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(a) Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as t increases. (b) Eliminate the parameter to ind a Cartesian equation of the curve. $$ x=\sin t, \quad y=1-\cos t, \quad 0 \leqslant t \leqslant 2 \pi $$

Short Answer

Expert verified
The curve is a circle centered at (0, 1) with radius 1.

Step by step solution

01

Identify Parametric Equations

You have the parametric equations: \( x = \sin t \) and \( y = 1 - \cos t \), with \( 0 \leq t \leq 2\pi \). These describe the relationship between \( x \) and \( y \) as a function of a parameter \( t \).
02

Plot Specific Points

Choose several values of \( t \) within the range and calculate corresponding \( x \) and \( y \) coordinates. Example points are:- \( t=0 \): \( x = 0 \), \( y = 0 \)- \( t=\pi/2 \): \( x = 1 \), \( y = 2 \)- \( t=\pi \): \( x = 0 \), \( y = 1 \)- \( t=3\pi/2 \): \( x = -1 \), \( y = 2 \)- \( t=2\pi \): \( x = 0 \), \( y = 0 \)Plot these points on the coordinate plane.
03

Sketch the Curve

Connect the plotted points smoothly to form the path of the curve. The curve will look like a unique shape traced by these points with corresponding \( x \) and \( y \) values. Draw an arrow on the curve to indicate the direction from \( t=0 \) to \( t=2\pi \), which is counterclockwise starting and ending at (0,0).
04

Eliminate the Parameter

Use trigonometric identities to eliminate \( t \). Start by squaring both parametric equations: - \( x = \sin t \rightarrow x^2 = \sin^2 t \)- \( y = 1 - \cos t \rightarrow 1 - y = \cos t \rightarrow (1 - y)^2 = \cos^2 t \)Using the identity \( \sin^2 t + \cos^2 t = 1 \), substitute: \[ x^2 + (1-y)^2 = 1 \]
05

Simplify to Cartesian Equation

Expand and simplify the equation:\[ x^2 + (1 - 2y + y^2) = 1 \]\[ x^2 + y^2 - 2y + 1 = 1 \]Subtract 1 from both sides:\[ x^2 + y^2 - 2y = 0 \]Complete the square for \( y \):\[ x^2 + (y-1)^2 = 1 \]This is the Cartesian equation of the curve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian Equation
When working with parametric equations, one of the main tasks is converting them into a Cartesian equation. This process involves eliminating the parameter—in this case, "t" from the equations.
In the given exercise, we started with the parametric equations:
  • \( x = \sin t \)
  • \( y = 1 - \cos t \)
To find the Cartesian equation, we make use of trigonometric identities to remove "t."
Squaring both equations gives us:
  • \( x^2 = \sin^2 t \)
  • \( (1 - y)^2 = \cos^2 t \)
Using the identity \( \sin^2 t + \cos^2 t = 1 \), we substitute and simplify to obtain a relationship just in terms of \( x \) and \( y \):\[ x^2 + (1-y)^2 = 1 \]
This results in the final Cartesian equation that describes the curve in a way that's free of the parameter \( t \).
Curve Sketching
Sketching curves described by parametric equations helps visualize how the variables change with respect to the parameter "t." In this exercise, plotting specific points obtained by substituting values of "t" is crucial.
By choosing values like \( t = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, \) and \( 2\pi \), we found points like (0,0), (1,2), (0,1), (-1,2), and back to (0,0).
Connecting these points smoothly, a loop-like curve emerges. The direction in which the curve is traced is indicated with an arrow from \( t=0 \) to \( t=2\pi \), moving counterclockwise.
This visualization helps understand not just the shape and nature of the curve but also how the curve is traversed over a cycle of the parameter. Curve sketching can provide a clear geometric interpretation of parametric paths.
Trigonometric Identities
Trigonometric identities are powerful tools in converting parametric equations to their Cartesian forms. They simplify the process of removing the parameter.
Here, identities such as \( \sin^2 t + \cos^2 t = 1 \) provide a connection between the squared terms gained from the parametric equations.
By squaring each part of our parametric equations and utilizing this core trigonometric identity, we are able to eliminate "t."
This results in the equation: \[ x^2 + (1-y)^2 = 1 \]
Trigonometric identities not only help in mathematical transformations but also assist in understanding relationships between angles and sides within trigonometric functions. Access to such identities is essential for anyone working with angles and periodic patterns in mathematics.
Completing the Square
Completing the square is a crucial algebraic technique used to transform quadratic expressions into a different form, often to reveal geometric properties of an equation.
In the Cartesian equation derived:\[ x^2 + y^2 - 2y = 0 \]
Completing the square for the "y" part involves:
  • Rewriting \( y^2 - 2y \) as \( (y-1)^2 - 1 \)
This transformation helps in rearranging the equation into:\[ x^2 + (y - 1)^2 = 1 \]
This reveals a standard circle equation centered at (0,1) with radius 1 on the Cartesian plane. Completing the square offers a technique to understand forms, centers, and dimensions of these geometric figures, allowing mathematical equations to be interpreted as real-world shapes.

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