Chapter 12: Problem 46
Use the given information to find the normal scalar component of acceleration at time \(t=1\) $$ \|\mathbf{a}(1)\|=9 ; a_{T}(1) \mathbf{T}(1)=2 \mathbf{i}-2 \mathbf{j}+\mathbf{k} $$
Short Answer
Expert verified
The normal scalar component of acceleration at \( t=1 \) is \( 6\sqrt{2} \).
Step by step solution
01
Understanding the Problem
We are given the magnitude of acceleration \( \|\mathbf{a}(1)\| = 9 \) and the tangential component of acceleration \( a_T(1) \mathbf{T}(1) = 2 \mathbf{i} - 2 \mathbf{j} + \mathbf{k} \). We need to find the normal scalar component of acceleration, which we'll denote as \( a_N(1) \).
02
Calculate the Magnitude of the Tangential Component
First, calculate the magnitude of the tangential component vector \( a_T(1) \mathbf{T}(1) \):\[ \|a_T(1) \mathbf{T}(1)\| = \sqrt{(2)^2 + (-2)^2 + (1)^2} = \sqrt{4 + 4 + 1} = 3 \]
03
Calculate the Tangential Component
The tangential component \( a_T(1) \) can be found using the formula \( a_T(1) = \frac{\|a_T(1) \mathbf{T}(1)\|}{\|\mathbf{T}(1)\|} \). Given that \( \|\mathbf{T}(1)\| = 1 \) (since \( \mathbf{T} \) is a unit vector), we have \( a_T(1) = 3 \).
04
Use the Formula for Total Acceleration
The total acceleration is given by \( \|\mathbf{a}(1)\|^2 = a_T(1)^2 + a_N(1)^2 \). Substitute the values we know:\[ 9^2 = 3^2 + a_N(1)^2 \]
05
Solve for the Normal Component
Rearrange the equation to solve for \( a_N(1) \):\[ 81 = 9 + a_N(1)^2 \] Subtract 9 from both sides and solve:\[ 72 = a_N(1)^2 \] Take the square root to find \( a_N(1) \):\[ a_N(1) = \sqrt{72} = 6\sqrt{2} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Normal component of acceleration
The normal component of acceleration, often denoted as \( a_N \), is a key concept when we consider motion along a curved path. It measures the part of acceleration directed perpendicular to the path's tangent. Think of a car driving around a bend. While it’s accelerating along the path of the road, it also has an acceleration pushing it towards the center of the curve.
- The formula to find the normal component relates to the Pythagorean theorem: \( a_N^2 = \|\mathbf{a}\|^2 - a_T^2 \).
- This component is perpendicular to the direction of motion.
- It often indicates how quickly the direction of the speed is changing rather than its magnitude.
Tangential component of acceleration
The tangential component of acceleration, denoted as \( a_T \), focuses on how fast an object speeds up or slows down along its path. Unlike the normal component, \( a_T \) is parallel to the direction of travel.
- This component is calculated by the change in the speed of the object in its path.
- The formula is \( a_T = \frac{d|v|}{dt} \) where \( |v| \) is the magnitude of velocity.
- Tangential acceleration can be understood as the rate of change of speed along the path.
Vector magnitude
The magnitude of a vector, sometimes called its length or norm, is a measure of how long the vector is. For a vector \( \mathbf{v} = a \mathbf{i} + b \mathbf{j} + c \mathbf{k} \), the magnitude \( \|\mathbf{v}\| \) is computed using the equation
- \( \|\mathbf{v}\| = \sqrt{a^2 + b^2 + c^2} \)
- The magnitude depicts the size of the vector regardless of its direction.
- In physics, it often represents quantities like speed, force, or acceleration.