Chapter 10: Problem 72
(a) Show that the curvature at each point of a straight line is \(\kappa=0\). (b) Show that the curvature at each point of a circle of radius \(r\) is \(\kappa=1 / r\).
Short Answer
Expert verified
(a) Curvature of a straight line is 0.
(b) Curvature of a circle is \(1/r\).
Step by step solution
01
Understanding Curvature on a Straight Line
The curvature \( \kappa \) at any point on a curve describes how the curve changes direction at that point. For a straight line, intuitively, there is no change in direction.
02
Mathematical Definition for Curvature
The curvature \( \kappa \) of a curve defined by \( y = f(x) \) is given by:\[\kappa = \frac{|f''(x)|}{[1+f'(x)^2]^{3/2}}\]For a straight line \( y = mx + c \), the first derivative \( f'(x) = m \) is constant, and the second derivative \( f''(x) = 0 \).
03
Calculate Curvature for Straight Line
Substituting \( f''(x) = 0 \) into the curvature formula:\[\kappa = \frac{0}{[1 + m^2]^{3/2}} = 0\]Thus, the curvature \( \kappa \) is zero for a straight line.
04
Understanding Curvature on a Circle
For a circle, the curvature indicates how sharply the curve forms around its center point. Intuitively, a smaller radius circle bends more sharply, implying higher curvature.
05
Mathematical Definition for Circle's Curvature
Consider a circle centered at \( (0,0) \) with radius \( r \), parameterized as \( (r\cos(\theta), r\sin(\theta)) \). The general formula for curvature \( \kappa \) is:\[\kappa = \left| \frac{x'y'' - y'x''}{(x'^2 + y'^2)^{3/2}} \right|\]where \( x' = -r\sin(\theta) \), \( x'' = -r\cos(\theta) \), \( y' = r\cos(\theta) \), and \( y'' = -r\sin(\theta) \).
06
Calculate Curvature for Circle
Substitute the derivatives obtained for \( x \) and \( y \) in the curvature formula:\[\kappa = \left| \frac{(-r\sin(\theta))(-r\sin(\theta)) - (r\cos(\theta))(-r\cos(\theta))}{((-r\sin(\theta))^2 + (r\cos(\theta))^2)^{3/2}} \right|\]Simplify the equation to:\[\kappa = \left| \frac{r^2(\sin^2(\theta) + \cos^2(\theta))}{r^3} \right|\]Since \( \sin^2(\theta) + \cos^2(\theta) = 1 \), the expression simplifies further to:\[\kappa = \frac{1}{r}\]Therefore, the curvature for a circle is \( \frac{1}{r} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curvature of a Straight Line
Let's start by understanding the concept of curvature, particularly for a straight line. Curvature describes how much a curve deviates from being straight. In simple terms, it's a measure of how "bendy" a curve is. For a straight line, this is easy to determine: it doesn't bend at all. Therefore, its curvature is zero. The mathematics supports this intuition. Consider the mathematical definition of curvature for a function described by \( y = f(x) \). The curvature \( \kappa \) is given by the formula: \[ \kappa = \frac{|f''(x)|}{[1+f'(x)^2]^{3/2}} \] For a straight line, \( y = mx + c \), you have a constant slope \( m \), meaning the first derivative \( f'(x) = m \) is constant, and the second derivative \( f''(x) = 0 \). Plugging into the formula, the numerator becomes zero, leaving \( \kappa = 0 \). This mathematically confirms that a straight line has zero curvature.
Curvature of a Circle
The curvature of a circle is an intriguing concept because it's everywhere the same on the shape. The idea is simple: a circle wraps around a central point and its curvature tells us how sharply it bends. Intuitively, a smaller circle has a sharper bend, whereas a larger one bends gently. The curvature \( \kappa \) for a circle with radius \( r \) is given by: \( \kappa = \frac{1}{r} \). So, if the circle is small, the curvature is higher, and as the circle gets larger, the curvature decreases. Some practical examples:
- A circle with radius 1 (unit circle) has a curvature of 1.
- A circle with radius 2 has a curvature of 0.5.
Mathematical Definition of Curvature
The mathematical definition of curvature provides a way to precisely measure how much a curve deviates from being a straight line at any given point. For any function described by \( y = f(x) \), the formal definition of curvature is: \[\kappa = \frac{|f''(x)|}{[1+f'(x)^2]^{3/2}} \] This formula uses derivatives to determine changes in the slope direction.
- \( f'(x) \), the first derivative, measures the slope or steepness of a curve at any point.
- \( f''(x) \), the second derivative, measures how the slope itself is changing.
Radius and Curvature
The relationship between radius and curvature is fundamental, especially when considering circular shapes. The formula \( \kappa = \frac{1}{r} \) implies that curvature and radius are inversely related, providing insights into geometric properties.
- A smaller radius results in a larger curvature, meaning the curve sharpens.
- A larger radius results in a smaller curvature, making the curve more gentle.