Chapter 3: Problem 25
Find \(d y / d x\). $$ y=\log \left(\sin ^{2} x\right) $$
Short Answer
Expert verified
The derivative \( \frac{d y}{d x} \) is \( 2 \cdot \cot x \).
Step by step solution
01
Apply Logarithmic Differentiation
To differentiate the function \( y = \log(\sin^2 x) \), we recognize it as the logarithm of a power. We can use the property: \( \log(a^b) = b \cdot \log(a) \). Thus, we rewrite: \( y = 2 \cdot \log(\sin x) \).
02
Differentiate Using Chain Rule
Differentiate \( y = 2 \cdot \log(\sin x) \) with respect to \( x \) using the chain rule. The derivative of \( \log(u) \) where \( u = \sin x \) is \( \frac{1}{u} \cdot \frac{du}{dx} \). Here, \( \frac{du}{dx} = \cos x \).
03
Write the Derivative
Following the chain rule application, \( \frac{d}{dx}\left(2 \cdot \log(\sin x)\right) = 2 \cdot \frac{1}{\sin x} \cdot \cos x = 2 \cdot \cot x \).
04
Combine to Final Answer
The derivative \( \frac{d y}{d x} = 2 \cdot \cot x \) using the steps above.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental concept in calculus used to differentiate composite functions, which are functions built from two or more combined functions. For example, in our exercise, the function is composed of a logarithm and a trigonometric function. The chain rule can be expressed as follows:
- If you have a composite function, say \( y = f(g(x)) \), the derivative \( \frac{dy}{dx} \) can be found by multiplying two derivatives: \( f'(g(x)) \) and \( g'(x) \).
- The outer function is \( \, \log(\sin x) \, \).
- The inner function is \( \, \sin x \, \).
Trigonometric Functions
Trigonometric functions like \( \sin x \, \) (sine), \( \cos x \, \) (cosine), and \( \tan x \, \) (tangent) play an essential role in calculus, especially in this exercise.In the exercise, the function \( y = \log(\sin^2 x) \) involves taking the logarithm of a trigonometric expression. Here are a few important points about trigonometric functions:
- The sine function, \( \sin x \), oscillates between -1 and 1. It's important when incorporating periodic behavior in differentiation problems.
- The cosine function, \( \cos x \), is the derivative of \( \sin x \), and also oscillates between -1 and 1. Using it as \( \frac{d}{dx}(\sin x) = \cos x \) is crucial for chain rule applications.
- The cotangent function, \( \cot x = \frac{\cos x}{\sin x} \), often appears when working with derivatives of ratios involving sine and cosine.
Derivatives
Derivatives represent the rate of change of a function with respect to its variable. When we want to find the derivative of a function involving trigonometric and logarithmic expressions, using techniques like the chain rule and understanding how to handle each component is necessary.In the original problem, we needed to differentiate \( y = \log(\sin^2 x) \). We simplified it first to \( y = 2 \log(\sin x) \) using logarithmic properties.Key steps for finding derivatives:
- Understand the function type: Identify if the function is composite, involving multiple operations.
- Apply properties: Use log properties to simplify, if possible, before differentiating.
- Use differentiation techniques: Apply rules like the chain rule to handle composite parts.