Chapter 7: Problem 41
Express the improper integral as a limit, and then evaluate that limit with a CAS. Confirm the answer by evaluating the integral directly with the CAS. $$ \int_{0}^{+\infty} e^{-x} \cos x d x $$
Short Answer
Expert verified
The integral evaluates to \( \frac{1}{2} \).
Step by step solution
01
Express the Integral as a Limit
The given integral is improper because it has an infinite upper limit. To express it as a limit, we rewrite the integral with a finite upper boundary, say \( b \), and take the limit as \( b \) approaches infinity:\[\lim_{{b \to \infty}} \int_{0}^{b} e^{-x} \cos x \, dx.\]
02
Evaluate the Integral
To evaluate \( \int_{0}^{b} e^{-x} \cos x \, dx \), we use integration by parts. Let \( u = \cos x \) and \( dv = e^{-x} dx \). Then, \( du = -\sin x \, dx \) and \( v = -e^{-x} \). Integration by parts gives:\[\int e^{-x} \cos x \, dx = -e^{-x} \cos x + \int e^{-x} \sin x \, dx.\]Repeat the integration by parts on \( \int e^{-x} \sin x \, dx \) to end up with an expression that includes \( \int e^{-x} \cos x \, dx \). Solve algebraically to express \( \int e^{-x} \cos x \, dx \) completely.
03
Substitute and Solve for the Limit
Upon evaluating the integral, we find:\[\int e^{-x} \cos x \, dx = \frac{-e^{-x}(\cos x + \sin x)}{2} + C.\]Substituting the limits from 0 to \( b \), we have:\[\left[ \frac{-e^{-x}(\cos x + \sin x)}{2} \right]_{0}^{b} = \left.\frac{-e^{-b}(\cos b + \sin b)}{2}\right|_{b=0}^{b=b}\]\[+ \frac{1}{2}(\cos 0 + \sin 0) = \frac{1}{2}.\]Take the limit as \( b \to \infty \), noting that \( e^{-b} \to 0 \), so the limit reduces to \( \frac{1}{2} \).
04
Confirm by Evaluating the Integral Directly
Using a CAS (Computer Algebra System), input \( \int_{0}^{\infty} e^{-x} \cos x \, dx \). The CAS should also simplify this integral to \( \frac{1}{2} \), confirming our manual calculation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration by Parts
"Integration by parts" is a useful technique for solving integrals of products of functions. It's like a product rule in reverse. The formula for integration by parts is:\[\int u \, dv = uv - \int v \, du\]This means we choose parts of the integrand to be \( u \) and \( dv \). Then, we differentiate \( u \) to find \( du \), and integrate \( dv \) to find \( v \).
- Choose \( u \) and \( dv \): Begin by selecting parts of the function such as \( u = \cos x \) and \( dv = e^{-x} \, dx \).
- Find \( du \) and \( v \): Differentiate \( u \), giving \( du = -\sin x \, dx \), and integrate \( dv \) to get \( v = -e^{-x} \).
- Apply the formula: Plug these into the integration by parts formula, and simplify.
Limit of a Function
The concept of the "limit of a function" is used to describe the behavior of a function as its input approaches a certain value. In the context of improper integrals, limits play a crucial role in handling infinite borders. For instance, when we encounter an integral like\[\int_{0}^{\infty} e^{-x} \cos x \, dx,\]we don't compute infinity directly. Instead, we first calculate the integral up to a finite point, say \( b \), and then observe what happens as \( b \) goes to infinity:\[\lim_{{b \to \infty}} \int_{0}^{b} e^{-x} \cos x \, dx.\]This transforms the improper integral into a problem of finding a limit.Employing limits ensures that we consider the behavior of functions over possibly unbounded domains without attempting to plug-in undefined values such as infinity. Thus, by taking the limit of our expression, we make sure all parts of the function's behavior are accurately captured.
Computer Algebra System (CAS)
A "Computer Algebra System (CAS)" is a software tool used to symbolically compute mathematical problems. These systems can solve equations, perform algebraic manipulations, and evaluate integrals, among other tasks.
- Accuracy and Efficiency: CAS helps in checking the manual calculations, ensuring they are accurate and efficiently solved.
- Symbolic Computation: CAS can handle symbolic mathematics, meaning it manipulates mathematical expressions in their formulaic form, rather than converting everything to numbers immediately.
- Verification: Using a CAS, we can verify our results from manual calculations. For instance, we'd type in \( \int_{0}^{\infty} e^{-x} \cos x \, dx \) to verify that it simplifies to \( \frac{1}{2} \).