Chapter 6: Problem 21
Use a CAS to find the volume of the solid generated when the region enclosed by \(y=e^{x}\) and \(y=0\) for \(1 \leq x \leq 2\) is revolved about the \(y\) -axis.
Short Answer
Expert verified
The volume is \( 2\pi (e^2 - e) \) cubic units.
Step by step solution
01
Understand the Problem
We need to find the volume of the solid generated by revolving the region under the curve \( y = e^x \) from \( x = 1 \) to \( x = 2 \) about the \( y \)-axis. The integral to calculate this volume uses the method of cylindrical shells.
02
Use the Shell Method Formula
The volume \( V \) for revolving around the \( y \)-axis using the shell method is given by the integral formula: \[ V = 2\pi \int_{a}^{b} x \, f(x) \, dx \] where \( f(x) = e^x \), \( a = 1 \), and \( b = 2 \).
03
Set Up the Integral
Plug \( f(x) = e^x \) into the shell method formula: \[ V = 2\pi \int_{1}^{2} x \, e^x \, dx \]
04
Integrate the Expression
Calculate the integral \[ \int x \, e^x \, dx \] using integration by parts. Let \( u = x \) and \( dv = e^x \, dx \), then \( du = dx \) and \( v = e^x \). Thus, the integral becomes:\[ \int x \, e^x \, dx = x \, e^x - \int e^x \, dx = x \, e^x - e^x + C \] Therefore, \[ \int_{1}^{2} x \, e^x \, dx = \left[ x \, e^x - e^x \right]_{1}^{2} \]
05
Evaluate the Integral
Substitute the bounds into the evaluated integral:\[ \left[ x \, e^x - e^x \right]_{1}^{2} = \left(2e^2 - e^2\right) - \left(1e^1 - e^1\right) \]\[ = e^2 - (1 - 1) = e^2 - 0 \]Thus, the integral is \( e^2 - e \).
06
Calculate Total Volume
Substitute back into the volume formula:\[ V = 2\pi \int_{1}^{2} x \, e^x \, dx = 2\pi (e^2 - e) \]
07
Final Answer for the Volume
The volume \( V \) of the solid generated is \[ 2\pi (e^2 - e) \] cubic units.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cylindrical Shells Method
The Cylindrical Shells Method is a powerful technique used to find the volume of a solid of revolution. This is particularly useful when revolving a region around a vertical line, such as the y-axis. To intuitively understand this method, imagine peeling an onion: each thin layer you remove represents a cylindrical shell. By adding the volumes of these shells, you get the total volume of the solid.
The key formula for finding the volume when revolving around the y-axis is:
The key formula for finding the volume when revolving around the y-axis is:
- \( V = 2\pi \int_{a}^{b} x \cdot f(x) \, dx \)
- Think of each slice as a wrapper around the y-axis, stretching from \( x = 1 \) to \( x = 2 \).
- Multiply the results by \( 2\pi \) to account for the circular nature of the revolution.
Integration by Parts
Integration by Parts is a vital technique in calculus for integrating products of functions. The formula is derived from the product rule for differentiation and provides a way to transform difficult integrals into simpler ones.
The integration by parts formula is:
Ultimately, the integration simplifies to \( x \, e^x - e^x + C \). Evaluating this from 1 to 2, it becomes \( \left[ x \, e^x - e^x \right]_{1}^{2} \), providing the definite result needed for finding the volume. This method allowed us to effectively handle the complexities arising from products of functions.
The integration by parts formula is:
- \( \int u \, dv = uv - \int v \, du \)
- Choose \( u = x \), which simplifies to \( du = dx \).
- Select \( dv = e^x \, dx \), giving \( v = e^x \) after integration.
- \( \int x \, e^x \, dx = x \, e^x - \int e^x \, dx \)
Ultimately, the integration simplifies to \( x \, e^x - e^x + C \). Evaluating this from 1 to 2, it becomes \( \left[ x \, e^x - e^x \right]_{1}^{2} \), providing the definite result needed for finding the volume. This method allowed us to effectively handle the complexities arising from products of functions.
Definite Integrals
Definite Integrals are a fundamental concept used to find the area under a curve over a given interval. In the context of our problem, they help compute the volume of the solid after applying the cylindrical shells method.
The notation for a definite integral is:
Once the integral is evaluated, it is crucial to apply the boundaries:
The notation for a definite integral is:
- \( \int_{a}^{b} f(x) \, dx \)
Once the integral is evaluated, it is crucial to apply the boundaries:
- \( \left[ x \, e^x - e^x \right]_{1}^{2} \)
- Calculate by substituting \( x = 2 \) and \( x = 1 \) into \( x \, e^x - e^x \) and finding the difference.