Chapter 11: Problem 26
Test the series for convergence or divergence. $$ \sum_{n=1}^{\infty} \frac{n^{2}+1}{5^{n}} $$
Short Answer
Expert verified
The series converges by the Ratio Test.
Step by step solution
01
Identify the Series Type
The given series is \( \sum_{n=1}^{\infty} \frac{n^{2}+1}{5^{n}} \). This looks like an exponential-geometric series because the terms involve \( 5^{n} \), an exponential base raised to the power of \( n \).
02
Apply the Ratio Test
To determine the convergence of the series, we'll apply the Ratio Test. The Ratio Test states that for the series \( \sum a_n \), the series converges absolutely if \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1 \). If \( a_n = \frac{n^2 + 1}{5^n} \), then \( a_{n+1} = \frac{(n+1)^2 + 1}{5^{n+1}} \).
03
Calculate the Ratio
We calculate \( \left| \frac{a_{n+1}}{a_n} \right| = \left| \frac{(n+1)^2 + 1}{5^{n+1}} \cdot \frac{5^n}{n^2 + 1} \right| = \frac{(n+1)^2 + 1}{5(n^2 + 1)} \).
04
Evaluate the Limit
Find \( \lim_{n \to \infty} \frac{(n+1)^2 + 1}{5(n^2 + 1)} \). As \( n \to \infty \), the dominant terms in the numerator and denominator are \( n^2 \). So, the limit becomes \( \lim_{n \to \infty} \frac{n^2 + 2n + 2}{5n^2} \). Simplifying, we get: \( \lim_{n \to \infty} \frac{1}{5} + \frac{2}{5n} + \frac{2}{5n^2} = \frac{1}{5} \).
05
Conclude Using the Ratio Test
Since \( \frac{1}{5} < 1 \), the Ratio Test confirms that the series \( \sum_{n=1}^{\infty} \frac{n^{2}+1}{5^{n}} \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ratio Test
The Ratio Test is a crucial tool in determining the nature of series, particularly whether they converge or diverge. This test utilizes the concept of limit to analyze the behavior of a series’ terms as they approach infinity. The test is applied to a series \( \sum a_n \) by examining the absolute value of the ratio of consecutive terms, \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \).
- If this limit is less than 1, \( \sum a_n \) will converge absolutely. This result means that the series settles into a specific value as more and more terms are added.
- If the limit is greater than 1, or if it reaches infinity, the series will diverge, meaning it grows without bounds.
- If the limit equals 1, the test is inconclusive, and other methods are needed for further examination.
Exponential-Geometric Series
An exponential-geometric series is a blend of the exponential and geometric series properties, often characterized by a sequence where one of the series elements is in the form of \( b^n \), with \( b \) being a constant base greater than zero. Such series can be challenging to analyze due to their structure, often featuring combinations like polynomial over exponential terms, which appear in our series: \( \sum_{n=1}^{\infty} \frac{n^2 + 1}{5^n} \).In this particular series:
- The exponential part \( 5^n \) can rapidly dominate the growth of the terms, making it paramount for convergence analysis. This is because the geometric decay of \( 5^n \) in the denominator often overpowers any polynomial growth in the numerator.
- Despite having a polynomial numerator, the exponential term in the denominator ensures that the series converges because the series terms become extremely small as \( n \) increases.
Limit of a Sequence
Understanding the limit of a sequence is foundational in the calculus-based exploration of series. A sequence \( \{a_n\} \) is essentially a list of numbers, and its limit describes what value this list approaches as it progresses to infinity. Here is how limits play a role:
- The limit helps us in the Ratio Test by revealing the behavior of the series as terms become very large. In our exercise, computing the limit of \( \frac{(n+1)^2 + 1}{5(n^2 + 1)} \) was crucial and reduced to tackling the behavior of \( n^2 \), the dominant term in the fraction.
- Simplifying to the limit \( \lim_{n \to \infty} \frac{1}{5} + \frac{2}{5n} + \frac{2}{5n^2} = \frac{1}{5} \) demonstrated that as \( n \) grows, the additional fractions become negligible, leaving us with the primary limiting value.
- This directed insight into the series' convergence, guiding us effectively to conclude about its behavior without needing to calculate exact sums.