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Evaluate the integrals by making appropriate \(u\) -substitutions and applying the formulas reviewed in this section. $$ \int(x+1) \cot \left(x^{2}+2 x\right) d x $$

Short Answer

Expert verified
\( \frac{1}{2} \ln |\sin(x^2 + 2x)| + C \)."

Step by step solution

01

Identify the Substitution

First, identify the part of the integrand that can be substituted with a single variable. Here, we choose to let \( u = x^2 + 2x \). This is because the derivative of \( u \) will simplify part of the integrand.
02

Differentiate the Substitution

Differentiate \( u \) with respect to \( x \) to find \( du \). The derivative of \( u = x^2 + 2x \) is \( du = (2x + 2)dx \).
03

Solve for dx

We can rearrange the equation from Step 2 to express \( dx \) in terms of \( du \). Doing so, we have \( dx = \frac{du}{2x + 2} \).
04

Substitute in the Integral

Replace \( x^2 + 2x \) with \( u \), and \( dx \) with \( \frac{du}{2x + 2} \) in the integral. So, the integral becomes \( \int (x+1) \cot(u) \frac{du}{2(x+1)} \).
05

Simplify the Integral

Notice that \( x+1 \) cancels out from the numerator and the denominator, simplifying the integral to \( \frac{1}{2} \int \cot(u) \, du \).
06

Integrate with Respect to u

Recall from trigonometric identities that \( \int \cot(u) \, du = \ln |\sin(u)| + C \). Therefore, evaluating the integral gives \( \frac{1}{2} \ln |\sin(u)| + C \).
07

Substitute Back u

Replace \( u \) with the original expression \( x^2 + 2x \) to return to the variable \( x \). The solution is \( \frac{1}{2} \ln |\sin(x^2 + 2x)| + C \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

u-substitution
U-substitution is a helpful method in integral calculus, particularly when dealing with complex integrals where direct integration is challenging. The goal is to transform the integral into a simpler form by introducing a new variable, commonly denoted as \( u \).
To begin, identify a part of the integrand that can be substituted. Ideally, this is a portion whose derivative appears elsewhere in the integrand. In our example, we let \( u = x^2 + 2x \). This expression is chosen because its derivative, \( du = (2x + 2)dx \), matches a portion of the integrand.
Once \( u \) is identified, differentiate it to find \( du \). Then, solve for \( dx \) in terms of \( du \). Change the variable in the integral from \( x \) to \( u \), simplifying the integral and making it easier to solve.
Keep in mind that after integrating with respect to \( u \), you must substitute back the original \( x \) terms to complete the solution. This step ensures the final answer is expressed in terms of the original variable.
trigonometric integrals
Trigonometric integrals involve the integration of functions that include trigonometric functions like sine, cosine, tangent, and cotangent.
In our example, we encounter an integral involving \( \cot(u) \), which is a trigonometric function. For integrals of this type, it is essential to remember the trigonometric identities and formulas that relate to these functions. Specifically, the integral \( \int \cot(u) \, du \) is a standard result that yields \( \ln |\sin(u)| + C \), where \( C \) represents the constant of integration.
Understanding these identities allows us to integrate functions safely and accurately, converting a potentially complex problem into a much simpler one. Mastering these transformations is part of achieving proficiency in handling trigonometric integrals.
integration techniques
Integration techniques are a set of methods used to solve integrals that cannot be directly integrated using basic formulas. U-substitution is just one example of these techniques, helping simplify complex integrals.
Other methods include integration by parts, partial fraction decomposition, and trigonometric substitution, each suited to different types of integrals. The choice of technique depends on the form of the integrand. For instance:
  • **Integration by parts** is useful for products of functions, utilizing the formula \( \int u \, dv = uv - \int v \, du \).
  • **Partial fraction decomposition** is employed for rational functions, breaking them into simpler fractions.
  • **Trigonometric substitution** replaces variable expressions with trigonometric functions, often used for integrands involving square roots.
Proficiency in integration requires familiarity with these techniques, their appropriate use, and practice to implement them effectively when evaluating complex integrals.

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Most popular questions from this chapter

Find the arc length of the curve \(y=\ln (\cos x)\) over the interval \([0, \pi / 4]\).

(a) Make \(u\) -substitution (5) to convert the integrand to a rational function of \(u\), and then evaluate the integral. (b) If you have a CAS, use it to evaluate the integral (no substitution), and then confirm that the result is equivalent to that in part (a). $$ \int \frac{\sin x}{\sin x+\tan x} d x $$

Evaluate the integral. $$ \int_{0}^{\pi / 2} \tan ^{5} \frac{x}{2} d x $$

A transform is a formula that converts or "transforms" one function into another. Transforms are used in applications to convert a difficult problem into an easier problem whose solution can then be used to solve the original difficult problem. The Laplace transform of a function \(f(t)\), which plays an important role in the study of differential equations, is denoted by \(\mathscr{L}\\{f(t)\\}\) and is defined by $$\mathscr{L}\\{f(t)\\}=\int_{0}^{+\infty} e^{-s t} f(t) d t$$ In this formula \(s\) is treated as a constant in the integration process; thus, the Laplace transform has the effect of transforming \(f(t)\) into a function of \(s .\) Use this formula in these exercises. In each part, find the Laplace transform. (a) \(f(t)=t, s>0\) (b) \(f(t)=t^{2}, s>0\) (c) \(f(t)=\left\\{\begin{array}{ll}0, & t<3 \\ 1, & t \geq 3\end{array}, s>0\right.\)

Determine whether the statement is true or false. Explain your answer. The Simpson's rule approximation \(S_{50}\) for \(\int_{a}^{b} f(x) d x\) is a weighted average of the approximations \(M_{50}\) and \(T_{50}\), where \(M_{50}\) is given twice the weight of \(T_{50}\) in the average.

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