Chapter 11: Problem 11
Test the series for convergence or divergence. $$ \sum_{n=1}^{\infty}\left(\frac{1}{n^{3}}+\frac{1}{3^{n}}\right) $$
Short Answer
Expert verified
The series converges.
Step by step solution
01
Separate the Series
The given series can be expressed as the sum of two separate series: \[ \sum_{n=1}^{\infty} \frac{1}{n^{3}} + \sum_{n=1}^{\infty} \frac{1}{3^{n}}. \] We will consider each series individually for convergence.
02
Test the First Series - P-Series Test
The first series \( \sum_{n=1}^{\infty} \frac{1}{n^{3}} \) is a p-series with \( p = 3 \). Recall that a p-series \( \sum_{n=1}^{\infty} \frac{1}{n^{p}} \) converges if \( p > 1 \). Since \( p = 3 > 1 \), this series converges.
03
Test the Second Series - Geometric Series Test
The second series \( \sum_{n=1}^{\infty} \frac{1}{3^{n}} \) is a geometric series with a common ratio \( r = \frac{1}{3} \). A geometric series \( \sum_{n=1}^{\infty} ar^{n} \) converges if \( |r| < 1 \). Since \( \frac{1}{3} < 1 \), this geometric series converges.
04
Combine Results
Both sub-series \( \sum_{n=1}^{\infty} \frac{1}{n^{3}} \) and \( \sum_{n=1}^{\infty} \frac{1}{3^{n}} \) individually converge. By the principle that the sum of two convergent series is also convergent, the original series \( \sum_{n=1}^{\infty} \left( \frac{1}{n^{3}} + \frac{1}{3^{n}} \right) \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding P-Series
A p-series is a popular type of infinite series that takes the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \), where \( p \) is a positive constant. The convergence of a p-series depends on the value of \( p \). If \( p \) is greater than 1, then the series converges. Conversely, if \( p \) is less than or equal to 1, the series diverges.
To see why this matters, imagine pouring water into different-sized containers. If \( p > 1 \), the container overflows because the amount you pour (the series terms) decreases fast enough. But if \( p \leq 1 \), the container just keeps holding more water (the series diverges).
In our specific exercise, the series \( \sum_{n=1}^{\infty} \frac{1}{n^{3}} \) converges since \( p = 3 > 1 \). This means that as you add more terms from \( \frac{1}{1^3} \) to \( \frac{1}{2^3} \) and onwards, the sum approaches a finite value.
To see why this matters, imagine pouring water into different-sized containers. If \( p > 1 \), the container overflows because the amount you pour (the series terms) decreases fast enough. But if \( p \leq 1 \), the container just keeps holding more water (the series diverges).
In our specific exercise, the series \( \sum_{n=1}^{\infty} \frac{1}{n^{3}} \) converges since \( p = 3 > 1 \). This means that as you add more terms from \( \frac{1}{1^3} \) to \( \frac{1}{2^3} \) and onwards, the sum approaches a finite value.
What is a Geometric Series?
Geometric series have their own distinctive pattern. They can be written as \( \sum_{n=0}^{\infty} ar^n \), where \( a \) is the first term and \( r \) is the common ratio between successive terms. The convergence of a geometric series is determined by the absolute value of the common ratio \( |r| \).
Here's the rule:
In the original exercise, the second series is \( \sum_{n=1}^{\infty} \frac{1}{3^n} \) with \( r = \frac{1}{3} \). Given \( \left| \frac{1}{3} \right| < 1 \), we know it converges.
Here's the rule:
- If \( |r| < 1 \), the series converges.
- If \( |r| \geq 1 \), the series diverges.
In the original exercise, the second series is \( \sum_{n=1}^{\infty} \frac{1}{3^n} \) with \( r = \frac{1}{3} \). Given \( \left| \frac{1}{3} \right| < 1 \), we know it converges.
Diving Into Convergence Tests
Convergence tests are tools used to determine whether an infinite series converges or diverges. With a variety of tests available, selecting the right one depends on the series given.
Some common convergence tests include:
Some common convergence tests include:
- P-Series Test: Quickly determines the convergence of p-series when \( p > 1 \).
- Geometric Series Test: Checks convergence when \( |r| < 1 \) for geometric series.
- Comparison Test: Compares an unknown series with a series whose convergence status is known.
- Ratio Test: Effective for series with factorials or exponential expressions.
Examining Infinite Series
Infinite series are sequences of numbers added up indefinitely. They're an extension of finite series and play a crucial role in calculus and real analysis. The key question with infinite series is whether they converge to a particular value or keep growing endlessly (diverge).
Understanding infinite series involves recognizing different types:
Understanding infinite series involves recognizing different types:
- Arithmetic Series: Terms add a constant.
- Geometric Series: Terms multiply by a constant ratio.
- P-Series: Terms decrease by powers of n.
- Harmonic Series: The slowest diverging series, taking the form \( \sum_{n=1}^{\infty} \frac{1}{n} \).