Chapter 7: Problem 1
Evaluate the integrals by making appropriate \(u\) -substitutions and applying the formulas reviewed in this section. $$ \int(4-2 x)^{3} d x $$
Short Answer
Expert verified
The integral evaluates to \( -\frac{1}{8} (4 - 2x)^4 + C \).
Step by step solution
01
Choose a substitution for u
To simplify the integral, we can make a substitution. Let \( u = 4 - 2x \). This choice simplifies the integrand into a function of \(u\). By differentiating, we find \( \frac{du}{dx} = -2 \).
02
Express dx in terms of du
Rearrange the derivative \( \frac{du}{dx} = -2 \) to express \( dx \) in terms of \( du \). Therefore, \( dx = -\frac{1}{2} du \).
03
Substitute back into the integral
Now rewrite the original integral in terms of \( u \). The integral \( \int (4-2x)^3 \, dx \) becomes \( \int u^3 (-\frac{1}{2}) \, du \) or \( -\frac{1}{2} \int u^3 \, du \).
04
Integrate with respect to u
Use the power rule for integration to solve \( \int u^3 \, du \). The result is \( \frac{u^4}{4} \), so the integral becomes \( -\frac{1}{2} \times \frac{u^4}{4} + C \), simplifying to \( -\frac{1}{8} u^4 + C \).
05
Substitute back in terms of x
Replace \( u \) by \( 4 - 2x \) to return to the original variable. Thus, the integral is \( -\frac{1}{8} (4 - 2x)^4 + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding U-substitution
U-substitution is a powerful technique used in integration to simplify complex integrals. It is commonly referred to as `u-substitution` because you typically substitute parts of the integrand with a new variable, usually denoted as \( u \). This makes the integral easier to handle.
### The Process of U-substitution
By mastering this process, you can solve integrals that would otherwise be difficult or complicated.
### The Process of U-substitution
- **Selection of \( u \):** The first step is to choose a part of the integrand to replace with \( u \). Ideally, choose a section that will simplify the integral significantly.
- **Finding \( du \):** Next, differentiate \( u \) with respect to \( x \) to obtain \( \frac{du}{dx} \). This step is crucial as it helps to transform the original differential \( dx \) into terms of \( du \).
- **Rewriting the Integral:** Substitute both \( u \) and \( du \) into the original integral, transforming it into an expression entirely in terms of \( u \).
- **Integration:** Carry out the integration with respect to \( u \).
- **Re-substitution:** Finally, replace \( u \) with your original terms to revert back to the variable \( x \).
By mastering this process, you can solve integrals that would otherwise be difficult or complicated.
Definite and Indefinite Integrals
In calculus, integrals can be classified into two main types: `definite` and `indefinite integrals`. Understanding the difference between these is key in determining the kind of solution you need.
### Indefinite IntegralsIndefinite integrals represent a family of functions and are expressions with no limits of integration. They include an arbitrary constant of integration, \( C \), as they represent a collection of possible antiderivatives of a function.
### Definite IntegralsDefinite integrals, on the other hand, compute a number representing the area under a curve within a set range \([a, b]\).
Both types of integrals are essential and often used in calculus problems and real-life applications such as physics and engineering.
### Indefinite IntegralsIndefinite integrals represent a family of functions and are expressions with no limits of integration. They include an arbitrary constant of integration, \( C \), as they represent a collection of possible antiderivatives of a function.
- Expresses general form: \( \int f(x) \, dx = F(x) + C \).
- Used to find the most general form of a function whose derivative matches a given function.
### Definite IntegralsDefinite integrals, on the other hand, compute a number representing the area under a curve within a set range \([a, b]\).
- Has limits: \( \int_{a}^{b} f(x) \, dx \).
- Output is a numeric value representing the net area.
- Does not include a constant \( C \), unless it’s the evaluation of an indefinite integral before limits are applied.
Both types of integrals are essential and often used in calculus problems and real-life applications such as physics and engineering.
Basic Calculus Integration Techniques
In calculus, integration can be approached using a variety of methods. Each technique is suited to different types of functions and often requires practice to identify when and how to apply them. One such key technique is `u-substitution`.
### Common Integration Techniques:
### Applying the Techniques:Understanding the nature of the function you're dealing with will dictate the technique you should use. Practice is essential to become efficient in recognizing the right approach. U-substitution is often the go-to for integrated expressions involving composition of functions, proving its utility in simplifying complex integrals.
### Common Integration Techniques:
- **Power Rule:** Used for finding the antiderivative of power functions. If \( f(x) = x^n \), the integral is \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), for \( n eq -1 \).
- **Substitution (Change of Variables):** As discussed, this is used when an integral can be simplified by substituting part of the integrand.
- **Integration by Parts:** Useful for products of two functions, following the formula \( \int u \, dv = uv - \int v \, du \).
- **Partial Fraction Decomposition:** Decomposes a complex rational function into simpler fractions for easier integration.
### Applying the Techniques:Understanding the nature of the function you're dealing with will dictate the technique you should use. Practice is essential to become efficient in recognizing the right approach. U-substitution is often the go-to for integrated expressions involving composition of functions, proving its utility in simplifying complex integrals.