Chapter 7: Problem 19
Evaluate the integral. $$ \int e^{x} \sqrt{1-e^{2 x}} d x $$
Short Answer
Expert verified
\( \int e^{x} \sqrt{1-e^{2x}} \, dx = \frac{1}{2} \sin^{-1}(e^x) + \frac{1}{2} e^x \sqrt{1-e^{2x}} + C \).
Step by step solution
01
Identify the Substitution
To solve the integral \( \int e^{x} \sqrt{1-e^{2x}} \, dx \), we shall use the substitution method. Recognize the expression inside the square root, \( 1 - e^{2x} \), which suggests a suitable substitution letting the inside be a trigonometric identity. Set \( u = e^x \), so \( du = e^x \, dx \).
02
Rewrite the Integral in Terms of u
Substitute \( u = e^x \), \( du = e^x \, dx \) into the integral, replacing \( e^x \, dx \) with \( du \). This transforms the integral: \( \int e^{x} \sqrt{1-e^{2x}} \, dx \) becomes \( \int \sqrt{1-u^2} \, du \).
03
Solve the Integral \( \int \sqrt{1-u^2} \, du \)
The integral \( \int \sqrt{1-u^2} \, du \) is typically solved using trigonometric substitution. Let \( u = \sin \theta \), then \( du = \cos \theta \, d\theta \), and the integral becomes \( \int \sqrt{1 - \sin^2 \theta} \, \cos \theta \, d\theta \). The expression under the square root simplifies as \( \cos^2 \theta \), so the integral becomes \( \int \cos^2 \theta \, d\theta \).
04
Solve \( \int \cos^2 \theta \, d\theta \)
Use the double angle formula, \( \cos^2 \theta = \frac{1 + \cos(2\theta)}{2} \), to rewrite the integral: \( \int \frac{1 + \cos(2\theta)}{2} \, d\theta \). Separate it into two integrals: \( \frac{1}{2} \int 1 \, d\theta + \frac{1}{2} \int \cos(2\theta) \, d\theta \). These integrals evaluate to \( \frac{1}{2} \theta + \frac{1}{4} \sin(2\theta) + C \).
05
Back-Substitute \( \theta \rightarrow x \)
Recall the substitution \( u = \sin \theta \), so \( \theta = \sin^{-1}(u) \) and \( u = e^x \). Substitute back to obtain the expression in terms of \( x \): \( \frac{1}{2} \sin^{-1}(e^x) + \frac{1}{4} \sin(2\sin^{-1}(e^x)) + C \).
06
Simplify the Expression
The expression can be further simplified using the identity \( \sin(2\theta) = 2\sin\theta\cos\theta \). Thus, \( \sin(2\sin^{-1}(e^x)) = 2e^x\sqrt{1-(e^x)^2} \), achieving the final simplified form: \( \frac{1}{2} \sin^{-1}(e^x) + \frac{1}{2} e^x \sqrt{1-e^{2x}} + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
When dealing with integrals involving composite functions, substitution is a powerful technique. It simplifies integration by setting a new variable to make the integral more manageable. In the problem \( \int e^{x} \sqrt{1-e^{2x}} \, dx \), the integrand includes the expression \( 1 - e^{2x} \). This suggests that setting \( u = e^x \) could simplify our work. Therefore, \( du = e^x \, dx \), allowing us to replace \( e^x \, dx \) in our integral with \( du \). By making this substitution, you essentially replace a complex expression with a simpler variable, \( u \), making it easier to integrate. This step-by-step replacement process is fundamental in reducing calculative workload and navigating through the initial complexity of the integrand with ease.
Trigonometric Substitution
Once the integral \( \int \sqrt{1-u^2} \, du \) is achieved, a new technique called trigonometric substitution is applied. This method is especially useful when dealing with expressions under a square root resembling the Pythagorean identity. The identity \( 1 = \sin^2\theta + \cos^2\theta \) suggests a substitution such as \( u = \sin \theta \), which implies \( du = \cos \theta \, d\theta \). Applying this to the integral \( \int \sqrt{1 - \sin^2 \theta} \, \cos \theta \, d\theta \), you simplify \( \sqrt{1 - \sin^2 \theta} \) to \( \cos \theta \). This simplification exploits the Pythagorean identity, transforming the integral into an easier form, \( \int \cos^2 \theta \, d\theta \). Trigonometric substitution is critical here, transforming complex algebraic forms into simpler trigonometric integrals.
Double Angle Formulas
The integral \( \int \cos^2 \theta \, d\theta \) can be resolved using another trigonometric tool – the double angle formula. By applying \( \cos^2 \theta = \frac{1 + \cos(2\theta)}{2} \), the integral splits into two separate, simpler integrals: \( \frac{1}{2} \int 1 \, d\theta + \frac{1}{2} \int \cos(2\theta) \, d\theta \). These integrals are straightforward to solve. The first integral evaluates to \( \frac{1}{2}\theta \), while the second becomes \( \frac{1}{4}\sin(2\theta) \) after integrating by recognizing the derivative. Combining these results gives you a solution in terms of \( \theta \). This formula not only simplifies calculations but also allows the bridging back to the original variable, resulting in the final expression in \( x \). Double angle formulas are invaluable in managing trig functions that otherwise complicate the integration process.