Chapter 7: Problem 48
(a) Make an appropriate \(u\) -substitution, and then use the Endpaper Integral Table to evaluate the integral. (b) If you have a CAS, use it to evaluate the integral (no substitution), and then confirm that the result is equivalent to that in part (a). $$ \int x \ln \left(2+x^{2}\right) d x $$
Short Answer
Expert verified
The integral is \( \frac{1}{2} \left( (2+x^2) \ln(2+x^2) - (2+x^2) \right) + C \).
Step by step solution
01
Choose the substitution
Identify a suitable function for substitution. Set \( u = 2 + x^2 \), which simplifies the integral.
02
Differentiate u
Compute the derivative of \( u \) with respect to \( x \). This gives \( \frac{du}{dx} = 2x \). Solve for \( dx \) to substitute later: \( dx = \frac{du}{2x} \).
03
Substitute into the integral
Replace variables in the integral using the substitutions: \( \int x \ln(u) \cdot \frac{du}{2x} \). This simplifies to \( \frac{1}{2} \int \ln(u) \, du \).
04
Integrate with respect to u
Use the Endpaper Integral Table to find \( \int \ln(u) \, du = u \ln(u) - u + C \). Thus, our integral becomes \( \frac{1}{2} \left( u \ln(u) - u \right) + C \).
05
Substitute back for x
Replace \( u \) with the expression \( 2 + x^2 \) to revert to the original variable: \( \frac{1}{2} \left( (2+x^2) \ln(2+x^2) - (2+x^2) \right) + C \).
06
Verify with CAS
Use a Computer Algebra System (CAS) to evaluate the integral directly: \( \int x \ln(2 + x^2) \, dx = \frac{1}{2} \left( (2+x^2) \ln(2+x^2) - (2+x^2) \right) + C \).
07
Confirm equivalence
Ensure that the result from the CAS matches the expression obtained through substitution, confirming the solution is consistent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
u-substitution
The "u-substitution" method is a powerful technique in integral calculus to simplify integrals for easier evaluation. It involves changing the variable of integration to transform a complex integral into a simpler form.
This technique is often useful when dealing with composite functions, such as functions of functions.Here's how it works:
This technique is often useful when dealing with composite functions, such as functions of functions.Here's how it works:
- Identify a substitution: Choose a part of the integrand to replace with a new variable, typically denoted as \( u \).
- Differentiate the substitution: Differentiate \( u \) with respect to the variable of integration (usually \( x \)) to find \( \frac{du}{dx} \).
- Rewrite the integral: Replace all occurrences of the expressions in the original integral with the new variable \( u \) and \( du \).
- Integrate: Solve the new, usually simpler, integral with respect to \( u \).
- Back-substitute: Return to the original variable by replacing \( u \) with the corresponding expression in terms of \( x \).
integral calculus
Integral calculus is the study of integrals and their properties. The integral of a function represents the accumulation of quantities and can be seen as the area under a curve.There are two main types of integrals:
- Definite integrals: These have limits of integration and yield a numeric result representing the net area under the curve.
- Indefinite integrals: These do not have limits of integration and represent a family of functions, including a constant \( C \), since integration is the reverse process of differentiation.
computer algebra system (CAS)
A Computer Algebra System (CAS) is a software tool that facilitates symbolic mathematics, allowing users to perform complex algebraic tasks with ease.CAS can be a powerful aid in verifying solutions to intricate calculus problems:
- Automated calculations: These systems can handle complicated manipulations swiftly and accurately, even those that might be prone to human error.
- Symbolic manipulations: Unlike numerical calculators, CAS can solve equations symbolically, displaying exact expressions instead of decimal approximations.
- Verification tool: In educational settings, it serves as a "second pair of eyes" ensuring that manual computations are correct, as demonstrated in the given exercise.