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Find the exact value of each expression. $$ \frac{1}{3} \ln (x+2)^{3}+\frac{1}{2}\left[\ln x-\ln \left(x^{2}+3 x+2\right)^{2}\right] $$

Short Answer

Expert verified
The exact value is \( \ln\left( \frac{\sqrt{x}}{x+1} \right) \).

Step by step solution

01

Simplify Each Logarithmic Term Using Power Rule

Rewrite the expression using the power rule for logarithms, which states that \( a \ln(b) = \ln(b^a) \). The given expression is \( \frac{1}{3} \ln (x+2)^3 \). Applying the power rule yields:\[\ln((x+2)^3)^{1/3} = \ln(x+2)\]
02

Simplify Complex Logarithmic Expression

Apply the power rule to the second term as well: \[ \frac{1}{2} [\ln x - \ln(x^2 + 3x + 2)^2] \to \ln(x)^{1/2} - \ln((x^2 + 3x + 2)^2)^{1/2} \]Simplifying further by substituting powers:\[ \ln \sqrt{x} - \ln(x^2 + 3x + 2) \]
03

Combine Logarithmic Terms Using Logarithm Rules

Combine the logarithmic expressions using the quotient rule of logarithms. The quotient rule states \( \ln a - \ln b = \ln \frac{a}{b} \).So, we have:\[ \ln(x+2) + \ln \frac{\sqrt{x}}{x^2 + 3x + 2} \] Combine these to get:\[ \ln\left( (x+2) \cdot \frac{\sqrt{x}}{x^2 + 3x + 2} \right) \]
04

Factor the Expression in the Denominator

Factor \( x^2 + 3x + 2 \) in the denominator. This quadratic can be factored as:\[ x^2 + 3x + 2 = (x+1)(x+2) \] Substitute back into the expression:\[ \ln\left( (x+2) \cdot \frac{\sqrt{x}}{(x+1)(x+2)} \right) \]
05

Simplify and Find Final Expression

Cancel similar terms in the numerator and the denominator:\[ \ln\left( \frac{\sqrt{x}}{x+1} \right) \]So, the exact value of the given expression is \( \ln\left( \frac{\sqrt{x}}{x+1} \right) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule for Logarithms
The power rule for logarithms is a useful property that helps us simplify logarithmic expressions by moving exponents outside the log. It states that \( a \ln(b) = \ln(b^a) \). Basically, if you have the logarithm of a power, you can move the exponent in front of the log as a coefficient. For example, in the expression \( \frac{1}{3} \ln (x+2)^3 \), you can simplify it by applying the power rule: multiply the exponent, 3, by \( \frac{1}{3} \) to get \( \ln(x+2) \). This simplification helps make complex expressions more manageable, allowing us to see the underlying structure more clearly.
  • Simplifies expressions by turning exponents into coefficients.
  • Makes complex logarithmic terms easier to work with.
The power rule is especially beneficial when simplifying expressions, making it easier to apply additional algebraic techniques.
Quotient Rule for Logarithms
The quotient rule for logarithms is another key tool in simplifying logarithmic expressions. It states that the difference of two logarithms can be expressed as the logarithm of a quotient: \( \ln a - \ln b = \ln \frac{a}{b} \). This principle helps combine two logs into one, which simplifies the arithmetic. For instance, when managing the expression \( \ln x - \ln(x^2 + 3x + 2) \), you can apply the quotient rule to rewrite it as \( \ln \frac{x}{x^2 + 3x + 2} \).
  • Transforms subtraction of logs into a division inside a single log.
  • Reduces the number of logarithmic terms, helping in further simplifications.
Using this rule can dramatically reduce the complexity of solving equations involving logarithms, especially when you're working toward isolating a particular variable or term.
Factoring Quadratics
Factoring quadratics is a very important algebraic skill, especially useful when simplifying expressions involving quadratic terms. The process involves rewriting a quadratic expression in the form \( ax^2 + bx + c \) into the product of two binomials. For instance, the quadratic \( x^2 + 3x + 2 \) can be factored as \( (x+1)(x+2) \). This step is crucial when simplifying complex rational expressions, as it can lead to cancellation of terms and further simplification.
  • Identifies factors that make the quadratic expression easier to work with.
  • Often leads to simplification by canceling terms in numerators and denominators.
Factoring is often the key step before any cancellation in rational expressions, allowing for a clearer understanding of what is happening in the problem.

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Most popular questions from this chapter

If \(f\) and \(g\) are both even functions, is \(f+g\) even? If \(f\) and \(g\) are both odd functions, is \(f+g\) odd? What if \(f\) is even and \(g\) is odd? Justify your answers.

After alcohol is fully absorbed into the body, it is metabolized with a half- life of about 1.5 hours. Suppose you have had three alcoholic drinks and an hour later, at midnight, your blood alcohol concentration (BAC) is \(0.6 \mathrm{mg} / \mathrm{mL}\). (a) Find an exponential decay model for your BAC \(t\) hours an after midnight. (b) Graph your BAC and use the graph to determine when you can drive home if the legal limit is \(0.08 \mathrm{mg} / \mathrm{mL}\).

A spherical balloon is being inflated and the radius of the balloon is increasing at a rate of \(2 \mathrm{cm} / \mathrm{s}\). (a) Express the radius \(r\) of the balloon as a function of the time \(t\) (in seconds). (b) If \(V\) is the volume of the balloon as a function of the radius, find \(V \circ r\) and interpret it.

When a camera flash goes off, the batteries immediately begin to recharge the flash's capacitor, which stores electric charge given by $$ Q(t)=Q_{0}\left(1-e^{-t / a}\right) $$ (The maximum charge capacity is \(Q_{0}\) and \(t\) is measured in seconds.) (a) Find the inverse of this function and explain its meaning. (b) How long does it take to recharge the capacitor to \(90 \%\) of capacity if \(a=2 ?\)

Find the exact value of each expression. $$ \text { (a) } \log _{5} \frac{1}{125} \quad \text { (b) } \ln \left(1 / e^{2}\right) $$

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