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The function \(s(t)\) describes the position of a particle moving along a coordinate line, where \(s\) is in meters and \(t\) is in seconds. The function \(s(t)\) describes the position of a particle moving along a coordinate line, where \(s\) is in meters and \(t\) is in seconds. (a) Make a table showing the position, velocity, and acceleration to two decimal places at times \(t=1,2,3,4,5\). (b) At each of the times in part (a), determine whether the particle is stopped; if it is not, state its direction of motion. (c) At each of the times in part (a), determine whether the particle is speeding up, slowing down, or neither. $$ s(t)=\sin \frac{\pi t}{4} $$

Short Answer

Expert verified
Calculate the position, velocity, and acceleration for each time step, then analyze the motion's direction and speed changes, noting if stopped.

Step by step solution

01

Calculate position at each time

For each given time \( t = 1, 2, 3, 4, 5 \), substitute \( t \) into the position function \( s(t) = \sin\left(\frac{\pi t}{4}\right) \) to find the position.- \( t=1 \): \( s(1) = \sin\left(\frac{\pi}{4}\right) = 0.71 \)- \( t=2 \): \( s(2) = \sin\left(\frac{\pi}{2}\right) = 1.00 \)- \( t=3 \): \( s(3) = \sin\left(\frac{3\pi}{4}\right) = 0.71 \)- \( t=4 \): \( s(4) = \sin(\pi) = 0.00 \)- \( t=5 \): \( s(5) = \sin\left(\frac{5\pi}{4}\right) = -0.71 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the study of motion without considering the forces that cause it. In kinematics, we explore how objects move in terms of displacement, velocity, and acceleration. Understanding kinematics is essential in physics as it allows us to predict future positions and motions of objects.

In our exercise, we focus on a particle moving along a coordinate line. This movement is described by the position function \(s(t) = \sin \left( \frac{\pi t}{4} \right)\). Here, \(s(t)\) tells us the position of the particle at any time \(t\). By calculating \(s(t)\) at different times, we get different positions, which are crucial for understanding the particle's motion pattern.

  • Displacement: Refers to the change in position of the particle.
  • Path: Describes the trajectory the particle follows.
By plotting the function, you can visually see how kinematics applies to real-world problems, helping you anticipate where the particle will be at any given time based on its initial position and movement pattern.
Velocity
Velocity in differential calculus is a concept that tells us how fast and in what direction a particle's position is changing over time.
It is the derivative of the position function \(s(t)\) with respect to time \(t\), represented as \(v(t) = s'(t)\).

In our exercise, velocity plays a crucial role in not just determining speed but also the direction in which the particle is moving. Calculating velocity involves finding the derivative of \(s(t) = \sin \left( \frac{\pi t}{4} \right)\), which helps pinpoint the precise motion at any moment.
  • Formula for Velocity: Deriving yields \(v(t) = \frac{\pi}{4} \cos \left( \frac{\pi t}{4} \right)\).
  • Interpreting Velocity: Positive velocity indicates motion in the positive direction along the coordinate line, while negative velocity implies it moves in the opposite direction.
By computing \(v(t)\) for different \(t\) values, you can determine when the particle stops (velocity is zero) and how its speed changes, helping to answer the exercise questions about stopping and direction.
Acceleration
Acceleration is the rate at which velocity changes with time, shedding light on how the speed of a particle varies. It's the derivative of the velocity function \(v(t)\), and helps determine if a particle is speeding up or slowing down.

To find acceleration in our problem, we derive the velocity to get \(a(t) = v'(t) = -\left( \frac{\pi^2}{16} \right) \sin \left( \frac{\pi t}{4} \right)\). This tells us how velocity changes at any given moment.

  • Speeding Up or Slowing Down: A particle speeds up when its velocity and acceleration have the same sign. It slows down when they have opposite signs.
  • Direction of Acceleration: Positive acceleration implies a change in a positive direction, while negative acceleration suggests a direction change in the negative way.
Consequently, by analyzing both the velocity and acceleration at specific times, one can ascertain whether the particle is gaining or losing speed, and thus thoroughly address the exercise parts about its motion tendencies.

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