Chapter 9: Problem 7
Write out the first five terms of the sequence, determine whether the sequence converges, and if so find its limit. $$ \left\\{\frac{n}{n+2}\right\\}_{n=1}^{+\infty} $$
Short Answer
Expert verified
The sequence converges to 1.
Step by step solution
01
Identify the Sequence Formula
The given sequence is defined as \( a_n = \frac{n}{n+2} \) where \( n \) starts from 1 and goes to infinity.
02
Calculate the First Five Terms
Substitute \( n = 1, 2, 3, 4, 5 \) in the formula to find the terms:\( \frac{1}{1+2} = \frac{1}{3} \), \( \frac{2}{2+2} = \frac{2}{4} = \frac{1}{2} \), \( \frac{3}{3+2} = \frac{3}{5} \), \( \frac{4}{4+2} = \frac{4}{6} = \frac{2}{3} \), \( \frac{5}{5+2} = \frac{5}{7} \).
03
Observe the Pattern
The sequence of terms \( \frac{1}{3}, \frac{1}{2}, \frac{3}{5}, \frac{2}{3}, \frac{5}{7}\) shows an increasing pattern as \( n \) increases.
04
Determine the Behavior as \( n \to \infty \)
Examine the limit of the sequence as \( n \) approaches infinity by considering the expression \( \frac{n}{n+2} \). Dividing the numerator and denominator by \( n \), the expression becomes \( \frac{1}{1 + \frac{2}{n}} \).
05
Calculate the Limit
As \( n \to \infty \), \( \frac{2}{n} \to 0 \), so the limit of the expression \( \frac{1}{1 + \frac{2}{n}} \) is \( \frac{1}{1} = 1 \). Thus, the sequence converges to 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sequence Formula
A sequence formula is a mathematical expression that defines the rule for finding the terms in a sequence. In our context, the sequence is given by the formula \( a_n = \frac{n}{n+2} \). This formula tells us how each term in the sequence is related to its position \( n \), where \( n \) starts at 1 and continues indefinitely.
To find the first five terms, substitute \( n = 1, 2, 3, 4, 5 \) into the formula. It gives us the sequence:
To find the first five terms, substitute \( n = 1, 2, 3, 4, 5 \) into the formula. It gives us the sequence:
- \( \frac{1}{3} \)
- \( \frac{1}{2} \)
- \( \frac{3}{5} \)
- \( \frac{2}{3} \)
- \( \frac{5}{7} \)
Limit of a Sequence
The limit of a sequence refers to the value that the terms of a sequence approach as the index \( n \) (representing each term's position) goes to infinity. For the sequence \( a_n = \frac{n}{n+2} \), we want to explore what happens as \( n \) becomes very large.
To do this, rewrite the expression \( \frac{n}{n+2} \) by dividing both the numerator and denominator by \( n \), yielding:\[\frac{1}{1 + \frac{2}{n}}\]
As \( n \to \infty \), the term \( \frac{2}{n} \) becomes negligibly small. Thus, the expression simplifies to \( \frac{1}{1} = 1 \).
This shows that the sequence converges to the limit of 1. In simpler terms, the larger \( n \) becomes, the closer each term in the sequence gets to the value 1.
To do this, rewrite the expression \( \frac{n}{n+2} \) by dividing both the numerator and denominator by \( n \), yielding:\[\frac{1}{1 + \frac{2}{n}}\]
As \( n \to \infty \), the term \( \frac{2}{n} \) becomes negligibly small. Thus, the expression simplifies to \( \frac{1}{1} = 1 \).
This shows that the sequence converges to the limit of 1. In simpler terms, the larger \( n \) becomes, the closer each term in the sequence gets to the value 1.
Increasing Sequence
An increasing sequence is a sequence where each successive term is larger than the previous one. Our sequence \( a_n = \frac{n}{n+2} \) demonstrates this characteristic when we observe the progression of terms like \( \frac{1}{3}, \frac{1}{2}, \frac{3}{5}, \frac{2}{3}, \frac{5}{7} \).
To analyze whether this sequence is increasing:
In practical terms, our already computed sequence terms show an evident increase, indicating that \( \frac{n}{n+2} \) is indeed an increasing sequence as \( n \) grows. This property is essential since it assists in predicting the behavior of a sequence (e.g., convergence towards a limit).
To analyze whether this sequence is increasing:
- Calculate the difference between successive terms: \( a_{n+1} - a_n \).
- Check if the difference is positive, which implies an increase.
In practical terms, our already computed sequence terms show an evident increase, indicating that \( \frac{n}{n+2} \) is indeed an increasing sequence as \( n \) grows. This property is essential since it assists in predicting the behavior of a sequence (e.g., convergence towards a limit).