/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A function \(f\) is defined by ... [FREE SOLUTION] | 91Ó°ÊÓ

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A function \(f\) is defined by $$ f(x)=1+2 x+x^{2}+2 x^{3}+x^{4}+\cdots $$ that is, its coefficients are \(c_{2 n}=1\) and \(c_{2 n+1}=2\) for all \(n \geqslant 0 .\) Find the interval of convergence of the series and find an explicit formula for \(f(x) .\)

Short Answer

Expert verified
\(f(x) = \frac{1 + 2x}{1 - x^2}\) on \(-1 < x < 1\).

Step by step solution

01

Identify the Structure of the Series

The given function is a power series in the form of \(f(x) = \sum_{n=0}^{ ext{infinity}} c_n x^n\) with specific coefficients: 1 for even-powered terms and 2 for odd-powered terms. This can be rewritten as \(f(x) = 1 + 2x + x^2 + 2x^3 + x^4 + \, \ldots\).
02

Separate the Series into Two Parts

Notice the series has a pattern of alternating coefficients. Separate it into two series - one for even indices and one for odd indices: \(f(x) = (x^0 + x^2 + x^4 + \ldots) + (2x + 2x^3 + 2x^5 + \ldots)\).
03

Find the Sum of the Even-Powered Series

The even-powered series \(x^0 + x^2 + x^4 + \ldots\) is a geometric series with first term \(a = 1\) and common ratio \(r = x^2\). Therefore, the sum is \(\frac{1}{1 - x^2}\) for \(|x^2| < 1\).
04

Find the Sum of the Odd-Powered Series

The odd-powered series \(2x + 2x^3 + 2x^5 + \ldots\) is another geometric series with first term \(2x\) and common ratio \(x^2\). Its sum is \(\frac{2x}{1 - x^2}\) for \(|x^2| < 1\).
05

Combine the Series

Add the two expressions obtained: \(f(x) = \frac{1}{1-x^2} + \frac{2x}{1-x^2} = \frac{1 + 2x}{1-x^2}\).
06

Determine the Interval of Convergence

For both series, the common ratio \(r = x^2\) dictates convergence as \(|x^2| < 1\), which simplifies to \(-1 < x < 1\). Therefore, the interval of convergence is \(-1 < x < 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interval of Convergence
Understanding the interval of convergence is crucial when working with power series like the one given in the exercise. For a series to be meaningful at a certain point, it must converge at that point.
In simpler terms, this means we need to find the values of the variable where the series adds up to a finite number.
Given our exercise, the series converges when the absolute value of the common ratio is less than one.
The common ratio, in this case, is \(x^2\). Therefore, we require \(|x^2| < 1\) for convergence.
This inequality simplifies to the interval \(-1 < x < 1\), meaning the series is valid for all \x\ values between -1 and 1.
Take note, however: endpoints may need a separate check using convergence tests to see if they should be included.
Geometric Series
A geometric series is a powerful tool used to sum a sequence of numbers that have a constant ratio between consecutive terms.
In the given exercise, the power series is cleverly split into two geometric series.
The even-powered series \(x^0 + x^2 + x^4 + \ldots\) has a first term of \(1\) and a common ratio of \(x^2\).
Its sum converges to \(\frac{1}{1-x^2}\) when the ratio's absolute value is less than one.
Similarly, the odd-powered series \(2x + 2x^3 + 2x^5 + \ldots\) follows a parallel structure but starts with \(2x\).
By representing parts of the function as geometric series, this task becomes easier to handle, providing pathways to simplify complex series into aggregate results.
Explicit Formula
The objective of finding an explicit formula is to represent the series as a neat mathematical function.
Instead of an endless sequence, you calculate a closed expression that provides the same result.
In our exercise, we combined the sums of the two separated geometric series:
  • First part, \(\frac{1}{1-x^2}\), from the even terms.
  • Second part, \(\frac{2x}{1-x^2}\), from the odd terms.
Putting these together gives the series function: \(f(x) = \frac{1 + 2x}{1-x^2}\).
This explicit formula allows anyone to plug in a value within the convergence interval (-1, 1) for \(x\) to determine \(f(x)\).
The formula reflects the original series more compactly and efficiently.
Convergence Tests
Convergence tests are methods used to decide if a series converges and under what conditions.
They ensure us the series is well-behaved and won't trail off to infinity beyond control.
In this exercise, the geometric series test is primarily used. It checks conditions like the absolute value of the common ratio being less than one.
Without utilizing this rule, it’s difficult to narrow down the useful interval for calculating the series.
Moreover, other convergence tests could apply to more complex situations, like the ratio test or the root test.
However, for our series, the geometric series guidelines suffice, ensuring an interval of \(-1 < x < 1\) where the function \(f(x)\) converges consistently.
It's wise to practice several tests in different scenarios to hone a comprehensive understanding.

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Most popular questions from this chapter

Use the Alternating Series Estimation Theorem or Taylor's Inequality to estimate the range of values of \(x\) for which the given approximation is accurate to within the stated error. Check your answer graphically. $$ \cos x=1-\frac{x^{2}}{2}+\frac{x^{4}}{24} \quad(| \text { error } |<0.005) $$

Find the Taylor polynomial \(T_{3}(x)\) for the function \(f\) centered at the number \(a\). Graph \(f\) and \(T_{3}\) on the same screen. $$ f(x)=x e^{-2 x}, \quad a=0 $$

The resistivity \(\rho\) of a conducting wire is the reciprocal of the conductivity and is measured in units of ohm-meters \((\Omega-\mathrm{m}) .\) The resistivity of a given metal depends on the temperature according to the equation \(\rho(t)=\rho_{20} e^{\alpha(t-2 \omega)}\) where \(t\) is the temperature in \(^{\circ} \mathrm{C}\). There are tables that list the values of \(\alpha\) (called the temperature coefficient) and \(\rho_{20}\) (the resistivity at \(20^{\circ} \mathrm{C}\) ) for various metals. Except at very low temperatures, the resistivity varies almost linearly with temperature and so it is common to approximate the expression for \(\rho(t)\) by its first-or second-degree Taylor polynomial at \(t=20 .\) $$ \begin{array}{l}{\text { (a) Find expressions for these linear and quadratic }} \\ {\text { approximations. }} \\ {\text { (b) For copper, the tables give } \alpha=0.0039 /^{\circ} \mathrm{C} \text { and }} \\ {\rho_{20}=1.7 \times 10^{-8} \Omega \text { -m. Graph the resistivity of copper }} \\\ {\text { and the linear and quadratic approximations for }} \\ {-250^{\circ} \mathrm{C} \leqslant t \leqslant 1000^{\circ} \mathrm{C} \text { . }} \\\ {\text { (c) For what values of } t \text { does the linear approximation agree }} \\ {\text { with the exponential expression to within one percent? }}\end{array} $$

Use a computer algebra system to find the Taylor polynomials \(T_{n}\) centered at \(a\) for \(n=2,3,4,5\). Then graph these polynomials and \(f\) on the same screen. $$ f(x)=\sqrt[3]{1+x^{2}}, \quad a=0 $$

Approximate \(f\) by a Taylor polynomial with degree \(n\) at the number \(a\). (b) Use Taylor's Inequality to estimate the accuracy of the approximation \(f(x)=T_{x}(x)\) when \(x\) lies in the given interval. (c) Check your result in part (b) by graphing \(\left|R_{n}(x)\right|\). $$ f(x)=x \ln x, \quad a=1, \quad n=3, \quad 0.5 \leqslant x \leqslant 1.5 $$

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