/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Sketch the curve in polar coordi... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the curve in polar coordinates. \(r=4+3 \cos \theta\)

Short Answer

Expert verified
The limaçon \(r = 4 + 3 \cos \theta\) is a dimpled curve without a loop.

Step by step solution

01

Identify the Polar Equation Form

The given polar equation is \(r = 4 + 3 \cos \theta\). This is a type of limaçon equation, where it has the form \(r = a + b \cos \theta\). Here, \(a = 4\) and \(b = 3\).
02

Determine Special Points

Calculate the specific points such as maximum and minimum, by evaluating \(\theta = 0, \pi/2, \pi, 3\pi/2, 2\pi\). For \(\theta = 0\), \(r = 7\). For \(\theta = \pi\), \(r = 1\). Notice the symmetry because of the \(\cos\) function.
03

Determine Limaçon Type

Compare \(a\) and \(b\). Since \(a > b\), this is called a "limaçon with a loop". The loop occurs because \(b < a\), meaning there is no inner loop.
04

Identify Intercepts and Symmetry

The curve should have symmetry over the horizontal axis due to the cosine function. The intercepts occur at \(\theta = 0\) and \(\theta = \pi\) as previously calculated. Also check other angles like \(\theta = \pi/2\) where \(r = 4\), representing lateral extension.
05

Sketch the Curve

Plot the key points on the polar graph. Start at the maximum distance from the pole at \(r = 7\) along \(\theta = 0\). The curve reduces to the minimum at \(r = 1\) for \(\theta = \pi\), and has a circular symmetry due to the nature of the cosine function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limaçon Curve
A Limaçon curve is a fascinating type of shape that you can easily recognize in polar coordinates. It's defined by its equation format, which is typically expressed as \(r = a + b \cos \theta\) or \(r = a + b \sin \theta\). The curve gets its name from the French word for "snail" because it often exhibits a spiral-like appearance. Depending on the values of \(a\) and \(b\), the Limaçon can have various forms. One way it might appear is as a heart-shaped curve known as a cardioid, which happens when \(a = b\). In this exercise, the equation \(r = 4 + 3 \cos \theta\) represents a Limaçon without an inner loop, because here, \(a > b\). This results in a "dimpled" appearance rather than one with a loop, which you would see if \(b > a\). To visualize it, you can think of it as a rounded shape with a distinct indentation at some angles on its graph.
Symmetry in Polar Graphs
Understanding symmetry is crucial when sketching curves in polar graphs. Symmetry helps simplify the process by reducing the number of points you need to calculate. For polar equations like \(r = a + b \cos \theta\), you often see symmetry about the polar axis, meaning the curve mirrors itself about the horizontal axis. This symmetry stems from the properties of the cosine function, which repeats every \(2\pi\) and mirrors every \(\pi\). When graphing such equations, you might only need to calculate values from 0 to \(\pi\), knowing the pattern will repeat and mirror itself. This characteristic is particularly helpful in quickly sketching the graph and understanding its overall shape without extra redundant calculations. For this Limaçon, the symmetry about the polar axis allows it to maintain balance, contributing to its smooth continuous appearance.
Maximum and Minimum Points
Finding maximum and minimum points is an essential part of graphing polar curves. For the equation \(r = 4 + 3 \cos \theta\), these points help describe the extent of the curve. The maximum value of \(r\) occurs when the cosine function reaches its highest value, which is 1. This happens at \(\theta = 0\), where \(r = 4 + 3(1) = 7\). This means the curve reaches its farthest point from the pole at this angle. The minimum value of \(r\) occurs when \(\cos \theta = -1\), at \(\theta = \pi\), where \(r = 4 + 3(-1) = 1\). This gives the closest point to the pole. Identifying these critical points is not just about sketching but understanding the reach and the limits of the curve. By calculating these points, you can sketch a more precise and informative graph, offering a clearer picture of the curve's behavior.

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Most popular questions from this chapter

In the late seventeenth century the Italian astronomer Giovanni Domenico Cassini (1625-1712) introduced the family of curves $$ \left(x^{2}+y^{2}+a^{2}\right)^{2}-b^{4}-4 a^{2} x^{2}=0 \quad(a>0, b>0) $$ in his studies of the relative motions of the Earth and the Sun. These curves, which are called \mathrm{\\{} C a s s i n i ~ o v a l s , ~ h a v e ~ one of the three basic shapes shown in the accompanying figure. (a) Show that if \(a=b\), then the polar equation of the Cassini oval is \(r^{2}=2 a^{2} \cos 2 \theta\), which is a lemniscate. (b) Use the formula in Exercise 71 to show that the lemniscate in part (a) is the curve traced by a point that moves in such a way that the product of its distances from the polar points \((a, 0)\) and \((a, \pi)\) is \(a^{2}\).

Discuss the relationship between the eccentricity \(e\) of an ellipse and the distance \(z\) between the directrix and center of the ellipse. For example, if the foci remain fixed, what happens to \(z\) as \(e\) approaches 0 ?

True-False Determine whether the statement is true or false. Explain your answer. The polar coordinate pairs \((-1, \pi / 3)\) and \((1,-2 \pi / 3)\) describe the same point.

Prove: The line tangent to the hyperbola $$ \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1 $$ at the point \(\left(x_{0}, y_{0}\right)\) has the equation $$ \frac{x x_{0}}{a^{2}}-\frac{y y_{0}}{b^{2}}=1 $$

(a) Use a graphing utility to confirm that the graph of \(r=2-\sin (\theta / 2)(0 \leq \theta \leq 4 \pi)\) is symmetric about the \(x\) -axis. (b) Show that replacing \(\theta\) by \(-\theta\) in the polar equation \(r=2-\sin (\theta / 2)\) does not produce an equivalent equation. Why does this not contradict the symmetry demonstrated in part (a)?

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