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True-False Determine whether the statement is true or false. Explain your answer. If \(\lim _{x \rightarrow a} f(x)\) and \(\lim _{x \rightarrow a} g(x)\) exist, then so does \(\lim _{x \rightarrow a}[f(x)+g(x)]\)

Short Answer

Expert verified
The statement is true, based on the limit laws in calculus.

Step by step solution

01

Understand Limit Properties

To solve this problem, you should know one of the basic properties of limits. If both \( \lim_{x \to a} f(x) \) and \( \lim_{x \to a} g(x) \) exist and are finite, then the limit of their sum \( \lim_{x \to a} [f(x) + g(x)] \) also exists. This property is part of the limit laws in calculus.
02

Apply Limit Property

Using the limit property, we can apply the knowledge that if the limits of \( f(x) \) and \( g(x) \) as \( x \to a \) exist, then the limit of \( f(x) + g(x) \) as \( x \to a \) is simply the sum of the two limits. Mathematically, \( \lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x) \).
03

Conclusion

Given the application of the limit property, it confirms that the statement is true. The existence of \( \lim_{x \to a} f(x) \) and \( \lim_{x \to a} g(x) \) guarantees the existence of \( \lim_{x \to a} [f(x) + g(x)] \) due to the same limit laws.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Laws
Limit laws are fundamental in calculus, playing a crucial role in calculating the behavior of functions as they approach a particular point or infinity. One of the key limit laws states that if the limits of individual functions exist at a point, then their combination through addition, subtraction, multiplication, or division (provided the limit of the divisor is not zero) will also have limits that can be computed through straightforward arithmetic operations.
Understanding these laws allows mathematicians and students alike to break down complex expressions into simpler parts, solving them with ease.
  • For the sum: \( \lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x) \)
  • For the difference: \( \lim_{x \to a} [f(x) - g(x)] = \lim_{x \to a} f(x) - \lim_{x \to a} g(x) \)
  • For the product: \( \lim_{x \to a} [f(x) \cdot g(x)] = \lim_{x \to a} f(x) \cdot \lim_{x \to a} g(x) \)
  • For the quotient: \( \lim_{x \to a} \frac{f(x)}{g(x)} = \frac{\lim_{x \to a} f(x)}{\lim_{x \to a} g(x)} \), provided \( \lim_{x \to a} g(x) eq 0 \)
These laws make analyzing limits powerful, providing clarity and a path to solving even the most challenging calculus problems.
Sum of Functions Limits
When working with limits involving the sum of two functions, the process is relatively simple, thanks to the sum property of limits. If two individual limits of functions as \( x \) approaches a point exist, the limit of their sum can also be easily determined. This is crucial in calculus, where functions are often combined.
This property allows the separation of more complex expressions into simpler components, each approachable through its limit.
Imagine two functions, \( f(x) \) and \( g(x) \), both tending towards a limit as \( x \) approaches 'a'. According to the sum rule, the overall limit when adding these functions is the simple sum of their two individual limits. This holds true for all points where the original individual limits are defined and finite.
  • Applicable when both individual limits are finite and defined.
  • Ensures algebraic simplicity, allowing focused calculation on separate parts of a function.
This insight greatly simplifies tackling problems in calculus dealing with multiple functions.
Continuity and Limits
Continuity in a function means there's no interruption, gap, or jump in the function's value at a given point. Limit concepts are tightly woven with understanding continuity. A function \( f(x) \) is continuous at a point \( x = a \) if the following conditions hold:
  • \( f(a) \) is defined.
  • \( \lim_{x \to a} f(x) \) exists.
  • \( \lim_{x \to a} f(x) = f(a) \)
When these three criteria are met, the function behaves smoothly at that point, enhancing the overall comprehension of curves and graphs. Understanding where limits exist helps identify and describe where continuity appears in functions.
Continuity is critical in calculus as it defines how a function behaves between intervals, ensuring predictable results when applying further calculus operations, like differentiation and integration. Recognizing where a function is continuous allows you to apply limit laws reliably and is foundational to more advanced concepts such as derivatives and integrals.

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Most popular questions from this chapter

(a) Find the largest open interval, centered at the origin on the \(x\) -axis, such that for each \(x\) in the interval, other than the center, the values of \(f(x)=1 / x^{2}\) are greater than 100 . (b) Find the largest open interval, centered at \(x=1\), such that for each \(x\) in the interval, other than the center, the values of the function \(f(x)=1 /|x-1|\) are greater than 1000 . (c) Find the largest open interval, centered at \(x=3\), such that for each \(x\) in the interval, other than the center, the values of the function \(f(x)=-1 /(x-3)^{2}\) are less than \(-1000\). (d) Find the largest open interval, centered at the origin on the \(x\) -axis, such that for each \(x\) in the interval, other than the center, the values of \(f(x)=-1 / x^{4}\) are less than \(-10,000\).

A function \(f\) is said to have a removable discontinuity at \(x=c\) if \(\lim _{x \rightarrow c} f(x)\) exists but \(f\) is not continuous at \(x=c\), either because \(f\) is not defined at \(c\) or because the definition for \(f(c)\) differs from the value of the limit. This terminology will be needed in these exercises. (a) Sketch the graph of a function with a removable discontinuity at \(x=c\) for which \(f(c)\) is undefined. (b) Sketch the graph of a function with a removable discontinuity at \(x=c\) for which \(f(c)\) is defined.

Suppose that the speed \(v\) (in \(\mathrm{ft} / \mathrm{s})\) of a skydiver \(t\) seconds after leaping from a plane is given by the equation \(v=190\left(1-e^{-0.168 t}\right)\) (a) Graph \(v\) versus \(t\). (b) By evaluating an appropriate limit, show that the grapl of \(v\) versus \(t\) has a horizontal asymptote \(v=c\) for an appropriate constant \(c\). (c) What is the physical significance of the constant \(c\) in part (b)?

Evaluate the limit using an appropriate substitution. $$ \lim _{x \rightarrow+\infty}\left[\ln \left(x^{2}-1\right)-\ln (x+1)\right][\text { Hint }: t=x-1] $$

Suppose that \(f\) and \(g\) are two functions such that both \(\lim _{x \rightarrow a} f(x)\) and \(\lim _{x \rightarrow a}[f(x)+g(x)]\) exist. Use Theo- rem \(1.2 .2\) to prove that \(\lim _{x \rightarrow a} g(x)\) exists.

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