/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Sketch the graph of \(\mathbf{r}... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of \(\mathbf{r}(t)\) and show the direction of increasing \(t .\) $$ \mathbf{r}(t)=t \mathbf{i}+t^{2} \mathbf{j}+2 \mathbf{k} $$

Short Answer

Expert verified
The graph is a parabola translated to the plane \( z = 2 \) with direction from left to right as \( t \) increases.

Step by step solution

01

Identify Components

The vector function is given by \( \mathbf{r}(t) = t \mathbf{i} + t^2 \mathbf{j} + 2 \mathbf{k} \). This function is in the form \( (x(t), y(t), z(t)) = (t, t^2, 2) \). It describes a curve in three-dimensional space, with each component impacting a specific axis: \( x = t \), \( y = t^2 \), and \( z = 2 \).
02

Analyze the Path on the xy-plane

On the xy-plane, eliminate the parameter \( t \) by expressing \( y \) in terms of \( x \). Since \( x(t) = t \) and \( y(t) = t^2 \), replace \( t \) with \( x \) to get \( y = x^2 \). This is a standard parabola that opens upwards.
03

Determine the z-component

The function \( z(t) = 2 \) indicates that z is constant. Therefore, the graph is a parabola (from the xy-plane) that is translated or elevated to the plane \( z = 2 \). This means the parabola lies parallel to the xy-plane and is shifted upwards along the z-axis by 2 units.
04

Show Direction of Increasing t

As \( t \) increases from negative to positive values, \( x = t \) increases linearly, \( y = t^2 \) increases quadratically, and \( z \) remains constant at 2. The direction of the curve's path can be indicated by an arrow along the curve pointing in the positive x-direction, as it moves from negative to positive values.
05

Sketch the Graph

Sketch a parabola on the xy-plane. Then, elevate the entire parabola to where \( z = 2 \). Draw the curve to curve upward along the y-axis while lying flat parallel to the z-axis, with an arrow showing the direction of increasing \( t \) (from left to right along the x-axis).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Parametric equations are a powerful tool in mathematics. They describe a set of related quantities as functions of an independent variable, often referred to as the parameter. Unlike standard functions that express output directly in terms of inputs, parametric equations allow each coordinate to be expressed independently.
For example, in the exercise, we have
  • \( x(t) = t \)
  • \( y(t) = t^2 \)
  • \( z(t) = 2 \)
These equations describe the position of a point in three-dimensional space as the parameter \( t \) changes. The power of parametric equations is that they can describe complex curves and paths that are not easily solvable by traditional functions. In our example, the parametric form simplifies how we view and manipulate the curve as \( t \) varies.
Three-Dimensional Space
In three-dimensional space, we use a coordinate system involving three axes: \( x \), \( y \), and \( z \). This allows us to represent points not just on a flat plane, but in space with depth. In vector calculus, we often describe paths or curves in this space using vector functions.
For instance, the function \( \mathbf{r}(t) = t \mathbf{i} + t^2 \mathbf{j} + 2 \mathbf{k} \) outlines a curve in 3D space.
  • The \( x \)-component, \( t \), moves linearly.
  • The \( y \)-component, \( t^2 \), creates a parabolic shape.
  • The \( z \)-component, being constant \( z = 2 \), shifts the parabola upwards.
This function describes how a point traverses a path over time, with these axes providing a framework to visualize its movement through space.
Graph Sketching
Graph sketching in vector calculus is about visualizing curves described by parametric equations in space. When given a vector function like \( \mathbf{r}(t) = t \mathbf{i} + t^2 \mathbf{j} + 2 \mathbf{k} \), the goal is to form an accurate picture of what this path looks like and its orientation.
Firstly, identify how each component affects the curve:
  • \( x = t \) plots linearly along the x-axis.
  • \( y = t^2 \) shapes the path as a parabola in the xy-plane.
  • \( z = 2 \) elevates the curve repeatedly by the same measure, floating it parallel to the plane.
To sketch the graph, begin on the xy-plane with a parabola. Then, lift this shape entirely to the plane where \( z = 2 \). As \( t \) rises, trace the curve from left to right, showing increasing \( t \) with an arrow. This helps depict its motion in space, directly visualizing how our parameter guides the shape's progression.

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Most popular questions from this chapter

(a) Suppose that at time \(t=t_{0}\) an electron has a position vector of \(\mathbf{r}=3.5 \mathbf{i}-1.7 \mathbf{j}+\mathbf{k}\), and at a later time \(t=t_{1}\) it has a position vector of \(\mathbf{r}=4.2 \mathbf{i}+\mathbf{j}-2.4 \mathbf{k}\). What is the displacement of the electron during the time interval from \(t_{0}\) to \(t_{1}\) ? (b) Suppose that during a certain time interval a proton has a displacement of \(\Delta \mathbf{r}=0.7 \mathbf{i}+2.9 \mathbf{j}-1.2 \mathbf{k}\) and its fi- nal position vector is known to be \(\mathbf{r}=3.6 \mathbf{k}\). What was the initial position vector of the proton?

A shell is fired from ground level at an elevation angle of \(\alpha\) and a muzzle speed of \(\underline{v_{0} \text { . }}\) (a) Show that the maximum height reached by the shell is $$ \text { maximum height }=\frac{\left(v_{0} \sin \alpha\right)^{2}}{2 g} $$ (b) The horizontal range \(R\) of the shell is the horizontal distance traveled when the shell returns to ground level. Show that \(R=\left(v_{0}^{2} \sin 2 \alpha\right) / g .\) For what elevation angle will the range be maximum? What is the maximum range?

Calculate \(d \mathbf{r} / d \tau\) by the chain rule, and then check your result by expressing \(\mathbf{r}\) in terms of \(\tau\) and differentiating. $$ \mathbf{r}=t \mathbf{i}+t^{2} \mathbf{j} ; \quad t=4 \tau+1 $$

Use the given information to find the position and velocity vectors of the particle. $$ \mathbf{a}(t)=(t+1)^{-2} \mathbf{j}-e^{-2 t} \mathbf{k} ; \mathbf{v}(0)=3 \mathbf{i}-\mathbf{j} ; \mathbf{r}(0)=2 \mathbf{k} $$

Calculate \(d \mathbf{r} / d \tau\) by the chain rule, and then check your result by expressing \(\mathbf{r}\) in terms of \(\tau\) and differentiating. $$ \mathbf{r}=\langle 3 \cos t, 3 \sin t\rangle ; \quad t=\pi \tau $$

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