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Write out the first five terms of the sequence, determine whether the sequence converges, and if so find its limit. $$ \left\\{\ln \left(\frac{1}{n}\right)\right\\}_{n=1}^{+\infty} $$

Short Answer

Expert verified
The sequence does not converge; it diverges to \(-\infty\).

Step by step solution

01

Understand the Sequence

The sequence given is \(\{\ln(\frac{1}{n})\}_{n=1}^{+\infty}\). This represents a series of logarithmic terms where \(n\) starts at 1 and increases indefinitely.
02

Calculate the First Five Terms

To find the first five terms, substitute \(n = 1, 2, 3, 4, 5\) into the expression \(\ln(\frac{1}{n})\): - When \(n=1\), the term is \(\ln(\frac{1}{1}) = \ln(1) = 0\).- When \(n=2\), the term is \(\ln(\frac{1}{2}) = \ln(0.5)\).- When \(n=3\), the term is \(\ln(\frac{1}{3}) = \ln(0.333...)\).- When \(n=4\), the term is \(\ln(\frac{1}{4}) = \ln(0.25)\).- When \(n=5\), the term is \(\ln(\frac{1}{5}) = \ln(0.2)\).
03

Analyze Convergence

To determine if the sequence converges, consider the limit of \(\ln(\frac{1}{n})\) as \(n\) approaches infinity. Rewrite \(\ln(\frac{1}{n})\) as \(-\ln(n)\). Observe that as \(n\) increases, \(-\ln(n)\) decreases and approaches \(-\infty\).
04

Determine Limit

Since the sequence \(\ln(\frac{1}{n}) = -\ln(n)\) goes to \(-\infty\) as \(n\) approaches infinity, the sequence does not converge to a finite limit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

logarithmic sequences
A logarithmic sequence involves terms that are logarithms of a particular function of a variable. In our sequence, we are dealing with \( \ln\left( \frac{1}{n} \right) \). Logarithmic functions have unique properties that can influence the behavior of a sequence. For example, when \( n \) is in the denominator, we are effectively saying that as \( n \) increases, the value of the term inside the logarithm decreases. Hence, for each positive integer \( n \), we get a term of the sequence by taking the natural logarithm of the reciprocal of \( n \).
  • When \( n = 1 \), \( \ln(\frac{1}{1}) = \ln(1) = 0 \).
  • As \( n \) increases, the values of \( \ln(\frac{1}{n}) \) become increasingly negative because the reciprocal of \( n \) gets smaller.
Understanding the behavior of the natural logarithm as part of the sequence is crucial for analyzing whether a sequence like this converges and if it does, what the limit might be.
limits
When examining sequences, limits help us understand their behavior as the term number \( n \) approaches infinity. The concept of a limit is crucial when determining convergence. For the logarithmic sequence \( \ln\left( \frac{1}{n} \right) \), we can express it as \( -\ln(n) \).
This helps analyze its limit by observing the behavior of \( \ln(n) \) itself.As \( n \) grows larger, \( \ln(n) \) also increases without a bound, meaning it approaches infinity. Consequently, \( -\ln(n) \) does the opposite: it heads towards \(-\infty\).This outcome tells us that the sequence does not approach a specific finite value, implying that the sequence does not converge.
infinite sequences
An infinite sequence is a sequence that continues indefinitely. We consider the sequence \( \ln\left( \frac{1}{n} \right) \) as \( n \) becomes infinitely large. Understanding the behavior as \( n \rightarrow \infty \) is key.In finite sequences, there is a definite number of terms, whereas in infinite sequences, the list goes on and on.
The given sequence represents a type whose terms get smaller in magnitude, but larger in number, never-ending.This characteristic makes it vital to determine its convergence: does it settle towards a particular number, or does it diverge away endlessly? In this case, since the terms continually decrease towards \(-\infty\), our sequence diverges indefinitely. Utilizing the properties of logarithms and limits aids in thoroughly analyzing how infinite sequences behave.

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