Chapter 10: Problem 24
Sketch the curve in polar coordinates. \(r=4 \cos \theta\)
Short Answer
Expert verified
The curve is a circle with radius 2, centered at (2,0) on the x-axis in polar coordinates.
Step by step solution
01
Understand Polar Coordinates
In polar coordinates, each point on the plane is defined by a distance from the origin (r) and an angle (θ) from the positive x-axis. The equation given is in the form \( r = 4 \cos \theta \). This describes a set of points where the radius \( r \) changes as the angle \( \theta \) changes.
02
Identify the Type of Curve
The equation \( r = 4 \cos \theta \) is a type of polar curve known as a limaçon. However, when the equation is in the form \( r = a \cos \theta \), and \( a > 0 \), it represents a circle. Specifically, when \( r = a \cos \theta \), it is a circle with a diameter of \( a = 4 \) along the x-axis.
03
Set Limits for θ
Since we are dealing with a cosine function, \( \theta \) typically ranges from 0 to \( 2\pi \) to complete a full circle. The value of \( r \) will be non-negative from \( -\pi/2 \) to \( \pi/2 \), affecting the graph accordingly.
04
Calculate Key Points
To sketch the curve, it is helpful to calculate several points. Plug in values of \( \theta = 0, \pi/3, \pi/2, \pi, 3\pi/2 \) to get corresponding \( r \) values:- At \( \theta = 0 \), \( r = 4 \cos(0) = 4 \).- At \( \theta = \pi/2 \), \( r = 4 \cos(\pi/2) = 0 \).- Similarly, at \( \theta = \pi \), \( r = 4 \cos(\pi) = -4 \), but \( r < 0 \) indicates the radius length in the opposite direction, leading back to positive x-direction.- At \( \theta = 3\pi/2 \), \( r = 0 \) again.
05
Sketch the Curve
To sketch \( r = 4 \cos \theta \), draw a circle centered on the x-axis. The circle will have a radius of 2, showing complete symmetry about the x-axis as its center is displaced at \((2, 0)\) from the origin. The x-values range between -2 and 2, effectively making the total diameter of the circle 4.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
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The term "limaçon" is derived from the French word for snail, capturing the essence of these unique polar curves. A limaçon features a characteristic looping or eyeglass shape, influenced by the trigonometric components in its equation. Generally, when a polar equation takes the form \( r = a \, + \, b \cos \theta \) or \( r = a \, + \, b \sin \theta \), it describes a limaçon.
Depending on the relationship between the coefficients \(a\) and \(b\), the limaçon can have different forms:
Depending on the relationship between the coefficients \(a\) and \(b\), the limaçon can have different forms:
- If \( a = b \), the curve appears as a cardioid.
- If \( a > b \), the limaçon resembles a dimpled circle.
- If \( a < b \), it features an inner loop. This can appear quite prominently when \( a \) is significantly smaller than \( b \).
Circle in Polar Coordinates
In polar coordinates, defining a circle equation is both simple and intuitive. A circle in the polar coordinate system is often expressed through an equation like \( r = a \cos \theta \) or \( r = a \sin \theta \). These are special cases of limaçons where no additional constant is added to the basic trigonometric term.
For the specific equation \( r = 4 \cos \theta \), it corresponds to a circle centered along the x-axis in the Cartesian plane. The radius of this circle can be found by understanding that from \(-2\) to \(2\) along the x-axis, it covers its full diameter. Hence, the radius is \(\frac{4}{2} = 2\).
This particular circle is not centered at the origin. Instead, it has been displaced along the x-axis to reflect the cosine component’s influence. It effectively centers at \((2, 0)\), allowing it to strike a perfect balance between the left and right stretches on the graph.
For the specific equation \( r = 4 \cos \theta \), it corresponds to a circle centered along the x-axis in the Cartesian plane. The radius of this circle can be found by understanding that from \(-2\) to \(2\) along the x-axis, it covers its full diameter. Hence, the radius is \(\frac{4}{2} = 2\).
This particular circle is not centered at the origin. Instead, it has been displaced along the x-axis to reflect the cosine component’s influence. It effectively centers at \((2, 0)\), allowing it to strike a perfect balance between the left and right stretches on the graph.
Graphing Polar Equations
Graphing polar equations can initially seem daunting. However, it becomes clearer with practice and a methodical approach. The most straightforward way to start is by understanding the nature and symmetry of the trigonometric function you are working with.
Here are a few steps to help guide your graphing of equations like \( r = 4 \cos \theta \):
Here are a few steps to help guide your graphing of equations like \( r = 4 \cos \theta \):
- Identify the type of curve: Knowing in advance what shape you anticipate – like a circle or limaçon – can guide your graphing.
- Calculate key points: Choose several strategic values of \( \theta \) (e.g., \(0, \frac{\pi}{3}, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi\)) and compute corresponding \(r\) values to plot important locations.#
- Use symmetry: Recognize intrinsic symmetries due to cosine or sine functions to simplify your plotting.
- Consider limits of \( \theta \): Depending on the function – especially when it involves cosines or sines – recognize typical limits like \([0, 2\pi]\) for a smooth, complete picture.