Chapter 3: Problem 39
Find formulas for \(d y\) and $\Delta y . $$ y=x^{3} $$
Short Answer
Expert verified
\( dy = 3x^2 \, dx \) and \( \Delta y \approx 3x^2 \, \Delta x \).
Step by step solution
01
Understand the Given Function
The problem presents the function \( y = x^3 \). We need to find the expressions for both the differential \( dy \) and the approximate change \( \Delta y \) for this function.
02
Differentiate the Function
To find \( dy \), we need to compute the derivative of the given function. Start by differentiating \( y = x^3 \) with respect to \( x \): \[\frac{dy}{dx} = \frac{d}{dx}(x^3) = 3x^2\].
03
Formulate the Expression for \( dy \)
The differential \( dy \) represents an infinitesimally small change in \( y \) for a small change \( dx \). We can write it in terms of \( dx \) as \[dy = 3x^2 \, dx\].
04
Understand the Approximate Change \( \Delta y \)
The approximate change in \( y \), denoted \( \Delta y \), can be estimated using the derivative for small changes in \( x \). For a small \( \Delta x \), we estimate \( \Delta y \) as\[\Delta y \approx 3x^2 \, \Delta x\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
In calculus, the derivative is a fundamental concept that describes how a function changes as its input changes. When considering the function \( y = x^3 \), the derivative tells us the rate at which \( y \) changes concerning \( x \). It's like finding the slope of the curve at any given point, which can help us predict how small changes in \( x \) will affect \( y \).
To calculate the derivative of \( y = x^3 \), we use the power rule. This rule states that for \( y = x^n \), the derivative is \( n \cdot x^{n-1} \). Applying this to our function, we get:
To calculate the derivative of \( y = x^3 \), we use the power rule. This rule states that for \( y = x^n \), the derivative is \( n \cdot x^{n-1} \). Applying this to our function, we get:
- The derivative \( \frac{dy}{dx} = 3x^2 \).
- This tells us that the rate of change of \( y \) with respect to \( x \) is \( 3x^2 \).
Differential Approximation
Differential approximation is a method used to estimate the change in the value of a function based on a small change in its input. For the function \( y = x^3 \), the differential \( dy \) provides a way to express how much \( y \) changes for a tiny variation in \( x \).
Here's a simple way to understand differential approximation:
Here's a simple way to understand differential approximation:
- You calculate the derivative of the function, which, in our case, is \( 3x^2 \).
- This derivative is then multiplied by a small change in \( x \) (denoted as \( dx \)) to find \( dy \).
- Thus, \( dy = 3x^2 \, dx \) gives us an estimate of how much \( y \) would change for an infinitesimally small change in \( x \).
Infinitesimal Calculus
Infinitesimal calculus focuses on the concepts of limits, continuity, and the behavior of functions at extremely small values of their variables. In our discussion of the function \( y = x^3 \), we dive into infinitesimal calculus by exploring what happens when changes in \( x \) are incredibly tiny.
By considering infinitesimally small increments \( dx \), we can use calculus to predict \( dy \), the corresponding small change in \( y \). The beauty of this approach lies in its simplicity and power:
By considering infinitesimally small increments \( dx \), we can use calculus to predict \( dy \), the corresponding small change in \( y \). The beauty of this approach lies in its simplicity and power:
- It enables us to understand the behavior of complex functions through straightforward approximations.
- Infinitesimals make it possible to calculate derivatives and use them to derive important results like \( dy \) and \( \Delta y \).