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Determine whether the series converges or diverges. $$ \sum_{n=1}^{\infty} \frac{1}{n^{3}+8} $$

Short Answer

Expert verified
The series converges.

Step by step solution

01

Identify the General Term

The general term of the series is given by \( a_n = \frac{1}{n^3 + 8} \). We need to determine whether this series \( \sum_{n=1}^{\infty} a_n \) converges.
02

Compare with a Known Convergent Series

Since determining convergence or divergence directly can be complex, compare \( a_n = \frac{1}{n^3 + 8} \) with a simpler series. Notice \( a_n \approx \frac{1}{n^3} \) for large \( n \). The series \( \sum_{n=1}^{\infty} \frac{1}{n^3} \) is known to converge since \( p = 3 > 1 \) when using the p-series test.
03

Apply the Limit Comparison Test

To use the Limit Comparison Test, consider \( b_n = \frac{1}{n^3} \). We compute the limit \( \lim_{n \to \infty} \frac{a_n}{b_n} = \lim_{n \to \infty} \frac{n^3}{n^3 + 8} \).
04

Calculate the Limit

Calculate the limit:\[\lim_{n \to \infty} \frac{n^3}{n^3 + 8} = \lim_{n \to \infty} \frac{1}{1 + \frac{8}{n^3}} = 1\]Since the limit is \( 1 \), a positive constant, by the Limit Comparison Test, both series converge or diverge together.
05

Conclusion on Convergence

Since we compared \( \sum_{n=1}^{\infty} \frac{1}{n^3+8} \) with the convergent series \( \sum_{n=1}^{\infty} \frac{1}{n^3} \) and obtained a finite, non-zero limit, the original series \( \sum_{n=1}^{\infty} \frac{1}{n^3+8} \) converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Comparison Test
The Limit Comparison Test is a useful tool in determining whether a complex series converges or diverges, by comparing it to a simpler series. To use this test, you find two sequences, say \( a_n \) and \( b_n \), which are positive for all sufficiently large \( n \).
The idea is to evaluate the limit \( L = \lim_{n \to \infty} \frac{a_n}{b_n} \). If \( L \) is a finite, positive number, then both series \( \sum a_n \) and \( \sum b_n \) converge or diverge together.
This test is especially handy when dealing with series that resemble each other except for a minor difference, such as the case with \( \sum \frac{1}{n^3+8} \) compared to \( \sum \frac{1}{n^3} \). By using this test, conclusions about the more complicated series can be made from the known properties of the simpler series.
p-series Test
The p-series test is another method to quickly assess whether a series converges or diverges. A p-series takes the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \), where \( p \) is a positive real number. The convergence of a p-series depends on the value of \( p \):
  • If \( p > 1 \), the series converges.
  • If \( p \leq 1 \), the series diverges.
In our example, the series \( \sum \frac{1}{n^3} \) is a p-series with \( p = 3 \), which is greater than 1. Therefore, it converges. The p-series test allows us to make quick judgments about series behaviour without extensive calculations.
Convergent Series
A convergent series is a series whose terms approach zero as their index increases, and the sum of its terms gets closer to a finite number.
When analyzing a series for convergence, something like \( \sum \frac{1}{n^3+8} \), tools such as the Limit Comparison Test or p-series test can be employed to determine if it converges toward a specific value.
This aspect of convergence implies that the series, when summed indefinitely, results in a particular finite value rather than growing unbounded. Convergence is essential in various branches of mathematics and applications where stability and predictability over infinite or continuous domains are required.
Divergent Series
A divergent series, on the other hand, is one where the sum of its terms does not converge to a finite limit. This typically happens when the terms of the series do not decrease at a necessary rate as \( n \) increases, or when terms do not tend towards zero.
For instance, the series \( \sum \frac{1}{n} \), which resembles the harmonic series, diverges because its terms only shrink linearly and not quickly enough.
Identifying divergence is crucial as it indicates that no finite sum exists as \( n \) approaches infinity. This is an important consideration for predicting outcomes in mathematical models or real-world phenomena where divergent series would represent unbounded behavior.

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