Chapter 13: Problem 21
Determine whether the limit exists. If so, find its value. $$ \lim _{(x, y, z) \rightarrow(0,0,0)} \frac{e^{\sqrt{x^{2}+y^{2}+z^{2}}}}{\sqrt{x^{2}+y^{2}+z^{2}}} $$
Short Answer
Expert verified
The limit exists and is equal to 1.
Step by step solution
01
Understand the Function and Limit Point
We are asked to find \( \lim_{(x, y, z) \rightarrow (0,0,0)} \frac{e^{\sqrt{x^{2}+y^{2}+z^{2}}}}{\sqrt{x^{2}+y^{2}+z^{2}}} \). The limit point is the origin (0,0,0) in three-dimensional space, and the function involves an exponential term divided by a radical expression. We need to determine whether this limit exists as \((x, y, z)\) approaches zero.
02
Convert to Spherical Coordinates
Since the limit involves \(x^2 + y^2 + z^2\), it's beneficial to convert to spherical coordinates where \(\rho = \sqrt{x^2 + y^2 + z^2}\), which simplifies the expression. This transforms the limit to \(\lim_{\rho \rightarrow 0} \frac{e^{\rho}}{\rho}\).
03
Analyze the Limit Expression
Look at the expression \( \lim_{\rho \rightarrow 0} \frac{e^{\rho}}{\rho} \). Direct substitution is not possible because it leads to the indeterminate form \(\frac{1}{0}\), which suggests further analysis is needed or the use of L'Hôpital's Rule if applicable.
04
Apply L'Hôpital's Rule
L'Hôpital's Rule states that for limits of the form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), we can take the derivative of the numerator and the denominator. In this case, we take the derivative of \(e^\rho\) and \(\rho\), which gives us: \[\lim_{\rho \rightarrow 0} \frac{\frac{d}{d\rho}(e^{\rho})}{\frac{d}{d\rho}(\rho)} = \lim_{\rho \rightarrow 0} \frac{e^{\rho}}{1} = \lim_{\rho \rightarrow 0} e^{\rho}.\]
05
Evaluate the Simplified Limit
The simplified limit expression \(\lim_{\rho \rightarrow 0} e^{\rho}\) is direct, and since \(e^{\rho}\) approaches \(e^0 = 1\) as \(\rho \rightarrow 0\), we find that the limit is equal to 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit of a function
The concept of the limit of a function, especially in multivariable calculus, is essential to understanding how functions behave as their inputs approach certain points. In our exercise, we are interested in the behavior of a function as its variables
- Approach a specific point, in this case, the origin (0, 0, 0).
- The key question is whether the function approaches a particular value when getting infinitely close to that point.
- \((x, y, z) \to (0, 0, 0)\).
Spherical coordinates
Spherical coordinates can greatly simplify problems in three-dimensional space involving radial symmetry, like in our function where you see
- The expression \(x^2 + y^2 + z^2\).
- \(\rho\) represents the radial distance from the origin (similar to radius in polar coordinates),
- \(\theta\) is the azimuthal angle in the xy-plane from the x-axis, and
- \(\phi\) denotes the angle from the z-axis.
L'Hôpital's Rule
L'Hôpital's Rule is a powerful tool in calculus for finding limits of indeterminate forms like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\). In our problem, the transformed limit expression using spherical coordinates, \(\lim_{\rho \to 0} \frac{e^{\rho}}{\rho}\), initially presents an indeterminate form. Here, L'Hôpital's Rule comes into play:
- By differentiating both the numerator \(e^\rho\) and the denominator \(\rho\).
- We turn the expression into \(\lim_{\rho \to 0} \frac{e^{\rho}}{1}\).