/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Find the limit of the following ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the limit of the following sequences or determine that the limit does not exist. $$\left\\{\frac{n^{3}}{n^{4}+1}\right\\}$$

Short Answer

Expert verified
Answer: The limit of the given sequence as n approaches infinity is 0.

Step by step solution

01

The numerator has a power of n^3, while the denominator has a power of n^4. The highest power in this sequence is n^4. #Step 2: Divide the numerator and the denominator by the highest power of n#

Divide both the numerator and the denominator by n^4 to simplify the expression and make the limit easier to determine: $$\frac{n^3}{n^4 + 1} = \frac{n^3/n^4}{(n^4 + 1)/n^4}$$ #Step 3: Simplify the expression#
02

Simplify the expression by canceling out the powers of n: $$\frac{n^3/n^4}{(n^4 + 1)/n^4} = \frac{1/n}{(1 + 1/n^4)}$$ #Step 4: Find the limit as n approaches infinity#

As n approaches infinity, both 1/n and 1/n^4 will approach 0: $$\lim_{n\to\infty}\frac{1/n}{(1 + 1/n^4)} = \frac{0}{(1+0)} = 0$$ The limit of the given sequence as n approaches infinity is 0.

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