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True-False Determine whether the statement is true or false. Explain your answer. [In these exercises, assume that a solid \(S\) of volume \(V\) is bounded by two parallel planes perpendicular to the \(x\) -axis at \(x=a\) and \(x=b\) and that for each \(x\) in \([a, b], A(x)\) denotes the cross-sectional area of \(S\) perpendicular to the \(x\) -axis.] If each cross section of \(S\) is a disk or a washer, then \(S\) is a solid of revolution.

Short Answer

Expert verified
True: The solid is a solid of revolution if each cross-section is a disk or washer.

Step by step solution

01

Understanding the Statement

The problem states that we have a solid \(S\) with cross-sections that are disks or washers. The question asks whether such a solid is necessarily a solid of revolution.
02

Defining Solids of Revolution

A solid of revolution is formed by rotating a two-dimensional shape about an axis. It generally involves a function rotated around an axis, creating circular cross-sections (disks or washers) perpendicular to that axis.
03

Analyzing the Given Solid

The solid \(S\) has cross-sections that are disks or washers parallel to the x-axis. This means that each slice of the solid perpendicular to the x-axis is circular, mimicking the appearance of a solid formed by rotation.
04

Connecting Cross Sections to Solid of Revolution

For \(S\) to be a solid of revolution, it must be possible to describe it as the result of rotating a two-dimensional area around an axis. If each cross-section is a disk or washer, then it suggests the solid could indeed be described by such a rotation.
05

Determining the Truth Value

Given that each slice perpendicular to the x-axis must be circular or ring-shaped, it follows that the entire solid could be reconstructed by rotating a generating curve or surface around an axis. Therefore, \(S\) conforms to the definition of a solid of revolution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross-Sectional Area
The concept of cross-sectional area is key when dealing with solids, especially in calculus when calculating volumes. A cross-sectional area is essentially the area of a particular slice of a three-dimensional object, perpendicular to an axis. This slice is usually shaped like a simple two-dimensional figure: it can be a circle, as in the case of a disk, or an annular ring, like a washer.

Imagine slicing through a loaf of bread. Each slice represents a cross-section. In the context of solids bounded by two parallel planes, we often examine these slices perpendicular to the x-axis. The variable function, represented as \(A(x)\), defines the area of the cross-section at any given point \(x\) across the specified range \([a, b]\).
  • Understanding cross-sectional areas helps visualize and solve problems involving volumes of more complex shapes.
  • The slices provide insight into the shape of the entire solid, one thin slice at a time.
  • The area function \(A(x)\) is crucial in determining total volume when integrating from \(x = a\) to \(x = b\).
Disk and Washer Method
The disk and washer methods are integral tools used for finding the volume of a solid of revolution. These methods simplify the calculation by breaking down the complex 3D solid into manageable 2D pieces, which can then be summed up using integration.

### Disk MethodThis approach is used when the solid is formed from disks. When a shape is revolved fully around an axis, each thin slice represents a disk perpendicular to that axis.
  • The disk has a radius equivalent to that part of the function graph that extends to the axis of rotation.
  • By integrating the area of these disks across the entire range, you can determine the volume of the solid.
The volume formula for one disk with a radius \(r(x)\) is: \[V = \int_a^b \pi [r(x)]^2 \, dx\]
### Washer MethodThe washer method is applicable when there is a hollow section in the middle, forming a washer rather than a complete disk.
  • A washer has two radii: an outer radius \(R(x)\) and an inner radius \(r(x)\).
  • The volume of these washers can be calculated similarly by integrating across the range.
The formula for the volume of a washer is given by: \[V = \int_a^b \pi( [R(x)]^2 - [r(x)]^2 ) \, dx\]
Volume of Solids
Calculating the volume of a solid revolves around the idea of summing up an infinite number of infinitesimally thin slices. Whether we're dealing with disks, washers, or a hybrid of the two, the principle remains consistent: integrate the area of each slice across the solid's length.

When approaching problems involving volumes, it's crucial to:
  • Identify the shape and nature of each cross-section—disk, washer, or otherwise.
  • Set up the correct integral bounds—these will be the limits, \(a\) and \(b\), over which to integrate to cover the entire volume.
  • Use the appropriate formula based on the cross-sectional type to compute the volume.
This method ensures that you capture the volume accurately by taking into account the sum of the areas of all individual cross-sections. By meticulously integrating these areas, you obtain the volume of even the most complex solids of revolution.

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