairs can project the same value along a given vector.
Cross Product
The cross product, or vector product, is another important operation in vector algebra, primarily applicable to three-dimensional vectors. It takes two vectors and returns a vector perpendicular to both, capturing the idea of rotational magnitude, often related to torque in physics. Given vectors \( \mathbf{a} \) and \( \mathbf{b} \), the cross product \( \mathbf{a} \times \mathbf{b} \) results in a vector whose components are determined by the determinant: \[ \mathbf{a} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix} \] Here, \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \) are unit vectors along the x, y, and z axes respectively. Crucially, if \( \mathbf{a} \times \mathbf{b} = \mathbf{a} \times \mathbf{c} \), it implies that \( \mathbf{b} - \mathbf{c} \) is parallel to \( \mathbf{a} \), but it doesn't mean \( \mathbf{b} = \mathbf{c} \). This is because the magnitude and direction can vary, allowing different vectors to produce the same perpendicular force.
Vector Equality
Vector equality is a straightforward concept, achieved when two vectors share identical magnitudes and directions. In equation form, two vectors \( \mathbf{b} \) and \( \mathbf{c} \) are equal if: \[ \mathbf{b} = \mathbf{c} \quad \text{if and only if} \quad b_1 = c_1, \; b_2 = c_2, \; b_3 = c_3 \] This means each of their corresponding components must match exactly. In problems where both the dot product and cross product are equal, as in \( \mathbf{a} \cdot \mathbf{b} = \mathbf{a} \cdot \mathbf{c} \) and \( \mathbf{a} \times \mathbf{b} = \mathbf{a} \times \mathbf{c} \), we can infer \( \mathbf{b} = \mathbf{c} \). This dual condition means the difference vector \( \mathbf{b} - \mathbf{c} \) is simultaneously zero in terms of projection and has no perpendicular component relative to \( \mathbf{a} \), enforcing complete equality between \( \mathbf{b} \) and \( \mathbf{c} \). These checks collectively assure us that both the direction and magnitude are identical, consolidating the equality hypothesis.

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