Chapter 11: Problem 75
Find the value of \(c\) if \(\sum_{n=2}^{\infty}(1+c)^{-n}=2\)
Short Answer
Expert verified
The value of \( c \) is \( \frac{-1 + \sqrt{3}}{2} \).
Step by step solution
01
Identify the Series
The series given is a geometric series starting from the term when \( n = 2 \). The general formula for the sum of an infinite geometric series \( \sum_{n=0}^{\infty} ar^n \) is \( \frac{a}{1-r} \), where \( |r| < 1 \). In this exercise, the first term \( a = (1+c)^{-2} \) and the common ratio \( r = (1+c)^{-1} \).
02
Apply the Sum Formula
The sum of the given series is \( \frac{(1+c)^{-2}}{1-(1+c)^{-1}} \). Set this equal to 2 (as given in the problem):\[\frac{(1+c)^{-2}}{1 - (1+c)^{-1}} = 2\]
03
Simplify the Denominator
Simplify the denominator \( 1 - (1+c)^{-1} \) which is equal to \( \frac{(1+c)-1}{1+c} \) or \( \frac{c}{1+c} \). Substitute back into the equation:\[\frac{(1+c)^{-2}}{\frac{c}{1+c}} = 2\]
04
Solve the Equation
Multiply both sides by \( \frac{c}{1+c} \) to eliminate the fraction:\[\frac{1}{(1+c)^2} \cdot \frac{1+c}{c} = 2 \after simplification\]\[\frac{1}{c(1+c)} = 2\]Cross-multiply to get:\[1 = 2c(1+c)\]Expand and rearrange:\[2c^2 + 2c - 1 = 0\]
05
Solve the Quadratic Equation
The quadratic equation \( 2c^2 + 2c - 1 = 0 \) can be solved using the quadratic formula \( c = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \) where \( a = 2 \), \( b = 2 \), and \( c = -1 \). Calculate the discriminant:\[b^2 - 4ac = 2^2 - 4 \cdot 2 \cdot (-1) = 4 + 8 = 12\]Substitute back into the quadratic formula:\[c = \frac{-2 \pm \sqrt{12}}{4} = \frac{-2 \pm 2\sqrt{3}}{4} = \frac{-1 \pm \sqrt{3}}{2}\]
06
Select the Valid Solution
Since \((1+c) > 0\) for the series to converge and \((1+c)^{-1} < 1\), we need \( c > -1 \). The valid solution is \( c = \frac{-1 + \sqrt{3}}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Infinite Series
An infinite series is a sum of the form \( a_1 + a_2 + a_3 + \ldots \), where there are infinitely many terms. In mathematics, working with infinite series can often help solve problems related to limits and certain functions.
A special kind of infinite series is the **geometric series**, where each term is a fixed multiple of the previous one. For example, \( a, ar, ar^2, ar^3, \ldots \). Here, \( a \) is the first term and \( r \) is the common ratio.
If the absolute value of \( r \) is less than 1, the infinite geometric series has a finite sum, which is given by:
A special kind of infinite series is the **geometric series**, where each term is a fixed multiple of the previous one. For example, \( a, ar, ar^2, ar^3, \ldots \). Here, \( a \) is the first term and \( r \) is the common ratio.
If the absolute value of \( r \) is less than 1, the infinite geometric series has a finite sum, which is given by:
- Sum of the series: \( \frac{a}{1-r} \)
- Condition: \( |r| < 1 \)
Convergence of Series
The concept of convergence is key in determining whether the series will approach a specific value or not. For a series to converge, the infinite sum of its parts must result in a finite number. This occurs under specific conditions that are often tied to the series' mathematical properties, like the common ratio in a geometric series.
For a geometric series, convergence happens when the absolute value of the common ratio \( r \) is less than 1. This ensures that each subsequent term reduces in size towards zero, allowing the overall sum to stabilize at a finite value. In the context of the exercise, our series contains terms of the form \( (1+c)^{-n} \). To ensure convergence:
For a geometric series, convergence happens when the absolute value of the common ratio \( r \) is less than 1. This ensures that each subsequent term reduces in size towards zero, allowing the overall sum to stabilize at a finite value. In the context of the exercise, our series contains terms of the form \( (1+c)^{-n} \). To ensure convergence:
- The condition \( (1+c)^{-1} < 1 \) or equivalently \(-1 < c < 0\) is observed.
- This condition ensures the stability of the series over an infinite range.
Quadratic Equation
A quadratic equation is any equation that takes the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants and \( a eq 0 \). Solving these equations can be done using various methods like factoring, completing the square, or using the quadratic formula.
The quadratic formula is especially handy, expressed as:
The quadratic formula is especially handy, expressed as:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- Calculate the discriminant \( b^2 - 4ac \). This value determines the nature of the roots.
- Substitute values into the formula and simplify
- If the discriminant is positive, there are two distinct solutions; if zero, there's one solution; and if negative, the solutions are complex.