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The function \(\cot ^{-1} x\) is defined to be the inverse of the restricted cotangent function $$ \cot x, \quad 00 \\ \pi+\tan ^{-1}(1 / x), & \text { if } x<0\end{array}\right.\) (b) \(\sec ^{-1} x=\cos ^{-1} \frac{1}{x}, \quad\) if \(|x| \geq 1\) (c) \(\csc ^{-1} x=\sin ^{-1} \frac{1}{x}, \quad\) if \(|x| \geq 1\).

Short Answer

Expert verified
(a) Use \(\tan^{-1}(1/x)\) for \(\cot^{-1} x\). (b) Use \(\cos^{-1}(1/x)\) for \(\sec^{-1} x\). (c) Use \(\sin^{-1}(1/x)\) for \(\csc^{-1} x\).

Step by step solution

01

Understanding Inverse Trigonometric Functions

The inverse trigonometric functions are used to find angles if given a trigonometric ratio. The inverse function \(\cot^{-1} x\) is the inverse of \(\cot x\) restricted to \(0 < x < \pi\). Similarly, \(\csc^{-1} x\) is the inverse of \(\csc x\) restricted to \(-\pi / 2 < x < \pi / 2, x eq 0\). Let's explore how these functions relate to their other trigonometric and inverse functions.
02

Proving (a) for \(\cot^{-1} x\)

To show \(\cot^{-1} x = \tan^{-1}(1/x)\) for \(x > 0\), consider that the cotangent function's inverse, \(y = \cot^{-1} x\), implies \(x = \cot y\). For \(x > 0\), this is equivalent to stating that \(\tan y = 1/x\), which means \(y = \tan^{-1}(1/x)\). When \(x < 0\), applying the range restrictions and periodicity of \(\cot y\), we see that \(y = \pi + \tan^{-1}(1/x)\) aligns with the range requirement \(0 < y < \pi\).
03

Proving (b) for \(\sec^{-1} x\)

The inverse \(\sec^{-1} x\) implies \(y = \sec^{-1} x\), and thus \(x = \sec y\). The identity \(\sec y = 1/\cos y\) leads to \(x = 1/\cos y\). Solving for \(\cos y\) gives \(\cos y = 1/x\), which implies \(y = \cos^{-1}(1/x)\) for \(|x| \geq 1\). This expression satisfies the range for \(\sec y\).
04

Proving (c) for \(\csc^{-1} x\)

For \(\csc^{-1} x\), the inverse implies \(y = \csc^{-1} x\), or \(x = \csc y\). Using the identity \(\csc y = 1/\sin y\), we have \(x = 1/\sin y\), thus, \(\sin y = 1/x\). Therefore, \(y = \sin^{-1}(1/x)\) if \(|x| \geq 1\), satisfying the range \(-\pi/2 < y < \pi/2, y eq 0\).
05

Conclusion

Each function's inverse can be rewritten using an equivalent trigonometric identity involving a reciprocal function. Specifically, these stepwise transformations confirm the identities provided in parts (a), (b), and (c), adhering to the constraints of the restricted ranges of these functions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cotangent
The cotangent function, denoted as \( \cot x \), is the reciprocal of the tangent function and is defined as \( \cot x = \frac{1}{\tan x} \). It is an important function in trigonometry, primarily utilized in problems involving right-angled triangles and periodic functions.
Understanding the inverse, \( \cot^{-1} x \), allows us to find an angle given the cotangent ratio. The range of \( \cot^{-1} x \) is restricted to the interval \( 0 < x < \pi \), ensuring it provides unique angle solutions.

To express \( \cot^{-1} x \) in terms of \( \tan^{-1} \), we use the relationship between cotangent and tangent. Here's how it works:
  • When \( x > 0 \), we have \( \cot^{-1} x = \tan^{-1} (1/x) \). This is because \( \cot \) being a reciprocal function translates the problem into an inverse tangent by taking \( 1/x \).
  • For \( x < 0 \), periodicity changes the scenario, and the expression becomes \( \cot^{-1} x = \pi + \tan^{-1} (1/x) \). This adjustment accounts for the angle's position within the interval \( 0 < x < \pi \).
By understanding these properties, you can solve inverse cotangent problems with confidence.
Cosecant
The cosecant function, represented as \( \csc x \), is the reciprocal of the sine function, defined by \( \csc x = \frac{1}{\sin x} \). It is particularly useful in trigonometric problems involving reciprocals and identities.
The inverse function, \( \csc^{-1} x \), helps determine angles from the cosecant value. Its range is constrained between \(-\pi/2 < x < \pi/2, x eq 0\) to provide a unique solution.

For the expression \( \csc^{-1} x = \sin^{-1} \left(\frac{1}{x}\right) \) when \(|x| \geq 1\), here's a simple breakdown:
  • The relationship \( \csc x = \frac{1}{\sin x} \) allows us to solve for \( \sin x \) in terms of \( \frac{1}{x} \).
  • This means \( \sin y = 1/x \), leading to \( \csc^{-1} x = \sin^{-1} (1/x) \).
The interval of \( \csc^{-1} x \) ensures that the angle remains within the accepted range, providing accurate inverse trigonometric solutions.
Secant
The secant function, denoted \( \sec x \), is another reciprocal function related to cosine, defined by \( \sec x = \frac{1}{\cos x} \). This function appears frequently in problems relating to angular measurement and trigonometric identities.
When dealing with its inverse, \( \sec^{-1} x \), we find the angle corresponding to a given secant value. The range for this is defined by the condition \( |x| \geq 1 \) to maintain unique and valid solutions.

By using the expression \( \sec^{-1} x = \cos^{-1} \left( \frac{1}{x} \right) \), here’s how we approach it:
  • The identity \( \sec y = \frac{1}{\cos y} \) directly implies \( x = \frac{1}{\cos y} \).
  • Therefore, solving for \( \cos y \) gives us \( \cos y = 1/x \), which is expressed in inverse terms as \( \sec^{-1} x = \cos^{-1} (1/x) \).
This setup maintains the true values within the domain and range required for correct inverse results.

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