Chapter 9: Problem 5
Use sigma notation to write the Maclaurin series for the function. \(\mathrm{H}\) $$ \ln (1+x) $$
Short Answer
Expert verified
The Maclaurin series for \( \ln(1+x) \) is \( \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n} x^n \).
Step by step solution
01
Understand the Maclaurin Series
A Maclaurin series is a special case of a Taylor series centered at 0. It takes the form: \[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!} x^n \]where \( f^{(n)}(0) \) is the \( n \)-th derivative of \( f(x) \) evaluated at \( x = 0 \).
02
Derive the Function Components for ln(1+x)
We need to find the derivatives of \( \ln(1+x) \) evaluated at \( x=0 \):- \( f(x) = \ln(1+x) \) implies \( f(0) = 0 \).- \( f'(x) = \frac{1}{1+x} \) implies \( f'(0) = 1 \).- \( f''(x) = -\frac{1}{(1+x)^2} \) implies \( f''(0) = -1 \).- Continuing, we find that \( f^{(n)}(0) = (-1)^{n-1}(n-1)! \).
03
Construct the General Term
The general formula derived from the derivatives is:\[ f^{(n)}(0) = (-1)^{n-1}(n-1)! \]So the \( n \)-th term of the series is:\[ \frac{f^{(n)}(0)}{n!} x^n = \frac{(-1)^{n-1}(n-1)!}{n!} x^n = \frac{(-1)^{n-1}}{n} x^n \]
04
Write the Series in Sigma Notation
The series above can be written as:\[ \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n} x^n \]This represents the Maclaurin series for the function \( \ln(1+x) \).
05
Final Step: Verify the Series Representation
Substitute \( x = 0 \) into the series to ensure it converges to 0 as expected for \( \ln(1+0) = 0 \), confirming the function matches the series at this center point.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor series
A Taylor series is a mathematical series that provides a powerful way to represent functions as an infinite sum of terms. Each term in a Taylor series is calculated from the derivatives of the function at a particular point, known as the center. If the function is centered at zero, we call this a Maclaurin series. This makes the study of Taylor series crucial for understanding how different functions can be expressed through infinite series.
A general Taylor series for a function \( f(x) \) centered at a point \( a \) is given by:
A general Taylor series for a function \( f(x) \) centered at a point \( a \) is given by:
- \( f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n \)
power series
A power series is a series in which each term is a multiple of some power of the variable. In its most basic form, a power series looks quite similar to a polynomial, but it can have infinitely many terms. Here's what a general power series centered at zero looks like:
- \( \sum_{n=0}^{\infty} a_n x^n \)
sigma notation
Sigma notation, sometimes called summation notation, is a convenient and compact way to write out long sums. This notation uses the Greek letter sigma (\( \Sigma \)) to denote a series and is prevalent in mathematics when dealing with Taylor series, power series, and similar constructs.
In sigma notation, a series can be expressed as:
For the Maclaurin series presented in your exercise, sigma notation comes in handy to neatly express the infinite series part:
In sigma notation, a series can be expressed as:
- \( \sum_{n=a}^{b} f(n) \)
For the Maclaurin series presented in your exercise, sigma notation comes in handy to neatly express the infinite series part:
- \( \ln(1+x) = \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n} x^n \)