Chapter 1: Problem 36
Use Definition \(1.4 .1\) to prove that the stated limit is correct. In each case, to show that \(\lim _{x \rightarrow a} f(x)=L\), factor \(|f(x)-L|\) in the form $$ |f(x)-L|=\mid \text { "something"| }|\cdot| x-a \mid $$ and then bound the size of \(\mid\) "something"l by putting restrictions on the size of \(\delta\). $$ \lim _{x \rightarrow 2} x^{3}=8 $$
Short Answer
Step by step solution
State the definition of a limit
Identify function and limit
Express \( |f(x) - L| \)
Bound "something"
Choose \( \delta \) and relate to \( \epsilon \)
Conclusion
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
epsilon-delta definition
According to this definition, we say that the limit of a function \( f(x) \) as \( x \) approaches \( a \) is equal to \( L \), denoted by \( \lim_{x \rightarrow a} f(x) = L \), if for every positive number \( \epsilon \), however small, there exists another positive number \( \delta \) such that whenever \( x \) gets close to \( a \) by at most \( \delta \) (meaning \( 0 < |x-a| < \delta \)), the function's value \( f(x) \) will be within \( \epsilon \) of \( L \) (meaning \( |f(x) - L| < \epsilon \)).
This definition insists on precision, ensuring the function approaches \( L \) under these constraints:
- \( \epsilon \) controls how close \( f(x) \) should be to \( L \).
- \( \delta \) controls how close \( x \) should be to \( a \).
This is what gives us the ability to prove limits with certainty.
factorization in limits
In the example where we prove that \( \lim_{x \rightarrow 2} x^3 = 8 \), factorization helps us express the distance between \( f(x) \) and \( L \) in a form that directly involves \( |x-a| \), the distance between \( x \) and \( a \). We start by looking at \( |x^3 - 8| \). Recognizing this as a standard difference of cubes, we factor it as:
\[ |x^3 - 8| = |(x-2)(x^2 + 2x + 4)| \]
This factorization is crucial because it separates terms into \( |x-2| \), which corresponds to our \( |x-a| \), allowing us to exploit the epsilon-delta definition effectively.
By expressing \( |f(x) - L| \) in this factored form, it highlights the terms you can "control" directly through \( \delta \). This step makes bounding \( |f(x) - L| \) in response to changes in \( x \) tractable, hence facilitating a methodical limit proof.
bounding expressions
In the process of proving \( \lim_{x \rightarrow 2} x^3 = 8 \), we needed to bound the expression \( |x^2 + 2x + 4| \), which appeared after factorization. Remember, bounding is essentially finding a maximum or controllable value for the expression on some interval close to \( a \).
We checked the value of \( x^2 + 2x + 4 \) within the context where \( x \) ranges from 1 to 3 (since \( |x - 2| < 1 \)), ensuring that:
- At \( x = 1 \), the expression equals 7.
- At \( x = 3 \), it equals 19.
- Therefore, within the chosen range, the expression \( |x^2 + 2x + 4| \leq 19 \).