Chapter 11: Problem 38
Determine whether the series is convergent or divergent. If it is convergent, find its sum. $$ \sum_{k=0}^{\infty}(\sqrt{2})^{-k} $$
Short Answer
Expert verified
The series is convergent with the sum \( \sqrt{2} + 1 \).
Step by step solution
01
Identify the Series Type
The given series is \( \sum_{k=0}^{\infty} (\sqrt{2})^{-k} \). This is a geometric series because each term can be expressed in the form of \( ar^k \), where \( a \) is the first term and \( r \) is the common ratio.
02
Determine the First Term and Common Ratio
In the series \( \sum_{k=0}^{\infty} (\sqrt{2})^{-k} \), the first term \( a \) is \((\sqrt{2})^{0} = 1\), and the common ratio \( r \) is \((\sqrt{2})^{-1} = \frac{1}{\sqrt{2}} \approx 0.707\).
03
Assess Convergence
A geometric series \( \sum_{k=0}^{\infty} ar^k \) converges if the absolute value of the common ratio \( |r| < 1 \). Here, \( r = \frac{1}{\sqrt{2}} \), and since \(|r| < 1 \), the series is convergent.
04
Find the Sum of the Convergent Series
The sum \( S \) of a convergent infinite geometric series is given by the formula \( S = \frac{a}{1-r} \). Substituting the values, we get \( S = \frac{1}{1 - \frac{1}{\sqrt{2}}} = \frac{1}{1 - \frac{1}{\sqrt{2}}} \). With simplification, \( S = \frac{\sqrt{2}}{\sqrt{2}-1} \). By further rationalizing and simplifying algebraically, this evaluates to \( \sqrt{2} + 1 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a fascinating and fundamental concept in mathematics where each term in the series is a constant multiple of the previous one. It is this repeated multiplication that defines the
- First Term: This is typically denoted by \( a \), and it represents the initial value or the starting point of the series.
- Common Ratio: It is represented as \( r \) and is the factor by which each term is multiplied to get the next. The entire series is driven by this ratio.
Infinite Series
An infinite series is a sum of terms that continues indefinitely. Unlike a finite series, which stops after a certain number of terms, an infinite series keeps going, potentially adding infinite amounts of terms together. The primary question with infinite series is whether they converge to a specific value or diverge. This means:
- Convergent Series: If the series approaches a specific value as more terms are added, it is termed as convergent.
- Divergent Series: If the series does not approach a finite limit, it is considered divergent.
Sum of Series
The sum of a series, especially in the context of a geometric series, can be calculated explicitly if the series is convergent. For geometric series, the formula \( S = \frac{a}{1-r} \) provides us with a tool to find this sum efficiently. Here’s what each element represents:
- \( a \) is the first term of the series.
- \( r \) is the common ratio.
- \( S \) is the sum of the series.