Chapter 12: Problem 27
What is the angle between the given vector and the positive direction of the x-axis? $$ \mathbf{i}+\sqrt{3} \mathbf{j} $$
Short Answer
Expert verified
The angle is \( \frac{\pi}{3} \) or 60°.
Step by step solution
01
Identify the Vector Components
The given vector can be represented in component form as \( \mathbf{v} = \mathbf{i} + \sqrt{3} \mathbf{j} \), where the \( x \)-component is 1 and the \( y \)-component is \( \sqrt{3} \).
02
Recall the Formula for Angle of a Vector
The angle \( \theta \) that a vector \( (x, y) \) makes with the positive \( x \)-axis is given by \( \theta = \tan^{-1}\left(\frac{y}{x}\right) \).
03
Substitute the Components into the Formula
Substitute \( x = 1 \) and \( y = \sqrt{3} \) into the formula: \( \theta = \tan^{-1}\left(\frac{\sqrt{3}}{1}\right) \).
04
Calculate the Inverse Tangent
Calculate \( \theta = \tan^{-1}\left(\sqrt{3}\right) \). Since \( \tan(\pi/3) = \sqrt{3} \), we find that \( \theta = \frac{\pi}{3} \).
05
Convert to Degrees (if Required)
If the angle is needed in degrees, convert \( \frac{\pi}{3} \) to degrees. Since \( \pi \text{ radians} = 180° \), \( \theta = \frac{180}{3} = 60° \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Components
Understanding vector components is crucial when dealing with angles and directions. A vector, often represented in bold or with an arrow on top, has both magnitude and direction. In the given problem, the vector \( \mathbf{i} + \sqrt{3} \mathbf{j} \) can be broken down into two components: the horizontal component \( \mathbf{i} \) (along the x-axis) and the vertical component \( \sqrt{3} \mathbf{j} \) (along the y-axis).
- The x-component is the multiplier of \( \mathbf{i} \), which is 1 in this case.
- The y-component is the multiplier of \( \mathbf{j} \), which is \( \sqrt{3} \).
Angle Formula for Vectors
To find the angle a vector makes with the positive x-axis, we use a specific angle formula. This formula derives from the tangent function, which relates the opposite and adjacent sides of a right triangle. The angle \( \theta \) can be calculated by:
- Using the formula \( \theta = \tan^{-1} \left( \frac{y}{x} \right) \).
- Here, \( y \) is the vector's y-component, and \( x \) is the vector's x-component.
Inverse Tangent Calculation
Inverse tangent, also known as arctan, is a trigonometric function that helps in finding angles from ratios. In our context, we use it to determine \( \theta \), the angle between the vector and the positive x-axis. Given that the tangent of an angle gives us \( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \), the inverse tangent helps solve for \( \theta \):
- We calculated \( \theta = \tan^{-1}(\sqrt{3}) \).
- Recognizing common tangent values helps realize that \( \tan\left(\frac{\pi}{3}\right) = \sqrt{3} \).
- Thus, \( \theta = \frac{\pi}{3} \) radians.
Radian to Degree Conversion
Angles in mathematics are often expressed in radians and degrees. Converting between these two is a common task. This is necessary if one form is needed over the other, or if a clearer understanding of the angle is preferred. In the radian to degree conversion:
- 1 radian equals \( \frac{180}{\pi} \) degrees.
- To convert radians to degrees, multiply the radian value by \( \frac{180}{\pi} \).