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Use a graphing utility to determine how many solutions the equation has, and then use Newton's Method to approximate the solution that satisfies the stated condition. $$ 2 \cos x=x ; x>0 $$

Short Answer

Expert verified
The equation has one solution with \( x > 0 \), approximately \( x \approx 1.029 \).

Step by step solution

01

Graph the Functions

We first graph the functions \( y = 2 \cos x \) and \( y = x \) to visually assess how many solutions exist. Using a graphing utility, plot \( y=2 \cos x \) and \( y=x \) in the range of \( x > 0 \). Note the intersections, which represent the solutions to the equation \( 2 \cos x = x \).
02

Observe the Intersection Points

From the graph, observe how the curve of \( y=2 \cos x \) and the line \( y=x \) intersect. Typically, you will see they intersect at one point when \( x > 0 \).
03

Apply Newton's Method

To apply Newton’s Method, we define the function \( f(x) = 2 \cos x - x \). Newton's Method uses the iterative formula:\[x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\]First, calculate the derivative: \( f'(x) = -2 \sin x - 1 \).
04

Choose an Initial Guess

Choose an initial guess for \( x \) close to where the graph indicates the intersection. For instance, start with \( x_0 = 0.5 \), since the intersection is likely close to this value.
05

Perform Iterations

Apply the iterative formula for Newton's Method:1. Calculate \( f(x_0) = 2 \cos(0.5) - 0.5 \) and \( f'(x_0) = -2 \sin(0.5) - 1 \).2. Substitute into Newton's formula to find \( x_1 \).3. Repeat the process until \(|x_{n+1} - x_n| < \epsilon\), where \( \epsilon \) is a small tolerance (e.g., 0.001).
06

Interpret the Result

Once the iterations converge, the value of \( x \) approximates the solution. For instance, after a few iterations, you may get \( x \approx 1.029 \) as an approximate solution satisfying the given condition \( x > 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Utility
A graphing utility is an essential tool in mathematics for visualizing functions and their intersections. To determine how many solutions an equation has, like the one given, we use a graphing utility to plot the functions. In this case, we examine the functions \( y = 2 \cos x \) and \( y = x \). The graph helps us visually identify points where the two functions intersect, representing the solutions to the equation \( 2 \cos x = x \).

When we focus on the region where \( x > 0 \), the utility graph shows us the intersection point. In the context of this exercise, it reveals that there is typically one point of intersection. By visualizing these functions, students can get an intuitive understanding of where to look for approximate solutions before using more calculation-intensive methods like Newton's Method.
Solution Approximation
Solution approximation is crucial when you're dealing with equations that cannot be solved easily through algebraic methods. For the equation \( 2 \cos x = x \) with \( x > 0 \), we use a combination of visualization and numeric methods to approximate the solution.

First, after using a graphing utility and identifying a potential intersection, we have a rough idea of where the solution lies, in this case, around \( x = 0.5 \). Then, to hone in on the exact value, iterative numerical methods like Newton's Method are employed. This method fine-tunes the approximation based on derivative calculations, gradually improving the estimate of \( x \) with each iteration.

Approximations are useful in having a precise idea of where solutions to equations sit on the number line, especially when exact solutions are difficult to obtain.
Newton's Method Iterations
Newton's Method is an iterative technique used to find successively better approximations to the roots (or solutions) of a real-valued function. To apply it, we need a function \( f(x) = 2 \cos x - x \) derived from the original equation.
The process starts with an initial guess \( x_0 \), which should be close to the intersection point identified through graphing. For this problem, we began with \( x_0 = 0.5 \). Then we use the formula: \[ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \] where \( f'(x) = -2 \sin x - 1 \).
This equation helps us iteratively compute new values of \( x \) that get closer to the actual solution. With each iteration:
  • Compute \( f(x_n) \) and \( f'(x_n) \).
  • Update \( x_n \) using Newton's formula.
  • Check if the change \( |x_{n+1} - x_n| \) is smaller than a chosen tolerance, \( \epsilon \).
Through these iterations, the solution converges to a more accurate value, typically \( x \approx 1.029 \) in this case. This iterative approach is powerful because it rapidly increases the precision of the estimated root, making it beneficial when seeking the roots of complex functions.

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Most popular questions from this chapter

If an unknown physical quantity \(x\) is measured \(n\) times, the measurements \(x_{1}, x_{2}, \ldots, x_{n}\) often vary because of uncontrollable factors such as temperature, atmospheric pressure, and so forth. Thus, a scientist is often faced with the problem of using \(n\) different observed measurements to obtain an estimate \(\bar{x}\) of an unknown quantity \(x\). One method for making such an estimate is based on the least squares principle, which states that the estimate \(\bar{x}\) should be chosen to minimize $$ s=\left(x_{1}-\bar{x}\right)^{2}+\left(x_{2}-\bar{x}\right)^{2}+\cdots+\left(x_{n}-\bar{x}\right)^{2} $$ which is the sum of the squares of the deviations between the estimate \(\bar{x}\) and the measured values. Show that the estimate resulting from the least squares principle is $$ \bar{x}=\frac{1}{n}\left(x_{1}+x_{2}+\cdots+x_{n}\right) $$ that is, \(\bar{x}\) is the arithmetic average of the observed values.

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Use a graphing utility to determine the number of times the curves intersect; and then apply Newton's Method, where needed, to approximate the \(x\) -coordinates of all intersections. $$ y=1 \text { and } y=e^{x} \sin x ; 0

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