/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Confirm that \(y=3 e^{x^{3}}\) i... [FREE SOLUTION] | 91Ó°ÊÓ

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Confirm that \(y=3 e^{x^{3}}\) is a solution of the initial-value problem \(y^{\prime}=3 x^{2} y, y(0)=3\).

Short Answer

Expert verified
Yes, it satisfies both the differential equation and initial condition.

Step by step solution

01

Differentiate the Given Function

Given the function, \(y = 3e^{x^3}\), differentiate it with respect to \(x\). Using the chain rule: \(\frac{d}{dx}[e^{x^3}] = e^{x^3} \cdot 3x^2\). Thus, \(y' = 3 \cdot e^{x^3} \cdot 3x^2 = 9x^2 e^{x^3}\). Hence, \(y' = 3x^2 \cdot 3e^{x^3} = 3x^2 \cdot y\).
02

Verify the Initial Condition

Substitute \(x = 0\) into the original function \(y = 3e^{x^3}\) to verify the initial condition: \(y(0) = 3e^{0^3} = 3e^0 = 3\). Thus, the initial condition \(y(0) = 3\) holds true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
A differential equation involves a function and its derivatives, representing how the function changes. Understanding them is essential because many real-world systems are modeled using these equations. In this exercise, the differential equation given is \[ y' = 3x^2 y \].This equation is a first-order differential equation because it involves the first derivative of the function, denoted as \( y' \). The goal is to find a function \( y \) that satisfies this relationship. In our problem, the function \( y = 3 e^{x^3} \), when substituted, holds true to the given differential equation. The idea here is to interpret how change in \( x \) affects \( y \) according to the formula represented by the differential equation.
Chain Rule Differentiation
Chain rule is a fundamental concept in differentiation, especially useful when dealing with composite functions. In simpler terms, if a function is nested inside another, the chain rule helps you differentiate it. For instance, in this exercise, the inner function is \( x^3 \) and the outer function is \( e^u \), where \( u = x^3 \). The derivative of \( e^{x^3} \) with respect to \( x \) is found using the chain rule: first, differentiate \( e^u \) with respect to \( u \), which is \( e^u \), and then multiply by the derivative of \( u \) with respect to \( x \), which is \( 3x^2 \). This gives us \( y' = 9x^2 e^{x^3} \). Understanding the chain rule allows you to take derivatives of more complex functions smoothly.
Verification of Solutions
Verifying a solution to a differential equation involves checking if the proposed function satisfies both the differential equation and any initial conditions. In this problem, verification occurs in two steps:
  • First, show that when \( y = 3e^{x^3} \) is differentiated, it satisfies the differential equation given as \( y' = 3x^2 y \). As shown in the solution, this condition is satisfied with \( y' = 9x^2 e^{x^3} \).
  • Second, check the initial condition \( y(0) = 3 \). By substituting \( x = 0 \) into \( y \), we get \( y(0) = 3e^{0^3} = 3 \), confirming the initial condition.
By fulfilling both these criteria, \( y = 3e^{x^3} \) is verified as a valid solution to the initial-value problem given the criteria specified in the problem. This process ensures that the solution is not just mathematically consistent but also appropriately initialized.

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Most popular questions from this chapter

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