Chapter 9: Problem 4
For each given \(p\) -series, identify \(p\) and determine whether the series converges. (a) \(\sum_{k=1}^{\infty} k^{-4 / 3}\) (b) \(\sum_{k=1}^{\infty} \frac{1}{\sqrt[4]{k}}\) (c) \(\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{k^{5}}}\) (d) \(\sum_{k=1}^{\infty} \frac{1}{k^{\pi}}\)
Short Answer
Expert verified
(a) Converges, (b) Diverges, (c) Converges, (d) Converges.
Step by step solution
01
Identify p for Part (a)
The given series is \( \sum_{k=1}^{\infty} k^{-4/3} \). For a p-series \( \sum_{k=1}^{\infty} \frac{1}{k^p} \), we identify \( p = \frac{4}{3} \).
02
Determine Convergence for Part (a)
For a p-series \( \sum \frac{1}{k^p} \), the series converges if and only if \( p > 1 \). Since \( \frac{4}{3} > 1 \), the series \( \sum_{k=1}^{\infty} k^{-4/3} \) converges.
03
Identify p for Part (b)
The series given is \( \sum_{k=1}^{\infty} \frac{1}{\sqrt[4]{k}} \). We can rewrite it as \( \sum_{k=1}^{\infty} k^{-1/4} \), thus \( p = \frac{1}{4} \).
04
Determine Convergence for Part (b)
Since \( \frac{1}{4} < 1 \), the series \( \sum_{k=1}^{\infty} k^{-1/4} \) diverges.
05
Rewrite and Identify p for Part (c)
The series is \( \sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{k^5}} \). It can be rewritten as \( \sum_{k=1}^{\infty} k^{-5/3} \). Therefore, \( p = \frac{5}{3} \).
06
Determine Convergence for Part (c)
Since \( \frac{5}{3} > 1 \), the series \( \sum_{k=1}^{\infty} k^{-5/3} \) converges.
07
Identify p for Part (d)
In the given series \( \sum_{k=1}^{\infty} \frac{1}{k^{\pi}} \), \( p = \pi \).
08
Determine Convergence for Part (d)
Since \( \pi \approx 3.14159 > 1 \), the series \( \sum_{k=1}^{\infty} \frac{1}{k^{\pi}} \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convergence
In mathematical analysis, convergence refers to the behavior of a series as its number of terms approaches infinity. When a series converges, it means that as we add more and more terms, the total sum approaches a specific value or limit. For p-series, this convergence is determined by the exponent value, \(p\), in the expression \(\sum_{k=1}^{\infty} \frac{1}{k^p}\).
If \(p > 1\), the series converges. This is because the terms become sufficiently small as \(k\) increases, making the overall sum approach a finite number. Examples of convergent series from the original exercise include:
If \(p > 1\), the series converges. This is because the terms become sufficiently small as \(k\) increases, making the overall sum approach a finite number. Examples of convergent series from the original exercise include:
- \(p = \frac{4}{3}\) for series \( \sum_{k=1}^{\infty} k^{-4 / 3} \)
- \(p = \frac{5}{3}\) for series \( \sum_{k=1}^{\infty} k^{-5/3} \)
- \(p = \pi\) for series \( \sum_{k=1}^{\infty} \frac{1}{k^\pi} \)
Divergence
The concept of divergence is important when analyzing series to determine their behavior over an infinite sequence. A series diverges when its terms do not sum up to a finite limit as the number of terms increases. Essentially, if the sum grows without bound or oscillates indefinitely, the series is divergent.
For a p-series, the rule of thumb is that if \(p \leq 1\), the series will diverge. This is because the terms decrease too slowly to create a convergent sum. From the original exercise, an example of a divergent series is:
For a p-series, the rule of thumb is that if \(p \leq 1\), the series will diverge. This is because the terms decrease too slowly to create a convergent sum. From the original exercise, an example of a divergent series is:
- \(p = \frac{1}{4}\) for series \( \sum_{k=1}^{\infty} k^{-1/4} \)
P-series Test
The p-series test is a fundamental tool in calculus to assess the convergence or divergence of series. Specifically used for series of the form \(\sum_{k=1}^{\infty} \frac{1}{k^p}\), the p-series test dictates that:
This straightforward test is crucial because it simplifies the process of evaluating the long-term behavior of infinite series. For instance, the exercise demonstrates this with different p-values, showing both convergence and divergence scenarios.
Properly applying the p-series test allows students to quickly identify whether an infinite sum will settle into a numeric value or not. It's an efficient method for analyzing series without delving into more complex calculations, making it an essential tool for students learning about calculus and series behavior.
- The series converges if \(p > 1\)
- The series diverges if \(p \leq 1\)
This straightforward test is crucial because it simplifies the process of evaluating the long-term behavior of infinite series. For instance, the exercise demonstrates this with different p-values, showing both convergence and divergence scenarios.
Properly applying the p-series test allows students to quickly identify whether an infinite sum will settle into a numeric value or not. It's an efficient method for analyzing series without delving into more complex calculations, making it an essential tool for students learning about calculus and series behavior.