Chapter 8: Problem 35
A scientist wants to determine the half-life of a certain radioactive substance. She determines that in exactly 5 days a \(10.0\) -milligram sample of the substance decays to \(3.5\) milligrams. Based on these data, what is the half-life?
Short Answer
Expert verified
The half-life is approximately 3.3 days.
Step by step solution
01
Understanding the Problem
We have a radioactive substance that decays over time. Initially, there is a 10.0 mg sample, which decays to 3.5 mg in 5 days. The goal is to find out how many days it takes for the substance to reduce to half its initial amount, known as the half-life.
02
Using the Exponential Decay Formula
The formula for exponential decay is given by:\[ A(t) = A_0 e^{-kt} \]where \( A(t) \) is the amount of substance at time \( t \), \( A_0 \) is the initial amount, and \( k \) is the decay constant. In our problem, \( A(5) = 3.5 \) mg and \( A_0 = 10.0 \) mg.
03
Substituting Known Values
Substitute the known values into the exponential decay formula:\[ 3.5 = 10.0 e^{-5k} \]Now, we solve for \( k \).
04
Solving for the Decay Constant \( k \)
First, divide both sides by 10:\[ 0.35 = e^{-5k} \]Take the natural logarithm of both sides:\[ \ln 0.35 = -5k \]Solve for \( k \):\[ k = -\frac{\ln 0.35}{5} \]
05
Calculating \( k \)
Calculate \( k \) using the natural logarithm:\[ k = -\frac{-1.0498}{5} \]\[ k \approx 0.20996 \]
06
Finding the Half-Life Formula
The half-life \( t_{1/2} \) can be found using the formula:\[ t_{1/2} = \frac{\ln 2}{k} \]
07
Calculating the Half-Life
Substitute \( k \) into the half-life formula:\[ t_{1/2} = \frac{\ln 2}{0.20996} \]\[ t_{1/2} \approx 3.301 \]
08
Conclusion
The half-life of the substance is approximately 3.3 days.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Life Calculation
When discussing radioactive decay, one frequently encounters the concept of "half-life." Half-life is the time it takes for a substance to decrease to half its initial amount. Consider it as a clock that counts down to half the original sample size. To calculate the half-life of a substance, you first need the decay constant, a value integral to determining how quickly the substance decays.
In the given problem, we determined the decay constant, and with this, the half-life was calculated. You can use the formula:
In the given problem, we determined the decay constant, and with this, the half-life was calculated. You can use the formula:
- Half-life formula: \( t_{1/2} = \frac{\ln 2}{k} \)
Decay Constant
The decay constant, \( k \), is a critical value in understanding radioactive decay. This constant describes the rate at which a radioactive substance decays. In simpler terms, it tells you how quickly you can expect a substance to decrease over time.
To find \( k \), you often need to rearrange the exponential decay formula:
To find \( k \), you often need to rearrange the exponential decay formula:
- Start with the formula: \( A(t) = A_0 e^{-kt} \)
- Plug in the known values for \( A(t) \), \( A_0 \), and \( t \).
- Example: \( 3.5 = 10 e^{-5k} \)
- Divide to simplify, then take the natural logarithm: \( \ln(0.35) = -5k \)
- Solve for \( k \): \( k = -\frac{\ln(0.35)}{5} \)
Radioactive Decay Formula
At the heart of this problem is the radioactive decay formula, which models how a substance decreases over time. The standard formula in use is the exponential decay formula:
- \( A(t) = A_0 e^{-kt} \)
- \( A(t) \): the amount remaining after time \( t \)
- \( A_0 \): the initial quantity of the substance
- \( e \): the base of the natural logarithm, approximately 2.71828
- \( k \): the decay constant