Chapter 11: Problem 18
Approximate \(f\) by a Taylor polynomial with degree \(n\) at the number \(a\). (b) Use Taylor's Inequality to estimate the accuracy of the approximation \(f(x)=T_{x}(x)\) when \(x\) lies in the given interval. (c) Check your result in part (b) by graphing \(\left|R_{n}(x)\right|\). $$ f(x)=\ln (1+2 x), \quad a=1, \quad n=3, \quad 0.5 \leqslant x \leqslant 1.5 $$
Short Answer
Step by step solution
Determine Derivatives
Compute Taylor Polynomial Terms
Construct the Taylor Polynomial
Apply Taylor's Inequality
Confirm with Graph
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor polynomial
Let’s consider how a Taylor polynomial is constructed! We choose a point, often denoted as \( a \), and then use the function's value and derivatives at this point. This helps form an approximate polynomial that represents the function near \( a \).
For example, the third-degree Taylor polynomial for the function \( f(x) = \ln(1 + 2x) \) at \( a = 1 \) is obtained by calculating derivative terms at \( a \). In this instance, we use the polynomial:
- Constant term: \( f(1) = \ln(3) \)
- First derivative term: \( f'(1) \times (x-1) = \frac{2}{3}(x-1) \)
- Second derivative term: \( \frac{f''(1)}{2!} \times (x-1)^2 = -\frac{2}{9}(x-1)^2 \)
- Third derivative term: \( \frac{f'''(1)}{3!} \times (x-1)^3 = \frac{8}{81}(x-1)^3 \)
remainder estimate
This is where the remainder estimate comes into play. The remainder, \( |R_n(x)| \), is essentially the error between the Taylor polynomial and the actual function for a specific degree \( n \). Calculating it allows us to understand how precise our polynomial approximation is in a given interval.
Using Taylor's inequality, we can estimate the remainder:\[ |R_n(x)| \leq \frac{M}{(n+1)!}|x-a|^{n+1} \]Where:
- \( M \) is the maximum value of the next derivative (in this case, the fourth derivative) over the interval.
- \( (n+1)! \) is the factorial of \( n+1 \).
derivatives calculation
For the function \( f(x) = \ln(1 + 2x) \), we find its derivatives as follows:
- First derivative, \( f'(x) = \frac{2}{1 + 2x} \), tells us the slope of the function.
- Second derivative, \( f''(x) = -\frac{4}{(1 + 2x)^2} \), indicates how the slope changes.
- Third derivative, \( f'''(x) = \frac{16}{(1 + 2x)^3} \), provides further details on concavity.
- Fourth derivative, \( f^{(4)}(x) = -\frac{96}{(1 + 2x)^4} \), adds more precision to our calculation.
- \( f(1) = \ln(3) \)
- \( f'(1) = \frac{2}{3} \)
- \( f''(1) = -\frac{4}{9} \)
- \( f'''(1) = \frac{16}{27} \)
Taylor's inequality
It provides an upper bound for the unexplored error between the function and the polynomial over a specific interval.
- Taylor's inequality formula: \[ |R_n(x)| \leq \frac{M}{(n+1)!}|x-a|^{n+1} \]
- \( M \) signifies the maximum value of the derivative's absolute value, here the fourth derivative in the interval \([0.5, 1.5]\).
For example, for \( f^{(4)}(x) = -\frac{96}{(1+2x)^4} \), \( M \) is approximately 0.64 within the given interval.
Then, applying:\[ |R_3(x)| \leq \frac{0.64}{24} \approx 0.0267 \]This bound confirms that the Taylor polynomial approximates the function within a small error, aiding us in judging and trusting the polynomial's use for approximations.