Chapter 5: Problem 17
Express the sums in closed form. $$ \sum_{k=1}^{n} \frac{3 k}{n} $$
Short Answer
Expert verified
\( \frac{3(n+1)}{2} \)
Step by step solution
01
Distribution of Constant Multiplier
Factor out the constant multiplier from the summation. In this case, the constant is \( \frac{3}{n} \). Thus, the expression becomes: \[ \sum_{k=1}^{n} \frac{3k}{n} = \frac{3}{n} \sum_{k=1}^{n} k \]
02
Replace the Sum with Its Formula
Recognize that \( \sum_{k=1}^{n} k \) is the well-known formula for the sum of the first \( n \) positive integers, which is \( \frac{n(n+1)}{2} \). Substitute this formula in: \[ \frac{3}{n} \sum_{k=1}^{n} k = \frac{3}{n} \cdot \frac{n(n+1)}{2} \]
03
Simplify the Expression
Simplify the expression by carrying out the multiplication, \( \frac{3}{n} \cdot \frac{n(n+1)}{2} = \frac{3n(n+1)}{2n} \). Notice that the \( n \) in the numerator and the denominator cancel each other out, leaving: \[ \frac{3(n+1)}{2} \]
04
Conclusion
The closed form expression for the sum \( \sum_{k=1}^{n} \frac{3k}{n} \) is simply \( \frac{3(n+1)}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sum of Integers
Understanding the sum of integers plays a crucial role when learning about sequences and series in mathematics. When you see a sum like \( \sum_{k=1}^{n} k \), it refers to the sum of all integers starting from 1 up to \( n \). The concept might seem daunting at first, but remember this simple breakdown:
- You are adding numbers sequentially; think of 1 + 2 + 3 all the way up to your chosen \( n \).
- The sum formula \( \frac{n(n+1)}{2} \) provides an elegant way to calculate this total quickly, without manual addition.
- You are adding numbers sequentially; think of 1 + 2 + 3 all the way up to your chosen \( n \).
- The sum formula \( \frac{n(n+1)}{2} \) provides an elegant way to calculate this total quickly, without manual addition.
- "\( n \)" is the largest integer in your sequence.
- The term "\( (n+1) \)" prepares for the sum total stretching one place further.
Summation Formulas
Summation formulas give us a toolset to work efficiently with sums in many mathematical contexts. In the problem presented, you encountered \( \sum_{k=1}^{n} \frac{3k}{n} \). Here are the steps that used the power of a summation formula:
- First, by recognizing constants, which can be factored out of the summation: the fraction \( \frac{3}{n} \) is a constant and can be moved outside of the summation.
- Then, applying the well-known formula for the sum of the first \( n \) integers, \( \sum_{k=1}^{n} k = \frac{n(n+1)}{2} \).
These formulas help break down and simplify larger, more cumbersome expressions, providing a quicker path to solutions, avoiding tedious calculations.
- First, by recognizing constants, which can be factored out of the summation: the fraction \( \frac{3}{n} \) is a constant and can be moved outside of the summation.
- Then, applying the well-known formula for the sum of the first \( n \) integers, \( \sum_{k=1}^{n} k = \frac{n(n+1)}{2} \).
These formulas help break down and simplify larger, more cumbersome expressions, providing a quicker path to solutions, avoiding tedious calculations.
Mathematical Simplification
Mathematical simplification is about reducing complex expressions to their most concise and understandable form. Once you've applied a summation formula, such as with our ongoing example, the next goal is to simplify:
- Begin with multiplication of simplified parts: notice where terms can cancel each other out, such as \( \frac{3}{n} \cdot \frac{n(n+1)}{2} = \frac{3n(n+1)}{2n} \).
- Since \( n \) appears in both the numerator and denominator, it can be cancelled, leaving the expression easier to interpret: \( \frac{3(n+1)}{2} \).
- Begin with multiplication of simplified parts: notice where terms can cancel each other out, such as \( \frac{3}{n} \cdot \frac{n(n+1)}{2} = \frac{3n(n+1)}{2n} \).
- Since \( n \) appears in both the numerator and denominator, it can be cancelled, leaving the expression easier to interpret: \( \frac{3(n+1)}{2} \).
- This emphasizes how simplification not only makes expressions easier to handle but also helps reveal any underlying meaning or outcome.