/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Evaluate the integral and check ... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integral and check your answer by differentiating. $$ \int\left(2+y^{2}\right)^{2} d y $$

Short Answer

Expert verified
\( \int (2 + y^2)^2 \, dy = 4y + \frac{4}{3}y^3 + \frac{1}{5}y^5 + C \)

Step by step solution

01

Expand the Integrand

To integrate \( \int (2 + y^2)^2 \, dy \), first expand the expression. Use the binomial expansion formula: \[(a + b)^2 = a^2 + 2ab + b^2\] Here, \( a = 2 \) and \( b = y^2 \). Expand the integrand:\[ (2 + y^2)^2 = 4 + 4y^2 + y^4 \] So the integral becomes:\[ \int (4 + 4y^2 + y^4) \, dy \]
02

Integrate Term by Term

Integrate each term individually:- \( \int 4 \, dy = 4y \)- \( \int 4y^2 \, dy = \frac{4}{3}y^3 \) using \( \int y^n \, dy = \frac{y^{n+1}}{n+1} \)- \( \int y^4 \, dy = \frac{1}{5}y^5 \)Combine these results to get:\[ 4y + \frac{4}{3}y^3 + \frac{1}{5}y^5 + C \] where \( C \) is the constant of integration.
03

Differentiate to Check

Differentiating the result should yield the original integrand:- The derivative of \( 4y \) is \( 4 \).- The derivative of \( \frac{4}{3}y^3 \) is \( 4y^2 \).- The derivative of \( \frac{1}{5}y^5 \) is \( y^4 \).Summing these derivatives, we get:\[ 4 + 4y^2 + y^4 \]This matches the expanded form of the original integrand \( (2 + y^2)^2 \), verifying our integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Expansion
Binomial Expansion is a powerful algebraic method used to expand expressions raised to a power. It follows specific patterns based on the binomial theorem. In the context of our integral, we were tasked with expanding \((2 + y^2)^2\).
For this, we used the formula:
  • \((a + b)^2 = a^2 + 2ab + b^2\)
In our case, \(a = 2\) and \(b = y^2\), so applying the formula:
  • \(2^2 = 4\)
  • \(2 \times 2 \times y^2 = 4y^2\)
  • \((y^2)^2 = y^4\)
Therefore, the expanded form is \(4 + 4y^2 + y^4\). This expansion simplifies the process of integrating polynomial expressions because each term can be dealt with separately.
Differentiation
Differentiation is the process by which we find the rate at which a function is changing at any given point. It's essentially the reverse process of integration. When we differentiate a polynomial, we systematically reduce the powers of each term.
For example, when differentiating our solution to check correctness:
  • The derivative of \(4y\) gives us \(4\)
  • The derivative of \(\frac{4}{3}y^3\) yields \(4y^2\)
  • The derivative of \(\frac{1}{5}y^5\) gives \(y^4\)
Adding these derivatives results in the original expanded expression \(4 + 4y^2 + y^4\). This step acts as a verification showing that our integration was performed correctly, as the differentiation returns us to the initial integrand.
Indefinite Integrals
Indefinite Integrals represent the family of all antiderivatives of a function. The process of integration is essentially finding a function whose derivative gives us the original function. When dealing with indefinite integrals, a constant \(C\) is usually added to represent all the possible vertical shifts of the antiderivative.
In this exercise, after expanding and integrating term by term:
  • The integral of \(4\) results in \(4y\)
  • The integral of \(4y^2\) is \(\frac{4}{3}y^3\)
  • The integral of \(y^4\) results in \(\frac{1}{5}y^5\)
We combine these to arrive at \(4y + \frac{4}{3}y^3 + \frac{1}{5}y^5 + C\). This expression represents an indefinite integral and covers all possible solutions by accounting for an unknown constant \(C\), which is crucial when solving real-world problems, as it allows for more variables in initial conditions.

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