/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Find \(f^{\prime}(x)\). $$ f... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(f^{\prime}(x)\). $$ f(x)=2 \sin ^{2} x $$

Short Answer

Expert verified
The derivative is \( f'(x) = \sin(2x) \).

Step by step solution

01

Recognize the Function Type

The function given is a trigonometric function, specifically a squared sine function. We will be using trigonometric identities and differentiation rules to find its derivative.
02

Apply the Chain Rule

Rewrite the function using a trigonometric identity: \( f(x) = 2 (\sin x)^2 \). To differentiate \( u^2 \), where \( u = \sin x \), apply the chain rule: if \( g(x) = u^2 \), then \( g'(x) = 2u \cdot u' \).
03

Differentiate \( \sin x \)

Identify \( u = \sin x \) and differentiate it with respect to \( x \): \( u' = \cos x \).
04

Find \( f'(x) \)

Apply the chain rule: \( f'(x) = 2(\sin x)(\cos x) \). Simplify the expression to obtain \( f'(x) = 2 \sin x \cos x \).
05

Use a Trigonometric Identity (Optional)

Recognize that \( 2 \sin x \cos x = \sin(2x) \), thus \( f'(x) = \sin(2x) \). This step is optional as it uses the double angle identity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The Chain Rule is a powerful technique in calculus used for finding the derivative of composite functions. In this context, a composite function is one that can be broken down into two or more functions nested within one another, like something wrapped up and interwoven.
Here's how it works:
  • Identify the outer function and the inner function.
  • Calculate the derivative of each function separately.
  • Multiply these derivatives together, ensuring the inner derivative is applied to the derivative of the outer function.
For the given function, \( f(x) = 2 \sin^2 x \), the outer function is \( u^2 \) and the inner function is \( u = \sin x \). Therefore, we apply the Chain Rule by first differentiating the outer function \( u^2 \), which yields \( 2u \), and then differentiate the inner function \( \sin x \), resulting in \( \cos x \).
After that, we combine them to get \( 2 \sin x \cos x \). Using the Chain Rule in this way helps bridge complex functions into simpler calculations, making differentiation easier and more understandable.
Trigonometric Identities
Trigonometric identities are mathematical formulas that relate different trigonometric functions to one another. They are incredibly useful in calculus, especially when simplifying expressions and solving equations.
In our example, the function \( f(x) = 2 \sin^2 x \) can benefit from these identities, particularly the Double Angle identity, which states:\[2 \sin x \cos x = \sin(2x)\]This identity helps to simplify the derivative we found using the Chain Rule. After applying the Chain Rule, we obtained the derivative \( 2 \sin x \cos x \). With the Double Angle identity, this expression transforms into \( \sin(2x) \).
Such transformations are optional but can make results neater and often reveal different perspectives or insights into the problem-solving process. By recognizing and using these identities effectively, we can streamline calculations and simplify complex trigonometric expressions.
Derivative of Trigonometric Functions
The derivative of trigonometric functions forms the foundation for differentiating a wide range of mathematical functions. The basic trigonometric functions—\( \sin x \), \( \cos x \), \( \tan x \), etc.—each have specific derivatives which need to be learned and memorized for efficient problem-solving.
When differentiating these functions, here are the key derivatives to remember:
  • The derivative of \( \sin x \) is \( \cos x \).
  • The derivative of \( \cos x \) is \(-\sin x \).
  • The derivative of \( \tan x \) is \( \sec^2 x \).
For the function \( f(x) = 2 \sin^2 x \), we focus on the derivative of \( \sin x \), which is \( \cos x \). This derivative plays a crucial role when we apply the Chain Rule, as it determines how the inner part of the composite function impacts the derivative of the overall function.
Understanding these fundamentals allows for a more straightforward process in differentiating functions involving trigonometric components, making calculus a bit less intimidating and much more manageable.

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Most popular questions from this chapter

Given that \(f^{\prime}(x)=\sqrt{3 x+4}\) and \(g(x)=x^{2}-1\), find \(F^{\prime}(x)\) if \(F(x)=f(g(x))\)

Show that if \(x \neq 0\), then \(y=1 / x\) satisfies the equation \(x^{3} y^{\prime \prime}+x^{2} y^{\prime}-x y=0\)

Determine whether the statement is true or false. Explain your answer. A spherical balloon is being inflated. (a) Find a general formula for the instantaneous rate of change of the volume \(V\) with respect to the radius \(r\), given that \(V=\frac{4}{3} \pi r^{3}\) (b) Find the rate of change of \(V\) with respect to \(r\) at the instant when the radius is \(r=5\).

Determine whether the statement is true or false. Explain your answer. If \(f\) and \(g\) are differentiable at \(x=2\), then $$ \left.\frac{d}{d x}[f(x)-8 g(x)]\right|_{x=2}=f^{\prime}(2)-8 g^{\prime}(2) $$

You are asked in these exercises to determine whether a piecewise-defined function \(f\) is differentiable at a value \(x=x_{0}\) where \(f\) is defined by different formulas on different sides of \(x_{0} .\) You may use without proof the following result, which is a consequence of the Mean-Value Theorem (discussed in Section 4.8). Theorem. Let \(f\) be continuous at \(x_{0}\) and suppose that \(\lim _{x \rightarrow x_{0}} f^{\prime}(x)\) exists. Then \(f\) is differentiable at \(x_{0}\), and \(f^{\prime}\left(x_{0}\right)=\lim _{x \rightarrow x_{0}} f^{\prime}(x)\) Let $$ f(x)=\left\\{\begin{array}{ll} x^{2}-16 x, & x<9 \\ \sqrt{x}, & x \geq 9 \end{array}\right. $$ Is \(f\) continuous at \(x=9\) ? Determine whether \(f\) is differentiable at \(x=9 .\) If so, find the value of the derivative there.

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