/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Suppose you know that the series... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose you know that the series \(\Sigma_{n-0}^{\infty} b_{n} x^{n}\) converges for \(|x|<2 .\) What can you say about the following series? Why? $$ \sum_{n=0}^{\infty} \frac{b_{n}}{n+1} x^{n+1} $$

Short Answer

Expert verified
The series converges for \(|x|<2\) due to the similar or increased convergence behavior.

Step by step solution

01

Understanding the Convergence of the Original Series

The series \( \sum_{n=0}^{\infty} b_{n} x^{n} \) converges for \( |x| < 2 \). Since the series are power series centered at \( x = 0 \), the interval of convergence is determined by the radius of convergence, which is \( R = 2 \) for this series.
02

Identify New Series Relationship

We need to analyze the new series \( \sum_{n=0}^{\infty} \frac{b_{n}}{n+1} x^{n+1} \). Notice that this series is obtained by taking each term \( b_n x^n \) from the original series, dividing by \( n+1 \), and multiplying by \( x \), effectively forming terms of the form \( \frac{b_n}{n+1} x^{n+1} \).
03

Determine the Ratio of Corresponding Terms

The nature of the coefficients \( \frac{b_n}{n+1} \) versus the \( b_n \) tends to reduce the magnitude of each term as \( n \) increases because \( n+1 \) increases linearly with \( n \).
04

Analyze Convergence Using Radius of Convergence

Since the division by \( n+1 \) only affects scaling and doesn't affect the convergence determined by \( x^{n+1} \), we can infer that the series \( \sum_{n=0}^{\infty} \frac{b_{n}}{n+1} x^{n+1} \) will have the same interval of convergence regarding \( x \) as the original series \( \sum_{n=0}^{\infty} b_{n} x^{n} \), that is \( |x| < 2 \). The convergence might be even better because each term is divided by an increasing integer, but this does not change the interval defined by \( x \).
05

Conclusion

The new series \( \sum_{n=0}^{\infty} \frac{b_{n}}{n+1} x^{n+1} \) converges in the same interval \(|x| < 2\) as the original series \( \sum_{n=0}^{\infty} b_{n} x^{n} \). This is because the division by \( n+1 \) stabilizes the convergence within the same radius of convergence.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radius of Convergence
When dealing with power series, the radius of convergence is a key concept. It indicates the distance from the center of the series, at which the series converges. For the series \( \sum_{n=0}^{\infty} b_{n} x^{n} \), the radius of convergence is given as \( R = 2 \). This tells us that within this radius, \( |x| < 2 \), the series will converge. This radius is determined by how the coefficients \( b_n \) behave as \( n \) increases. Often, tests like the ratio test are used to compute \( R \). It's helpful to think about it like the boundary inside which the series maintains stability and sum well-behaved results.
Interval of Convergence
The interval of convergence is directly related to the radius of convergence, and for our series, it spans from \(-2\) to \(2\), that is \(|x| < 2\). This interval indicates the specific range of \( x \) values where the series converges to a finite value. Within this interval, you can plug any \( x \) value and expect the series to yield a meaningful result. However, it's important to check the endpoints separately because power series might behave differently at the radius's edge, quite similar to how waves crash against a cliff at the ocean's edge. For the given series, we are focusing on \( |x| < 2 \), hence not including the endpoints \( -2 \) and \( 2 \) in this case.
Ratio Test
The ratio test is a method commonly used to determine the radius of convergence of a series. The test involves taking the limit of the absolute value of the ratio of successive terms in the series. Mathematically, this is expressed as:\[ \lim_{n\to\infty} \left| \frac{a_{n+1}}{a_n} \right| = L \]If \( L < 1 \), the series converges absolutely. If \( L > 1 \) or becomes infinite, the series diverges. If \( L = 1 \), the test is inconclusive. For our original series, applying the ratio test would help verify the radius as \( R = 2 \). For the new series, the additional \( x \) term shifts the ratio a bit, but crucially, since dividing by \( n+1 \) doesn’t drastically alter the foundation of convergence, the same radius applies. This subtlety highlights how small changes in a series can affect its convergence without altering its core properties.
Comparison of Series
Comparing series helps to understand how a modification in the terms of a series affects convergence. When comparing the original series \( \sum_{n=0}^{\infty} b_{n} x^{n} \) to the new series \( \sum_{n=0}^{\infty} \frac{b_{n}}{n+1} x^{n+1} \), we see that each term of the latter series is reduced by \( n+1 \), which increases as \( n \) grows. This means each modified term is smaller in magnitude, potentially enhancing convergence properties. By comparing the two series and understanding their term structure, it becomes clear that while the division changes the growth of the terms, it preserves the major convergence characteristics due to how the terms interplay within the power series. Thus, even though the coefficient changes tend to stabilize the series further, the new series retains the same interval of convergence as the original.

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Most popular questions from this chapter

The resistivity \(\rho\) of a conducting wire is the reciprocal of the conductivity and is measured in units of ohm-meters \((\Omega-\mathrm{m}) .\) The resistivity of a given metal depends on the temperature according to the equation \(\rho(t)=\rho_{20} e^{\alpha(t-2 \omega)}\) where \(t\) is the temperature in \(^{\circ} \mathrm{C}\). There are tables that list the values of \(\alpha\) (called the temperature coefficient) and \(\rho_{20}\) (the resistivity at \(20^{\circ} \mathrm{C}\) ) for various metals. Except at very low temperatures, the resistivity varies almost linearly with temperature and so it is common to approximate the expression for \(\rho(t)\) by its first-or second-degree Taylor polynomial at \(t=20 .\) $$ \begin{array}{l}{\text { (a) Find expressions for these linear and quadratic }} \\ {\text { approximations. }} \\ {\text { (b) For copper, the tables give } \alpha=0.0039 /^{\circ} \mathrm{C} \text { and }} \\ {\rho_{20}=1.7 \times 10^{-8} \Omega \text { -m. Graph the resistivity of copper }} \\\ {\text { and the linear and quadratic approximations for }} \\ {-250^{\circ} \mathrm{C} \leqslant t \leqslant 1000^{\circ} \mathrm{C} \text { . }} \\\ {\text { (c) For what values of } t \text { does the linear approximation agree }} \\ {\text { with the exponential expression to within one percent? }}\end{array} $$

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