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Use series to evaluate the limit. $$ \lim _{x \rightarrow 0} \frac{x^{3}-3 x+3 \tan ^{-1} x}{x^{5}} $$

Short Answer

Expert verified
The limit diverges to infinity as \(x\) approaches 0.

Step by step solution

01

Taylor Series Expansion for Functions

To evaluate the limit, we need to find the Taylor series expansions of the functions around \(x = 0\). The Taylor series for \(\tan^{-1}(x)\) is \(x - \frac{x^3}{3} + \frac{x^5}{5} - \cdots\).
02

Substitute Taylor Series into Expression

Substitute the series expansion for \(\tan^{-1}(x)\) into the given limit expression: \(\lim_{x \to 0} \frac{x^3 - 3x + 3(x - \frac{x^3}{3} + \frac{x^5}{5})}{x^5}\).
03

Simplify the Numerator

Simplify the expression in the numerator: \(x^3 - 3x + 3x - x^3 + \frac{3x^5}{5}\). This simplifies further to \(2x^3 + \frac{3x^5}{5}\).
04

Divide by \(x^5\)

Divide each term of the simplified expression by \(x^5\): \(\lim_{x \to 0} \frac{2x^3 + \frac{3x^5}{5}}{x^5} = \lim_{x \to 0} \left(\frac{2}{x^2} + \frac{3}{5}\right)\).
05

Evaluate the Limit

As \(x\) approaches 0, the term \(\frac{2}{x^2}\) approaches infinity, while \(\frac{3}{5}\) remains constant. Therefore, the expression \(\left(\frac{2}{x^2} + \frac{3}{5}\right)\) diverges to infinity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Expansion
A Taylor series expansion offers a powerful tool for approximating functions by infinite power series. The idea is to represent a function as an infinite sum of terms, calculated from the values of its derivatives at a single point.
For instance, the function \( an^{-1}(x)\) can be expanded around \(x = 0\) as follows:
  • \(x\)
  • \(-\frac{x^3}{3}\)
  • \(+ \frac{x^5}{5}\)
  • \(- \cdots\)
This series helps provide close approximations of \( an^{-1}(x)\) when \(x\) is near 0. By using this expansion, complex expressions can be simplified for further analysis, particularly when evaluating limits.
Limit Evaluation
When evaluating limits, especially those involving complex expressions, the Taylor series (or other series expansions) makes it easier to break down the problem. Given the complexity of some functions, direct substitution isn't always possible or helpful.
For example, in the expression \(\lim_{x \to 0} \frac{x^3 - 3x + 3 \tan^{-1} x}{x^5}\), using the Taylor series expansion of \(\tan^{-1}(x)\), simplifies the expression down to simpler polynomial terms.
This technique allows us to analyze the behavior of the expression as \(x\) approaches 0, revealing underlying trends or behaviors that are obscured in non-simplified expressions. This simplification is crucial, especially when higher order terms become negligible and the focus shifts to leading order terms.
Trigonometric Functions
Trigonometric functions like \( an^{-1}(x)\) often appear in problems involving limits and are frequently expanded using series to simplify calculations. These expansions provide a polynomial form, making it easier to assess the long-term behavior of the function near specific points, especially \(x = 0\).
Such expansions are critical because direct evaluations of limits involving trigonometric functions might be impractical due to their inherent complexities. Additionally, these functions exhibit distinct periodic properties that, when expressed in polynomial terms, offer clearer insights into their local behavior near particular points.
Divergence of Limits
Divergence in limits implies that as \(x\) approaches a certain point, the expression does not settle into a fixed number but instead approaches infinity or negative infinity.
In the expression \(\lim_{x \to 0} \left(\frac{2}{x^2} + \frac{3}{5}\right)\), simplifying the original problem yields a term with \(\frac{2}{x^2}\), making the whole expression divergent as \(x\) nears 0.
This insight illustrates how crucial the identification of divergent behavior is, allowing us to see that while some components might stabilize, others can grow without bound. Acknowledging the divergence is important for concluding how limits behave and for interpreting the implications of the expression as a whole.

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Most popular questions from this chapter

Find the Maclaurin series of \(f\) (by any method) and its radius of convergence. Graph \(f\) and its first few Taylor polynomials on the same screen. What do you notice about the relationship between these polynomials and \(f ?\) $$ f(x)=\ln \left(1+x^{2}\right) $$

13-22 (a) Approximate \(f\) by a Taylor polynomial with degree \(n\) at the number \(a\). (b) Use Taylor's Inequality to estimate the accuracy of the approximation \(f(x)=T_{x}(x)\) when \(x\) lies in the given interval. (c) Check your result in part (b) by graphing \(\left|R_{n}(x)\right|\). $$ f(x)=1 / x, \quad a=1, \quad n=2, \quad 0.7 \leqslant x \leqslant 1.3 $$

If a surveyor measures differences in elevation when making plans for a highway across a desert, corrections must be made for the curvature of the earth. (a) If \(R\) is the radius of the earth and \(L\) is the length of the highway, show that the correction is \(C=R \sec (L / R)-R\) (b) Use a Taylor polynomial to show that \(C \approx \frac{L^{2}}{2 R}+\frac{5 L^{4}}{24 R^{3}}\) (c) Compare the corrections given by the formulas in parts (a) and (b) for a highway that is \(100 \mathrm{km}\) long. (Take the radius of the earth to be \(6370 \mathrm{km}\).)

Find the Maclaurin series for \(f(x)\) using the definition of a Maclaurin series. [Assume that \(f\) has a power series expansion. Do not show that \(\left.R_{n}(x) \rightarrow 0 .\right]\) Also find the associated radius of convergence. $$ f(x)=x \cos x $$

Find the Maclaurin series of \(f\) (by any method) and its radius of convergence. Graph \(f\) and its first few Taylor polynomials on the same screen. What do you notice about the relationship between these polynomials and \(f ?\) $$ f(x)=\cos \left(x^{2}\right) $$

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